1/27
Looks like no tags are added yet.
Name | Mastery | Learn | Test | Matching | Spaced |
---|
No study sessions yet.
Field sketching - what to include
location name
labelled points of interest
estimated height
EIA - environmental impact assessment
looks at environmental, economic and social factors before development is done
+3 (positive impact) to -3 (negative impact)
doesn’t take into account importance of each factor - all even
flow line maps
show movement of people or goods
width represents number (wider=more)
arrowheads indicate direction
mean
add all numbers - divide by how many
exclude anomalies
mode
most common number in a data set
median
middle value when all points are ranked
if there is an even number of the results = add middle 2 and divide by 2
range
span of data within which all numbers lie
dispersion
how data is dispersed within a range
interquartile range
shows the middle 50% of data
find median
find 25% and 75% (by counting ¼ of the total number of values from the median)
find difference between upper and lower quartiles
variance
how far something varies from the average
find the mean
calculate how much difference each value is from the mean
standard deviation
shows by how much a value varies form the mean
shows data dispersion from the mean
calculate mean
calculate variance for each value
square variance values
put into formula
standard deviation formula
stand. dev = sq. root | sum of (x- mean)²/pop. size
scatter graphs
shows correlation between 2 data sets
don’t join dots
positive, negative or no correlation
life of best fits
can be drawn on a scatter graph
spearmans rank correlation
tests strength of relationship between 2 variables
gives figure between +1 (perfect correlation) 0 (no correlation) and -1(perfect negative correlation)
spearmans rank - calculation
rank values form highest to lowest
rank second data set from higher to lowest
subtract 1st rank from second
square each difference for each place
add up all differences²
spearmans rank formula
put sum of d² into formula
= 6xsum of d² / n(n²-1)
n = number of different paired values
will give a value for spearmans
spearmans rank - signficance testing
paired data sets - 1 = degrees of freedom
find confidence - 0.05
significant = equal to or greater than the critical value
insignificant = lower than critical value
Lorenz curve
shows and measures inequality in a graph form
assumes that an equal world - 10%of people have 10% of income
equality = straight line on Lorenz
more curve bends away from straight line = more inequality
Lorenz curve - how to draw
draw graph - plot equality line
calculate ratios of advantage (what each 10% of poorness owns of the countries wealth)
plot lowest ratio - poorest 10%
plot each 10% in order
join all points to form a line
gini index/coefficient
measures the inequality of wealth distribution
measures area between lorna curve and the line of equality
shown as a value btwn. 0-100
0 = equality
100 = complete inequality
coefficient is shown as 0-1
adavantages of gini index/coefficient
measures inequality - doesn’t show uniform picture of whole pop.
can compare inequalities of different kinds within a country
can see trends over time
chi squared
statistical test that measures and analyses distributions of data
establish hypothesis
decide theoretical numbers - expected values = E
record observed values = O
find difference between 2 sets = O-E
square results = O-E²
divide by expected = O-E²/E
add up these results = X²
find degrees of freedom (data-1) and critical value (0.05)
if x² is less than/equal to crit. val = ACCEPT null hypothesis
null hypothesis = there is no significant differences
index of diversity
measures diversity by counting number of species in a community and the number of plants in each species
higher figure produced = higher diversity
index of diversity - calculation
simpsons index
use formula
find N = total number of individual plants
Nx(N-1)
find n = number of individuals in each species
nx(n-1) - for each species
add up n(n-1) values
divide N(N-1) by sum of n(n-1)
t test formula - 1 sample
= mean - theoretical value/ standard deviation divided by square root of sample size
t test - hypothesis
finds the statistical difference between 2 groups
null = no significant difference between results
alternative = is a significant difference between results
t test - calculation
find mean of each sample
find difference between means
standard dev. for each sample
square standard dev.
divide standard dev.² by sample size of each group
add the 2 values
square root the number = standard error of the difference
divide the difference in the means by the standard error of the difference
find d.f. = sum of both sample sizes -2
find critical value
if t value is OVER critical value - reject null (is sig. difference)