Alkenes

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47 Terms

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What are alkenes

  • Unsaturated hydrocarbons (contain double bond)

  • There is a high electron density in the double bond

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What are polymers?

  • Large molecules formed from small identical molecules called monomers

<ul><li><p>Large molecules formed from small identical molecules called monomers </p></li></ul><p></p>
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What are addition polymers?

  • Addition polymers are formed from alkenes

  • (The monomers are alkenes)

  • Process called addition polymeriasation

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Naming addition polymers

  • Poly (Name of alkene monomer)

  • e.g. Polyethene

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Why are addition polymers unreactive?

  • Addition polymers are alkanes, despite being formed from alkenes (double bonds of the alkenes open up, connecting all the monomers to make the addition polymer)

  • Contain a large number of c-h and c-c bonds

  • These bonds are non-polar and strong, making them difficult to break

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What is the repeating unit?

  • It show the arrangement of atoms, that are repeated in the polymer chain

  • For most repeating units there is a n outside the brackets to show that the unit repeats many times in the polymer

<ul><li><p>It show the arrangement of atoms, that are repeated in the polymer chain</p></li><li><p>For most repeating units there is a n outside the brackets to show that the unit repeats many times in the polymer </p></li></ul><p></p>
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structure of a monomer from the polymer chain

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What is poly(chloroethene) or PVC used for?

  • Its a rigid polymer used to make plastic pipes

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What can flexible PVC be used for?

  • soft and is used to make flooring

  • Insulation on electrical cables

  • (Made flexible by using plasticisers)

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What is a plasticiser?

  • A small molecule that fits between polymer chains

  • Causing the chains to move further apart

  • Weakening the intermolecular forces between the chains

  • This allows the polymer chains to move over each other making the polymer flexible

<ul><li><p>A small molecule that fits between polymer chains</p></li><li><p>Causing the chains to move further apart </p></li><li><p>Weakening the intermolecular forces between the chains</p></li><li><p>This allows the polymer chains to move over each other making the polymer flexible  </p></li></ul><p></p>
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Why are addition polymers bad for the environment?

  • They are unreactive

  • So they are non-biodegradable, meaning they are not broken down by microorganisms

  • As a result addition polymers can pollute the environment for a long time

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What can we do rather than sending polymers to landfill?

  • Can be combusted to create energy

  • (But combusting polymers can release harmful chemicals)

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Another method to dispose of polymers

  • Polymer waste can be sorted into the different polymers

  • And recycled to create different products

  • This reduces the amount of wate in landfills and limits usage of crude oil

  • (As there is less of a need to produce new plastic from monomers derived from the crude oil)

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What is feedstock recycling

  • Feedstock is the raw materials used by the chemical industry

  • In feedstock recycling, waste polymers are converted back into simpler hydrocarbons

  • Which are then cracked and converted into different polymers

  • Adv=no need to sort out the different waste polymer

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General formula for alkenes

  • CnH2n

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Structure and bonds in alkanes

  • All covalent bonds in alkanes are sigma

  • Sigma bonds form when electron orbitals directly overlap

  • Sigma bonds are fully rotational

  • Alkanes have a tetrahedral structure

<ul><li><p>All covalent bonds in alkanes are sigma </p></li><li><p>Sigma bonds form when electron orbitals directly overlap</p></li><li><p>Sigma bonds are fully rotational </p></li><li><p>Alkanes have a tetrahedral structure</p></li></ul><p></p>
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Structure and bonding of alkenes

  • The double bond in alkenes consists of both pi and sigma bonds

  • Sigma bonds between c-h bonds

  • When double bond forms, one sigma bond is formed between c-c

<ul><li><p>The double bond in alkenes consists of both pi and sigma bonds </p></li><li><p>Sigma bonds between c-h bonds </p></li><li><p>When double bond forms, one sigma bond is formed between c-c </p></li></ul><p></p>
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Structure and bonding of alkenes 2

  • P orbitals overlap

  • Pi bonds (unlike sigma) cannot rotate

  • only 1 pi bond between c-c

<ul><li><p>P orbitals overlap</p></li><li><p>Pi bonds (unlike sigma) cannot rotate</p></li><li><p>only 1 pi bond between c-c</p></li></ul><p></p>
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Why cant the pi bond rotate?

  • Any rotation of the pi bond would reduce the overlap of the p orbitals

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Why are alkenes highly reactive

  • Due to the double bond

  • The bond contains 2 pairs of electrons

  • 1 pair in sigma bond and 1 pair in pi

  • The bond enthalpy of pi bond is lower than sigma

  • so less energy is required to break pi bond

  • making the electrons in the pi bond more likely to take part in a reaction

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Why do Pi bonds have a lower bond enthalpy than sigma bonds?

  • In a pi bond the orbitals overlap sideways so the bond is easier to break

  • In a sigma bond the orbitals directly overlap

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Define electrophilic addition

  • Refers to a process where an alkene reacts with an electrophile

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Define an electrophile

  • Any positive ion or molecule that is attracted to a region of high electron density

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How does a hydrogen halide react with an alkene

  • Hydrogen halide consists of a polar bond

  • The halogen is always more electronegative than the H

  • The positive hydrogen will act as an electrophile and be attracted to the high electron density in the double bond

  • The positive charge of the hydrogen atom will attract the pair of electrons in the pi bond of the alkene

  • Pair of electrons move towards the H atom

<ul><li><p>Hydrogen halide consists of a polar bond </p></li><li><p>The halogen is always more electronegative than the H </p></li><li><p>The positive hydrogen will act as an electrophile and be attracted to the high electron density in the double bond </p></li><li><p>The positive charge of the hydrogen atom will attract the pair of electrons in the pi bond of the alkene </p></li><li><p>Pair of electrons move towards the H atom </p></li></ul><p></p>
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The hydrogen atom can only form 1 covalent bond. What happens next?

  • The pair of electrons in the covalent bond between H and Br, move onto the bromine atom

<ul><li><p>The pair of electrons in the covalent bond between H and Br, move onto the bromine atom </p><p></p></li></ul><p></p>
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The products after the first stage of electrophilic addition

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What does the bromide ion do now?

  • The electron pair on the bromide ion are attracted to the positive carbon in the carbocation

<ul><li><p>The electron pair on the bromide ion are attracted to the positive carbon in the carbocation</p></li></ul><p></p>
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What is the final product of Hydrogen bromide reacting with ethene

  • Bromoethane

<ul><li><p>Bromoethane</p></li></ul><p></p>
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What happens when an asymmetric alkene reacts with a hydrogen halide?

  • You will form a 2 different products depending on where the positive carbon is in the carbocation

  • It will be a major product or a minor product

<ul><li><p>You will form a 2 different products depending on where the positive carbon is in the carbocation </p></li><li><p>It will be a major product or a minor product </p></li></ul><p></p>
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What does the stability of a carbocation depend on?

  • How many alkyl groups are bonded to the positive carbon

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What is a primary carbocation ?

  • Positive carbon is bonded to 1 alkyl group

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What is a secondary carbocation?

  • Positive carbon is bonded to 2 alkyl groups

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Why is the secondary carbocation more stable?

  • The alkyl groups are electron donating

  • This electron donation from the alkyl groups reduce the positive charge of the carbon

  • Making it less likely to react. Therefore the secondary carbocation is more stable

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What forms the major product?

  • The more stable carbocation

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Why is the mechanism for a halogen molecule reacting with an alkene different to the mechanism of a hydrogen halide reacting with an alkene?

  • Halogen molecule (e.g. Br-Br) does not contain a permanent dipole

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What happens in the first stage of the mechanism of a halogen molecule reacting with an alkene?

  • Halogen molecule (Br2) has no permanent dipole

  • But the region of high electron density in the double bond of the alkene repels the electron pair of the covalent bond in the Br molecule

  • Br2 now has an induced dipole

<ul><li><p>Halogen molecule (Br2) has no permanent dipole </p></li><li><p>But the region of high electron density in the double bond of the alkene repels the electron pair of the covalent bond in the Br molecule </p></li><li><p>Br2 now has an induced dipole </p></li></ul><p></p>
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What happens after the induced dipole is formed?

  • Pair of electrons in the pi bond of the alkene are attracted to the positive bromine (electrophile)

  • The pair of electrons in the the Br molecule move to the other bromine and covalent bond breaks

<ul><li><p>Pair of electrons in the pi bond of the alkene are attracted to the positive bromine (electrophile)</p></li><li><p>The pair of electrons in the the Br molecule move to the other bromine and covalent bond breaks </p></li></ul><p></p>
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What the final product formed after the halogen molecule reacts with the alkene

  • Electron pair on the bromide ion is attracted to the positive carbon in the carbocation

<ul><li><p>Electron pair on the bromide ion is attracted to the positive carbon in the carbocation</p></li></ul><p></p>
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What happens when you add a halogen to an asymmetric alkene?

  • You only get one product

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How do you test for an unsaturated molecule (alkene) using a halogen?

  • Use bromine water which is orange/brown

  • Add drops of bromine water into the substance being tested

  • Shake the test tube

  • If the substance is unsaturated the bromine will add across the double bond resulting in a colourless product

  • If the substance is saturated the bromine will not react

41
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What is the structure of sulfuric acid in terms of electronegativity

  • Oxygen is highly electronegative

  • So the hydrogen atoms have a partial positive charge

<ul><li><p>Oxygen is highly electronegative </p></li><li><p>So the hydrogen atoms have a partial positive charge </p></li></ul><p></p>
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What happens in the first stage of the reaction between an alkene and concentrated sulfuric acid (H2SO4)

  • Electron pair in the pi bond of the alkene is attracted to the positive hydrogen atom (which acts as an electrophile)

<ul><li><p>Electron pair in the pi bond of the alkene is attracted to the positive hydrogen atom (which acts as an electrophile)</p></li></ul><p></p>
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What are the products formed after stage 1 of an alkene reacting with H2SO4

  • Carbocation intermediate

  • Hydrogensulfate ion

<ul><li><p>Carbocation intermediate</p></li><li><p>Hydrogensulfate ion</p></li></ul><p></p>
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What happens with the Hydrogensulfate ion and the carbocation

  • Lone pair of electrons on the Hydrogensulfate ion are attracted to the positive carbon atom

<ul><li><p>Lone pair of electrons on the Hydrogensulfate ion are attracted to the positive carbon atom </p></li></ul><p></p>
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What happens if you add water to the product (e.g. ethylhydrogensulfate)of an alkene reacting with H2SO4

  • You make an alcohol (in this case ethanol)

  • The alcohol takes the place of the hydrogen sulfate

  • And reform sulfuric acid

<ul><li><p>You make an alcohol (in this case ethanol)</p></li><li><p>The alcohol takes the place of the hydrogen sulfate </p></li><li><p>And reform sulfuric acid </p></li></ul><p></p>
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What happens when an asymmetrical alkene reacts with H2SO4

  • Hydrogensulfate ion will bond to the more stable carbocation

<ul><li><p>Hydrogensulfate ion will bond to the more stable carbocation</p></li></ul><p></p>
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What happens if you add water to the product of an asymmetrical alkene reacting with H2S04

  • OH of the water replaces the Hydrogensulfate

  • Making a major product and sulfuric acid

  • In the example the major product is Propan-2-ol and minor product is Propan-1-ol (only produced in a small quantity)

<ul><li><p>OH of the water replaces the Hydrogensulfate</p></li><li><p>Making a major product and sulfuric acid </p></li><li><p>In the example the major product is Propan-2-ol and minor product is Propan-1-ol (only produced in a small quantity)</p></li></ul><p></p>