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Dehydrogenation/elimination
alcohol → oxidization agent brings in LG to the OH → then a base is used to remove the H from the C and the bond goes to the O and the LG leaves (E2)
primary alcohols → aldehydes (r-c=o-h)
secondary alcohols → ketones (r-c=o-r)
Aldehyde to acid
Requires h2o
aldehyde → hydrate (double bond goes away, r-c-h(oh)2 → ox agent brings in LG → base takes H (E2) → end with a carboxylic acid
wet cr+6 oxidation Jones reagent
CrO3 + h2o + h2so4
wet cr+6 oxidation chromate
Na2cro4 + h2o + h2so4
wet cr +6 oxidation dichromate reagent
Na2cr2o7 +h2o + h2so4
Wet cr+6 oxidation requires h2o
Cr+6 is protonated (o=c=o-oh-oh2) → alcohol (oh takes the protonated Cr which becomes the LG) → h2o takes the H off the OH → h2o comes back in as a base then E2 → acid aldehyde → h2o is added → hydrate is created (O=C is broken & becomes (oh-c-oh-h-r) → same steps again → carboxylic acid
primary alcohol → acid aldehyde → carboxylic acid
secondary alcohol → ketone
Dry cr+6
used to make primary alcohol stop at aldehyde
Needs cr+6 and base
O takes the CrO3 as a LG → O becomes + and one of the O on Cr becomes a single bond & - charge → pyridine takes the H off of OH → the 2nd pyridine does E2 →acid aldehyde
primary alc → acid aldehyde
secondary alc → ketone
Dry cr+6 reagent
cro3 + 2 equiv. of pyridine (benzene with N in as atom in ring)
swern oxidation
2-steps
alcohol takes ox agent & becomes LG → Cl- takes H off of OH → Base takes most acidic H (Ch3) → electrons are added to the C-S → intramolecular elimination occurs (C NBE takes the H off of C-H then that bond goes to O and LG leaves
Primary → aldehyde
Secondary → ketone
swern oxidation reagent
DMSO ( ch3-s=o-ch3) + (Cl-c=o-c=o-cl) → ch3-s-cl-ch3 (ox agent)
Base: N(ch2ch3)3 N with 3 ethyl groups