Gausses Law and Electric Potential - ch 23-25

studied byStudied by 0 people
0.0(0)
learn
LearnA personalized and smart learning plan
exam
Practice TestTake a test on your terms and definitions
spaced repetition
Spaced RepetitionScientifically backed study method
heart puzzle
Matching GameHow quick can you match all your cards?
flashcards
FlashcardsStudy terms and definitions

1 / 57

encourage image

There's no tags or description

Looks like no one added any tags here yet for you.

58 Terms

1

electric flux through the surface

amount of electric field that pierces the surface

New cards
2

area vector for a patch element on a surface (dA)

a vector that is perpendicular to the element and has a magnitude equal to the area dA of the element

New cards
3

how to calculate electric flux through a patch element

** dot product!

<p>** dot product!</p>
New cards
4

total flux through surface

knowt flashcard image
New cards
5

net flux through a closed surface

knowt flashcard image
New cards
6

Gauss’s Law

Gauss’s Law states that the total electric flux through a closed surface is proportional to the total charge enclosed by the surface divided by the permittivity of free space.

New cards
7

piercing direction

inward: negative flux

outward: positive flux

skimming field: zero flux

New cards
8

how to find the piercing direction

  • draw the area vector that is perpendicular to a patch pointing outward from the surface

  • look at the field vector if it pierces outward/inward

  • if dot product = +, flux is also positive (vv)

New cards
9

Gauss’s Law (net flux penetrating a closed surface to the net charge enclose by surface)

knowt flashcard image
New cards
10

Gauss’s Law in terms of electric field piercing though the surface

substitute the definition of flux

<p>substitute the definition of flux </p><p></p>
New cards
11

where are excess charge on an isolated conductor located?

entirely on the outer surface of the conductor

New cards
12

internal electric field of a charge isolated conductor is

zero

New cards
13

external field is

perpendicular to the surface

has a magnitude that depends on the surface charge density o

<p>perpendicular to the surface </p><p>has a magnitude that depends on the surface charge density o</p><p></p>
New cards
14

electric field at a point near an infinite line of charge with uniform linear charge denisty is

perpendicular to the line

has magnitude where r is the perpendicular distance from the line to the point

<p>perpendicular to the line</p><p>has magnitude where r is the perpendicular distance from the line to the point </p><p></p>
New cards
15

electric field due to an infinite non conducting sheet with uniform surface charge density

perpendicular to plane of the sheet

has magnitude of

<p>perpendicular to plane of the sheet </p><p>has magnitude of </p>
New cards
16

external electric field just outside the surface of an isolated charged conductor with surface charge density o

perpendicular to the surface and has magnitude

<p>perpendicular to the surface and has magnitude </p>
New cards
17

outside a spherical shell of uniform charge q, the electric field due to the shell is

radical (inward or outward depending on the sign of the charge)

r is the distance to the point of measurement from the center of the shell

<p>radical (inward or outward depending on the sign of the charge) </p><p>r is the distance to the point of measurement from the center of the shell </p><p></p>
New cards
18

inside the shell, the field due to the shell is

zero

New cards
19

inside the shphere with a uniform volume charge density, field is

radical

has magnitude of

R = radius of sphere

r = radial distance from the center of the sphere

<p>radical </p><p>has magnitude of </p><p>R = radius of sphere</p><p>r = radial distance from the center of the sphere </p>
New cards
20

electric potential energy at a point P in the electric field of a charged object

W(inf) = work that would be done by the electric foce on a positive test charge were it brought from an infinite distance to P

U = electric potential energy stored in

<p>W(inf) = work that would be done by the electric foce on a positive test charge were it brought from an infinite distance to P</p><p>U = electric potential energy stored in </p><p></p>
New cards
21

if a particle with charge q is placed at a point where the electric potential of a charged object is V, the electric potential energy of the particle object system is

knowt flashcard image
New cards
22

if the particle moves through a potential difference V, the chage in the electric PE is

knowt flashcard image
New cards
23

if a particle moves through a chage V in electric potential without an applied force acting on it, applying the conservation of mechanical energy gives the change in kinetic energy as

knowt flashcard image
New cards
24

if an applied foce acts on the particle doing work W(app), the change in kinetic energy is

knowt flashcard image
New cards
25

when K = 0, work of an applied force involves only the motion of the particle though a potential difference

knowt flashcard image
New cards
26

equipotential surface

adjacent points that have the same electric potential energy

New cards
27

electric potential difference betwen two points i and f is

knowt flashcard image
New cards
28

in a uniform field of magnitude E, the chage in potential from a higher equipotential surface to a lower one, spearated by distance x is

knowt flashcard image
New cards
29

electric potential due to a single charged particle at a distance r from that charged particle is

V has the same sign as q

<p>V has the same sign as q</p>
New cards
30

potential due to a collection of charged particles is

knowt flashcard image
New cards
31

electric potential of the dipole is

at a distance r from an electric dipole with dipole moment magnitude p = qd

angle lies betwen the dipole moment vector and a line extending from the dipole midpoint to the point of measurement

<p>at a distance r from an electric dipole with dipole moment magnitude p = qd</p><p>angle lies betwen the dipole moment vector and a line extending from the dipole midpoint to the point of measurement</p>
New cards
32

for a continuous distribution of charge over an extended object, potential energy can be found by

dividing the distribution into charge element dq that can be treated as particles

summing the potential due to each element by integrating over the full distribution

dq is replaced with the product of either a linear charge density and length element or a surface charge density o and area element

<p>dividing the distribution into charge element dq that can be treated as particles </p><p>summing the potential due to each element by integrating over the full distribution</p><p>dq is replaced with the product of either a linear charge density and length element or a surface charge density o and area element </p>
New cards
33

component of electric field potential is

negative of the rate at which potential changes with distance in that direction

<p>negative of the rate at which potential changes with distance in that direction </p>
New cards
34

the x, y, z component may be found from

knowt flashcard image
New cards
35

when E is uniform, it becomes

knowt flashcard image
New cards
36

electric field is zero parallel to

equipotential surface

New cards
37

two particle at separation r, electric potential of a system of charged particles is

equal to work needed to assemble the system

<p>equal to work needed to assemble the system </p>
New cards
38

where is an excess charge placed on a conductor will, in the equilibrium state?

located entirely on the outer surface of the conductor

New cards
39

potential of the entire conductor, including the interior points?

uniform potential

New cards
40

if an isolated conductor is placed in an external field

then the electric field due to the conduction electrons cancels the external electric field that otherwise would have been there

New cards
41

net electric field at every point on the surface is ____ to the surface

perpendicular

New cards
42

capacitors

tow isolated plates with charges +q and -q

V is the potential difference between the plates

q = CV

New cards
43

when a circuit with a battery, an open switch, and an uncharged capacitor is completed by closing the switch

conduction electrons shift, leaving the capacitor plates with opposite charge

New cards
44

parallel- plate capacitors

<p></p>
New cards
45

cylindrical capacitors

b = capacitance

a = radii

L = length

<p>b = capacitance</p><p>a = radii</p><p>L = length</p>
New cards
46

sphereical capacitors with conentric plates

knowt flashcard image
New cards
47

isolated sphere of radius R

knowt flashcard image
New cards
48

capacitors in parallel

Ceq = C1 + C2 + C3

New cards
49

capacitors in parallel

1/ Ceq = 1/C1 + 1/C2…

New cards
50

electric potential energy U of a charge capacitor

equal to the work requried to charge the capacitor.

<p>equal to the work requried to charge the capacitor.</p>
New cards
51

in a vacuum, the energy density u in a field of magnitude E is

knowt flashcard image
New cards
52

if the space between the plates of a capacitor is completely filled with a dielectric material, the capacitance C in the vacuum is

multiplied by the material’s dielectric constant K

New cards
53

in a region that is completely filled by a dielectric

all equation s containing E0 must be modified by KE0

New cards
54

when a dielectric material is placed in an external electric field

it develops an internal electric field that is oriented opposite the external fieldm thus reducing the magnitude of the electric field inside the material

New cards
55

when a dielectric material is placed in a capacitor with a fixed amount of charge on the surface

the net electric field betwen the plates decreased

New cards
56

when a dielectric is present Gauss’s law may become

q = free charge

<p>q = free charge </p>
New cards
57

induced charge is ____ the free charge on the plates

less than

New cards
58

inserting a dilectric into a capacitor causes

induced charge to appear on the face of the dielectric and weakens the electric field between the plates

New cards

Explore top notes

note Note
studied byStudied by 98 people
693 days ago
5.0(4)
note Note
studied byStudied by 241 people
678 days ago
5.0(2)
note Note
studied byStudied by 13 people
833 days ago
5.0(1)
note Note
studied byStudied by 52 people
787 days ago
5.0(1)
note Note
studied byStudied by 33 people
425 days ago
5.0(1)
note Note
studied byStudied by 9 people
169 days ago
5.0(2)
note Note
studied byStudied by 41 people
709 days ago
5.0(1)
note Note
studied byStudied by 100 people
760 days ago
5.0(2)

Explore top flashcards

flashcards Flashcard (112)
studied byStudied by 55 people
302 days ago
5.0(2)
flashcards Flashcard (198)
studied byStudied by 1 person
182 days ago
5.0(1)
flashcards Flashcard (24)
studied byStudied by 34 people
759 days ago
5.0(1)
flashcards Flashcard (47)
studied byStudied by 1 person
39 days ago
5.0(1)
flashcards Flashcard (137)
studied byStudied by 301 people
567 days ago
4.5(4)
flashcards Flashcard (308)
studied byStudied by 7 people
832 days ago
5.0(1)
flashcards Flashcard (35)
studied byStudied by 2 people
303 days ago
5.0(1)
flashcards Flashcard (334)
studied byStudied by 88 people
23 days ago
5.0(2)
robot