Chapter 9: Chemical Equilibrium
Dynamic equilibrium is when chemicals are reacting on a molecular scale but do not change in concentration
When a reaction begins, the reactants decrease and the products increase. When equilibrium is reached, the reaction does not stop occurring, but the concentrations of products and reactants remain the same.
Chemical equilibrium concepts are used to describe the compounds
The equilibrium concentrations are dependent on the initial concentration of the reactants. Different initial concentrations cause different equilibrium concentrations
Equilibrium expression is always followed no matter the initial concentration.
When you multiply the product concentrations and divide that value by all of the reactant concentrations multiplied together, you will obtain the equilibrium constant, K.
Equilibrium constant depends on the specific reaction and temperature when equilibrium is reached
K is the equilibrium constant symbol and can be specified with different subscripts
Kc is equilibrium constant when concentration is in Molarity
Kp is when partial pressure of gasses represents reactant and product
Ksp is solubility product
Ka is acid ionization constant
Kb is base ionization constant
If a reaction is written as aA + bB ⇄ pP + nN, then the equilibrium expression could be
Equilibrium constant is written from the balance reaction
To reverse direction of reaction, the reactant and products can be flipped.
Coefficients can be multiplied or divided by constant factors
Equations can be added or subtracted
To find K, simply measure the concentrations of products and reactants and use equilibrium expression
For O2 + 2SO2 ⇄ 2SO3 where the equilibrium concentration are [O2] = 2x10^-8 M, [SO2] = 3.4x10^-9 M, and [SO3] = .971 M
If the equilibrium constant is very large, more products are present and favored at equilibrium.
Very large is seen as greater than 10^10
If a lot of product is formed, the reaction has gone nearly to completion
If the constant is very small, more reactants are present and favored at equilibrium.
Very small is seen as less than 10^-10
If very little product has occurred, then virtually no reaction has occurred
If K = 1, the equilibrium mixture has equal products and reactants
Thermodynamically favorable reaction (TFP) has products form with very little assistance
TFP is seen as constant greater than 1
A reaction is seen as a thermodynamically unfavorable reaction, not TFP, when the equilibrium constant is less than 1.
Reaction quotient, Q, is obtained by using the equilibrium expression and using the values of product and reactant at any point in time, not just at equilibrium.
This is different from K because K can only be obtained at equilibrium.
Principles of Q
If Q does not change with time, the reaction is in a state of equilibrium. Q = K
Q = K is the reaction is at equilibrium
Q < K if the reaction will move forward (produce more products) to reach equilibrium
Q > K if the reaction will move in the reverse (produce more reactants) to reach equilibrium
Equilibrium table is used to organize given information in an problem to find the missing values
Comprised of five lines: the balance reaction, initial concentrations, how much the initials change, the equilibrium values, and the answer
For the reaction NO2 + SO2 ⇄ NO + SO3
Reaction | NO2 | + | SO2 | ⇄ | NO | + | SO3 |
---|---|---|---|---|---|---|---|
Inital [ ] | |||||||
Change | |||||||
Eqlbrm | |||||||
Answer |
The change line will be represented by x and the coefficient of x correlates to the coefficient of the line it is in. In this table, x will have a coefficient of 1. However, if NO2 was 2 NO2, the x would be 2x.
If a 4 L flask was comprised of 1 mole of each compound, then it would look like this (1 mol / 4 L = .250 M)
Reaction | NO2 | + | SO2 | ⇄ | NO | + | SO3 |
---|---|---|---|---|---|---|---|
Inital [ ] | .250M | .250M | .250M | .250M | |||
Change | -x | -x | +x | +x | |||
Eqlbrm | .250 -x | .250 -x | .250+x | .250 +x | |||
Answer |
Using the previous table, if it is then given that the equilibrium concentration of NO2 is .261M.
If .250 - x = .261M, then x = -.011M
Reaction | NO2 | + | SO2 | ⇄ | NO | + | SO3 |
---|---|---|---|---|---|---|---|
Inital [ ] | .250M | .250M | .250M | .250M | |||
Change | -x | -x | +x | +x | |||
Eqlbrm | .250 -x | .250 -x | .250+x | .250 +x | |||
Answer | .261M | .261M | .239M | .239M |
Plugging the answer values to the equilibrium expression:
At equilibrium, the chemical reaction obeys the equilibrium expression and the expression can be used to calculate the concentrations
For the reaction H2 + I2 ⇄ 2 HI, where K = 49, [I2] = .2M, [HI] = .05M, [H2] can be calculated:
If given initial concentrations and equilibrium constant, equilibrium concentrations can be determined for all compounds
For Br2 + Cl2 ⇄ 2BrCl, K = 6.9. If .1 mol BrCl is in a 500mL flask, find [Br2], [Cl2], and [BrCl].
.1 mol BrCl / .5L = .2M
Rxn | Br2 | + | Cl2 | ⇄ | 2BrCl |
---|---|---|---|---|---|
Initial [ ] | 0M | 0M | .2M | ||
Change | -x | -x | +2x | ||
Eqlbrm | -x | -x | .2M - 2x | ||
Answer |
Given the x value found, [Br2] and [Cl2] = .0432 and [BrCl] = .114M
For the reaction H2 + I2 ⇄ 2HI, the Kp expression is
For the reaction 2S + 3O2 ⇄ 2SO3 where the partial pressure are S = .0035atm, O2 = .0021atm, and SO3 = .005atm, what’s the Kp?
Kp = Kc(RT)^(Δng)
R = .0821
Δng = change in moles of gas (products - reactants)
For the reaction 2NO (g) + O2 (g) ⇄ 2 NO2 (g) where the Kc is 5.6x10^12 at 290K, what’s the Kp?
There are no units because they are seen as dimensionless quantities
Solubility product can be used to find how much of an salt dissolves in water
For the reaction Fe(OH)3 (s) ⇄ Fe (aq) + 3OH (aq), Ksp = [Fe][OH]
Fe(OH)3 does not appear because it is solid.
The column for Fe(OH)3 will not be used because it has no concentration
If the Ksp is 1.6x10^-39, the concentrations can be found
+ |
---|
Using this X value, [Fe] = 8.8x10^-11 and [OH] = 2.6x10^-10 M
Weak acids and weak bases ionize only slightly in water
For the reaction CH3COOH (aq) + H2O ⇄ CH3COO (aq) + H3O (aq)
For the reaction NH3 (aq) + H2O ⇄ NH4 (aq) + OH
For weak acids, the equilibrium constant is called the acid ionization constant and given the symbol Ka
Weak bases have the base ionization constant, Kb
Metal ions can react with anions and molecules to form complexes
For the reaction Cu (aq) + 4NH3 (aq) ⇄ Cu(NH3)4 (aq)
Kf, the formation constant, is used to represent the complex
When the reaction is reversed, it is the dissociation constant, Kd and are inversely proportional to each other
If a reaction is in equilibrium and it is disturbed, a stressor is added, the reaction will react again to return to equilibrium.
If the reactant is increased, more product will become favored/produced to restore equilibrium
If reactant decreases, the opposite occurs: more reactant is produced/favored
If products are increased, more reactants are favored/produced
If products are decreased, the opposite occurs
If more pressure is added to a reaction, the reaction will shift to produce more of the side with less moles of gas
If the reactants have 2 mols of gas and products have 3, the reaction will produce more reactants
If pressure is decreased, the reaction will shift to the side with more mols of gas
If the reactants have 2 mol and the products have 3, the reaction will create more products
If there are equal amounts of gas on each side of the reaction, no shifts will occur
Changing temperature is the only stressor that can change the value of the equilibrium constant
If a reaction is exothermic, where reactants ⇄ products + heat
If the temperature is increased more reactants will be produced, and the K will decrease
If the temperature is decreased, more products will be formed and K will increase
If a reaction is endothermic, where reactants + heat ⇄ products
If the temperature is increased, more products will be made and K will increase
If the temperature is decreased, more reactants will form and K will decrease
Dynamic equilibrium is when chemicals are reacting on a molecular scale but do not change in concentration
When a reaction begins, the reactants decrease and the products increase. When equilibrium is reached, the reaction does not stop occurring, but the concentrations of products and reactants remain the same.
Chemical equilibrium concepts are used to describe the compounds
The equilibrium concentrations are dependent on the initial concentration of the reactants. Different initial concentrations cause different equilibrium concentrations
Equilibrium expression is always followed no matter the initial concentration.
When you multiply the product concentrations and divide that value by all of the reactant concentrations multiplied together, you will obtain the equilibrium constant, K.
Equilibrium constant depends on the specific reaction and temperature when equilibrium is reached
K is the equilibrium constant symbol and can be specified with different subscripts
Kc is equilibrium constant when concentration is in Molarity
Kp is when partial pressure of gasses represents reactant and product
Ksp is solubility product
Ka is acid ionization constant
Kb is base ionization constant
If a reaction is written as aA + bB ⇄ pP + nN, then the equilibrium expression could be
Equilibrium constant is written from the balance reaction
To reverse direction of reaction, the reactant and products can be flipped.
Coefficients can be multiplied or divided by constant factors
Equations can be added or subtracted
To find K, simply measure the concentrations of products and reactants and use equilibrium expression
For O2 + 2SO2 ⇄ 2SO3 where the equilibrium concentration are [O2] = 2x10^-8 M, [SO2] = 3.4x10^-9 M, and [SO3] = .971 M
If the equilibrium constant is very large, more products are present and favored at equilibrium.
Very large is seen as greater than 10^10
If a lot of product is formed, the reaction has gone nearly to completion
If the constant is very small, more reactants are present and favored at equilibrium.
Very small is seen as less than 10^-10
If very little product has occurred, then virtually no reaction has occurred
If K = 1, the equilibrium mixture has equal products and reactants
Thermodynamically favorable reaction (TFP) has products form with very little assistance
TFP is seen as constant greater than 1
A reaction is seen as a thermodynamically unfavorable reaction, not TFP, when the equilibrium constant is less than 1.
Reaction quotient, Q, is obtained by using the equilibrium expression and using the values of product and reactant at any point in time, not just at equilibrium.
This is different from K because K can only be obtained at equilibrium.
Principles of Q
If Q does not change with time, the reaction is in a state of equilibrium. Q = K
Q = K is the reaction is at equilibrium
Q < K if the reaction will move forward (produce more products) to reach equilibrium
Q > K if the reaction will move in the reverse (produce more reactants) to reach equilibrium
Equilibrium table is used to organize given information in an problem to find the missing values
Comprised of five lines: the balance reaction, initial concentrations, how much the initials change, the equilibrium values, and the answer
For the reaction NO2 + SO2 ⇄ NO + SO3
Reaction | NO2 | + | SO2 | ⇄ | NO | + | SO3 |
---|---|---|---|---|---|---|---|
Inital [ ] | |||||||
Change | |||||||
Eqlbrm | |||||||
Answer |
The change line will be represented by x and the coefficient of x correlates to the coefficient of the line it is in. In this table, x will have a coefficient of 1. However, if NO2 was 2 NO2, the x would be 2x.
If a 4 L flask was comprised of 1 mole of each compound, then it would look like this (1 mol / 4 L = .250 M)
Reaction | NO2 | + | SO2 | ⇄ | NO | + | SO3 |
---|---|---|---|---|---|---|---|
Inital [ ] | .250M | .250M | .250M | .250M | |||
Change | -x | -x | +x | +x | |||
Eqlbrm | .250 -x | .250 -x | .250+x | .250 +x | |||
Answer |
Using the previous table, if it is then given that the equilibrium concentration of NO2 is .261M.
If .250 - x = .261M, then x = -.011M
Reaction | NO2 | + | SO2 | ⇄ | NO | + | SO3 |
---|---|---|---|---|---|---|---|
Inital [ ] | .250M | .250M | .250M | .250M | |||
Change | -x | -x | +x | +x | |||
Eqlbrm | .250 -x | .250 -x | .250+x | .250 +x | |||
Answer | .261M | .261M | .239M | .239M |
Plugging the answer values to the equilibrium expression:
At equilibrium, the chemical reaction obeys the equilibrium expression and the expression can be used to calculate the concentrations
For the reaction H2 + I2 ⇄ 2 HI, where K = 49, [I2] = .2M, [HI] = .05M, [H2] can be calculated:
If given initial concentrations and equilibrium constant, equilibrium concentrations can be determined for all compounds
For Br2 + Cl2 ⇄ 2BrCl, K = 6.9. If .1 mol BrCl is in a 500mL flask, find [Br2], [Cl2], and [BrCl].
.1 mol BrCl / .5L = .2M
Rxn | Br2 | + | Cl2 | ⇄ | 2BrCl |
---|---|---|---|---|---|
Initial [ ] | 0M | 0M | .2M | ||
Change | -x | -x | +2x | ||
Eqlbrm | -x | -x | .2M - 2x | ||
Answer |
Given the x value found, [Br2] and [Cl2] = .0432 and [BrCl] = .114M
For the reaction H2 + I2 ⇄ 2HI, the Kp expression is
For the reaction 2S + 3O2 ⇄ 2SO3 where the partial pressure are S = .0035atm, O2 = .0021atm, and SO3 = .005atm, what’s the Kp?
Kp = Kc(RT)^(Δng)
R = .0821
Δng = change in moles of gas (products - reactants)
For the reaction 2NO (g) + O2 (g) ⇄ 2 NO2 (g) where the Kc is 5.6x10^12 at 290K, what’s the Kp?
There are no units because they are seen as dimensionless quantities
Solubility product can be used to find how much of an salt dissolves in water
For the reaction Fe(OH)3 (s) ⇄ Fe (aq) + 3OH (aq), Ksp = [Fe][OH]
Fe(OH)3 does not appear because it is solid.
The column for Fe(OH)3 will not be used because it has no concentration
If the Ksp is 1.6x10^-39, the concentrations can be found
+ |
---|
Using this X value, [Fe] = 8.8x10^-11 and [OH] = 2.6x10^-10 M
Weak acids and weak bases ionize only slightly in water
For the reaction CH3COOH (aq) + H2O ⇄ CH3COO (aq) + H3O (aq)
For the reaction NH3 (aq) + H2O ⇄ NH4 (aq) + OH
For weak acids, the equilibrium constant is called the acid ionization constant and given the symbol Ka
Weak bases have the base ionization constant, Kb
Metal ions can react with anions and molecules to form complexes
For the reaction Cu (aq) + 4NH3 (aq) ⇄ Cu(NH3)4 (aq)
Kf, the formation constant, is used to represent the complex
When the reaction is reversed, it is the dissociation constant, Kd and are inversely proportional to each other
If a reaction is in equilibrium and it is disturbed, a stressor is added, the reaction will react again to return to equilibrium.
If the reactant is increased, more product will become favored/produced to restore equilibrium
If reactant decreases, the opposite occurs: more reactant is produced/favored
If products are increased, more reactants are favored/produced
If products are decreased, the opposite occurs
If more pressure is added to a reaction, the reaction will shift to produce more of the side with less moles of gas
If the reactants have 2 mols of gas and products have 3, the reaction will produce more reactants
If pressure is decreased, the reaction will shift to the side with more mols of gas
If the reactants have 2 mol and the products have 3, the reaction will create more products
If there are equal amounts of gas on each side of the reaction, no shifts will occur
Changing temperature is the only stressor that can change the value of the equilibrium constant
If a reaction is exothermic, where reactants ⇄ products + heat
If the temperature is increased more reactants will be produced, and the K will decrease
If the temperature is decreased, more products will be formed and K will increase
If a reaction is endothermic, where reactants + heat ⇄ products
If the temperature is increased, more products will be made and K will increase
If the temperature is decreased, more reactants will form and K will decrease