Physics- Forces and Pressure

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Last updated 4:24 AM on 3/23/26
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23 Terms

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Hooke’s Law

Formula: Force = Spring constant x Extension

The extension of a spring is directly proportional to the force/ load applied to it, provided the limit of proportionality is not exceeded

  • Beyond the extension the spring remains permanently stretched

<p><strong>Formula: Force = Spring constant x Extension</strong></p><p></p><p><strong>The extension of a spring is directly proportional to the force/ load applied to it, provided the limit of proportionality is not exceeded</strong></p><ul><li><p>Beyond the extension the spring remains permanently stretched</p></li></ul><p></p>
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Extension

Extension= Length of spring (with load) - original length of spring (without load)

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Elastic Material

An elastic material is one that will return to it’s original shape when the applied force is removed

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Plastic/Inelastic

A plastic or inelastic material is on that stays deformed when the applied force is removed

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Load-extension Graph

A load–extension graph for an elastic solid, such as a metal wire or spring, displays a linear (straight-line) relationship up to the proportionality limit, demonstrating Hooke’s Law. The graph (load on y-axis, extension on x-axis) has a gradient equal to the spring constant (stiffness).

<p><span><span>A load–extension graph for an </span><strong><span>elastic solid, </span></strong><span>such as a </span><strong><span>metal wire or spring</span></strong><span>, displays a </span><strong><span>linear (straight-line</span></strong><span>) relationship up to the proportionality limit, demonstrating Hooke’s Law. The graph (load on y-axis, extension on x-axis) has a gradient equal to the spring constant (stiffness).</span></span></p>
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Too large force on objects

If too large a force is applied the material will lose its elasticity and be permanently deformed

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Moment

Moment of a force is a measure of its turning effect of a single force

  • Forces can cause the rotation of an object about a fixed pivot

  • This rotation can be clockwise or anticlockwise

e.g. : cap on drink bottle, A see-saw

<p>Moment of a force is a measure of its turning effect of a single force</p><ul><li><p>Forces can cause the <strong>rotation</strong> of an object about a fixed <strong>pivot</strong></p></li><li><p>This rotation can be <strong>clockwise&nbsp;</strong>or&nbsp;<strong>anticlockwise</strong></p></li></ul><p>e.g. : cap on drink bottle, A see-saw</p>
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Moment Formula

  • Formula: Moment = force × perpendicular distance from the pivot

Units for Moments; Newton metre/(Nm)

Increasing the distance at which a force is applied from a pivot decreases the force required

  • If you try to push open a door right next to the hinge, it is very difficult, as it requires a lot of force

  • If you push the door open at the side furthest from the hinge, then it is much easier, as less force is required

<ul><li><p><strong>Formula: Moment = force × perpendicular distance from the pivot</strong></p></li></ul><p></p><p>Units for Moments; <strong>Newton metre/(Nm)</strong></p><p></p><p><strong>Increasing</strong> the <strong>distance</strong> at which a force is applied from a pivot <strong>decreases</strong> the <strong>force</strong> required</p><ul><li><p>If you try to push open a door right next to the hinge, it is very difficult, as it requires a lot of force</p></li><li><p>If you push the door open at the side furthest from the hinge, then it is much easier, as less force is required</p></li></ul><p></p>
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Equilibrium: Is balance

  • The forces on the object must be balanced/ the same

    • There must be no resultant force or resultant moment its in equilibrium

When a body is in equilibrium the sum of clockwise moments = Sum of anticlockwise moments about a pivot

  • Resultant moment = 0

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Example set up of equipment to demonstrate equilibrium

The ruler acts as the beam with the pin as the pivot. Unequal masses are added at different distances until the beam is balanced and equilibrium is reached

Method

  1. Hang unequal loads on either side of the pivot/fulcrum; one while one person hangs the loads

  2. Adjust the distances of mass 1, , and mass 2, , until the beam is balanced 

  3. Adjust further to ensure the beam is perfectly horizontal with no resultant moment

  4. Record the distance from the pivot of masses  and 

  5. Repeat the process for different sized load

<p><strong><em>The ruler acts as the beam with the pin as the pivot. Unequal masses are added at different distances until the beam is balanced and equilibrium is reached</em></strong></p><p>Method</p><ol><li><p>Hang unequal loads on either side of the pivot/fulcrum; one while one person hangs the loads</p></li><li><p>Adjust the distances of mass 1,&nbsp;, and mass 2,&nbsp;, until the beam is balanced&nbsp;</p></li><li><p>Adjust further to ensure the beam is perfectly horizontal with no resultant moment</p></li><li><p>Record the distance from the pivot of masses&nbsp; and&nbsp;</p></li><li><p>Repeat the process for different sized load</p></li></ol><p></p>
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Centre of Mass

The weight of an object acts as a single downward force from a point called the centre of mass or centre of gravity

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Determining the centre of gravity of an irregularly shaped plane lamina

For irregularly shaped objects, the centre of gravity can be found using the suspension method

  1. Punch 3 holes near the outer edges of the shape in different locations

  2. Create a loop of thread and hang the shape from the clamp

  3. Use a plumb line (a weighted thread) aligned with the hanging thread to show the line of action of the weight force

  4. Use a ruler and pencil to mark the line of action of the weight force onto the plane lamina

  5. Repeat the process until 3 lines have been drawn

  6. The point at which the lines intersect is the position of the centre of gravity 

 

Analysis of results

  • Each shape is an irregularly shaped object

  • When an object is suspended from a point, it will always settle with its centre of gravity directly below the point of suspension

<p><strong><em>For irregularly shaped objects, the centre of gravity can be found using the suspension method</em></strong></p><ol><li><p>Punch 3 holes near the outer edges of the shape in different locations</p></li><li><p>Create a loop of thread and hang the shape from the clamp</p></li><li><p>Use a plumb line (a weighted thread) aligned with the hanging thread to show the line of action of the weight force</p></li><li><p>Use a ruler and pencil to mark the line of action of the weight force onto the plane lamina</p></li><li><p>Repeat the process until 3 lines have been drawn</p></li><li><p>The point at which the lines intersect is the position of the centre of gravity&nbsp;</p></li></ol><p><strong>&nbsp;</strong></p><p>Analysis of results</p><ul><li><p>Each shape is an irregularly shaped object</p></li><li><p><strong>When an object is suspended from a point, it will always settle with its centre of gravity directly below the point of suspension</strong></p></li></ul><p></p>
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Position of the centre of gravity on the stability of simple objects

An object is most stable with a low Centre of gravity and a wide base, as a lower Centre of gravity requires a larger tilt angle for the vertical weight line to fall outside the base. Higher, narrower objects are less stable.

<p><strong><mark data-color="rgba(0, 0, 0, 0)" style="background-color: rgba(0, 0, 0, 0); color: inherit;">An object is most stable with a low Centre of gravity and a wide base, as a lower Centre of gravity requires a larger tilt angle for the vertical weight line to fall outside the base</mark></strong><span>. Higher, narrower objects are less stable.</span></p>
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Pressure

pressure is force per unit area;

  • P=F/A

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pressure varies with force and area in the context of everyday

examples

e.g.: Snowshoes: Snowshoes have a large surface area, which spreads a person's weight over a wider area, lowering the pressure on the snow and preventing sinking.

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Extension

Extension in the spring is directly proportional to the applied force causing the extension. ie applied force is double the extension on spring is doubled

<p>Extension in the spring is directly proportional to the applied force causing the extension. ie applied force is double the extension on spring is doubled</p><p></p>
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Spring Constant (k)

The spring constant (k) is a measure of the stiffness ( how difficult it is to stretch it of the spring)

  • Stifffer springs will have larger spring constans (k value

  • Units- N/m or N/cm or N/mm

<p>The spring constant (k) is a measure of the stiffness ( how difficult it is to stretch it of the spring)</p><ul><li><p>Stifffer springs will have larger spring constans (k value</p></li><li><p>Units- N/m or N/cm or N/mm</p></li></ul><p></p>
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Describe, qualitatively, how the pressure beneath the surface of a liquid changes with ensity of the liquid

Effect of Density

  • Liquid pressure is greater in liquids with higher density.

  • A denser liquid has more mass per unit volume.

  • Therefore it exerts greater weight and produces greater pressure at the same depth. Describe how the pressure beneath the surface of a liquid changes with depth and density of the liquid

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Describe, qualitatively, how the pressure beneath the surface of a liquid changes with depth of a liquid

Effect of Depth

  • Liquid pressure increases with depth.

  • The deeper you go below the surface, the greater the pressure.

  • This is because there is more liquid above, so the weight of the liquid increases

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Equation of Liquid Pressure

The Equation for Liquid Pressure: P=ρgh

  • P = change in pressure (Pa) e.g. : N/m²

  • ρ\rho = density of liquid (kg/m³)

  • g = gravitational field strength (N/kg)

  • h = depth (m)

Unit of pressure: Pa (N/m²)

🧠 What This Means

Pressure:

  • Increases with depth

  • Increases with density

  • Increases with gravitational field strength

<p>The Equation for Liquid Pressure: <strong>P=ρgh <br></strong></p><p></p><ul><li><p><strong>P</strong> = change in pressure (Pa) e.g. : <strong>N/m²</strong></p></li><li><p><strong>ρ\rho</strong> = density of liquid (kg/m³)</p></li><li><p><strong>g </strong>= gravitational field strength (N/kg)</p></li><li><p><strong>h </strong>= depth (m)</p></li></ul><p></p><p>Unit of pressure: <strong>Pa (N/m²)</strong></p><p><span data-name="brain" data-type="emoji">🧠</span> What This Means</p><p>Pressure:</p><ul><li><p>Increases with <strong>depth</strong></p></li><li><p>Increases with <strong>density</strong></p></li><li><p>Increases with <strong>gravitational field strength</strong></p></li></ul><p></p>
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Pascal

Pascal = N/m²

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Pressure in Liquids

Pressure in a liquid acts equally in all directions

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Forces effect on size and shape of a body

Forces can change the size and shape of a body

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