C1: Biological Molecules

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58 Terms

1
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Name the four key inorganic ions in living organisms

Magnesium (Mg2+) Iron (Fe2+) Calcium (Ca2+) Phosphate (PO43-)

2
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What is the role of Mg2+ in plants?

Mg2+ is used to produce chlorophyll.

3
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What is the role of Fe2+ in animals?

Fe2+ is found in haemoglobin and is involved in oxygen transport.

4
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What is the role of PO43- in living organisms?

PO43- is used to produce ADP and ATP.

5
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What is the role of Ca2+ in living organisms?

Ca2+ strengthens tissues such as bones and teeth in animals and cell walls in plants.

6
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Why is water a polar molecule?

Oxygen is more electronegative than hydrogen. Oxygen attracts the electron density in the covalent bond more strongly forming δ- O and δ+ H.

7
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Describe hydrogen bonding between water molecules.

Weak intermolecular forces of attraction between a lone pair on a δ- oxygen and δ+ H on an adjacent molecules.

8
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What is a metabolite?

A molecule formed or used in metabolic reactions.

9
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Describe the role of water as a metabolite.

A reactant in photosynthesis and hydrolysis reactions, is also a product in respiration and condensation reactions.

10
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Why is water’s high specific heat capacity important for organisms and plants?

Water acts as a temperature buffer, enabling endotherms to resist fluctuations in core temperature and to maintain optimum enzyme activity. Ensures stability in environmental temperatures for aquatic organisms.

11
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Why is water’s high latent heat of vaporisation important for organisms and plants?

Large amounts of heat energy needed for water to evaporate, so when water evaporates it has a cooling effect. Important in homeostasis as organisms lose heat through sweating and panting.

12
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Why is water an important solvent for organisms?

Water is a polar solvent enabling chemical reactions to take place within cells, the transport of materials in the plasma and the removal of metabolic waste.

13
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Why does water have a high surface tension?

Due to cohesion and ordered arrangement of molecules at the surface of the water.

14
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Why is water’s high surface tension important?

  • Enables the transport of water and nutrients through plant stems and small blood vessels in the body

  • Allows small insects to walk on water- pondskater

15
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What is a monosaccharide?

Simple sugar with formula Cn(H2O)n.

16
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Give some examples of monosaccharides.

  • ribose

  • deoxyribose

  • α-glucose

  • β-glucose

  • fructose

  • galactose

17
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Draw α-glucose.

A monosaccharide where the OH on carbon-1 is below the C1 atom.

<p>A monosaccharide where the OH on carbon-1 is below the C1 atom.</p>
18
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Draw β-glucose.

A monosaccharide where the OH on carbon-1 is above the C1 atom.

<p>A monosaccharide where the OH on carbon-1 is above the C1 atom.</p>
19
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What is the difference between deoxyribose and ribose sugars?

Deoxyribose lacks one oxygen atom compared to ribose.

20
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What bond is formed when two monosaccharides react?

Glycosidic bond.

21
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What is a disaccharide?

Two monosaccharides joined by condensation reaction forming a glycosidic bond

Formula - (C12H22O11)

22
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Give examples of disaccharides and their constituents.

  • sucrose glucose-fructose

  • maltose α-glucose–α-glucose

  • lactose glucose–galactose.

23
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What is a polysaccharide?

A polymer of monosaccharides formed by many condensation reactions.

24
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Give examples of polysaccharides.

  • starch

  • glycogen

  • cellulose

  • chitin

25
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What are characteristics of polysaccharides?

  • Unable to diffuse out of the cell

  • Compact in shape so glucose can be stored in a cell

  • Insoluble in water so they do not alter the water potential, no osmotic effect

  • easily hydrolysed into constituent monosaccharides

26
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What is the function of starch?

Energy storage in plants.

27
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Describe the structure of starch- amylose and amylopectin

  • Polymer of alpha glucose monomers

  • Amylose: alpha 1-4 glycosidic bonds unbranched

  • Amylopectin: alpha 1-4 and 1-6 glycosidic bonds branched

  • Amylopectin more branched means there are more exposed ends that can be hydrolysed resulting in a rapid release of glucose

28
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What is the function of glycogen?

Energy storage in animals.

29
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How does glycogen’s structure relate to its function?

Highly branched for rapid hydrolysis of glucose, more branched than amylopectin.

30
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Describe the structure and function of cellulose.

  • Linear polysaccharide that is the main component of the cell wall in plants

  • β-glucose molecules joined by β-1 4 glycosidic bonds

  • alternate glucose molecules rotated 180^ allowing hydrogen bonds between parallel chains forming myofibrils

31
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Describe the structure and function of chitin.

  • Linear polysaccharide found in the exoskeletons of insects and fungal cell walls

  • Consists of many β-glucose molecules with acetyl amine side group joined by 1-4 β-glycosidic bonds

  • Alternate glucose molecules rotated 180^ allowing h bonds between parallel chains, forming myofibrils

32
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Explain how a triglyceride is formed.

One molecule of glycerol joins three fatty acids via condensation forming ester bonds.

33
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Relate triglyceride structure to function.

  • Energy storage, high calorific value from oxidation

  • Insoluble hydrocarbon chain- no effect on water potential of cells, used for waterproofing

  • Thermal insulation- slow conductor of heat

  • Buoyancy of aquatic animals- less dense than water

34
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What is a phospholipid?

Lipid formed by the condensation of one molecule of glycerol, two molecules of fatty acid and a phosphate group.

35
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Relate phospholipid structure to function.

Glycerol backbone attached to two hydrophobic fatty acid tails and one hydrophilic polar phosphate head

  • forming phospholipid bilayer in water- component of cell membrane

  • waterproofing, tail splays outwards

36
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Difference between saturated and unsaturated fats.

  • Saturated no C=C bonds and are solid at room temperature due to strong intermolecular forces

  • Unsaturated one or more C=C liquid at room temperature due to weak intermolecular forces

37
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Difference between monounsaturated and polyunsaturated fats.

Monounsaturated- one C=C bond Polyunsaturated- more than one C=C bond.

38
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What is a low density lipoprotein (LDL)?

  • Combination of triglycerides from saturated fats and protein

  • blocks receptor sites reducing cholesterol absorption

  • ‘bad’ lipoprotein

39
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How do LDLs contribute to cardiovascular disease?

Cause high blood cholesterol leading to atherosclerosis plaque formation.

40
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Describe the general structure of an amino acid and draw it.

Amine group carboxyl group hydrogen variable R group.

<p>Amine group carboxyl group hydrogen variable R group.</p>
41
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How are polypeptides formed?

Many amino acids join via condensation forming peptide bonds and water.

42
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What is the primary structure of a protein?

Individual sequence of amino acids in a chain.

43
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Describe the secondary structure of a protein.

Folding of primary structure into a 3D shape held together by hydrogen bonds creating alpha helices and beta pleated sheets.

44
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Describe the tertiary structure of a protein.

Folding of alpha helices into a compact shape maintained by disulphide, ionic, hydrogen bonds and hydrophobic interactions. Gives globular proteinstheir functional 3D shape.

45
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Describe the quaternary structure of a protein.

Combination of two or more polypeptide chains in tertiary from combined. May involve prosthetic groups- haem group in haemoglobin.

46
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How does fibrous protein structure relate to function?

Long polypeptide chains folded in parallel. Cross-links for strength making them insoluble, good for structural roles.

47
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How does globular protein structure relate to function?

  • Compact spherical highly folded with tertiary/quaternary structures

  • Hydrophilic R groups face outwards and hydrophobic R groups face inwards making it water-soluble

  • Example is haemoglobin- 4 polypeptide chains haem group containing iron in the middle

48
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Difference between reducing and non-reducing sugars.

Reducing sugars have free aldehyde or ketone group non-reducing do not.

49
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Describe the Benedict’s test for reducing sugars.

  • Add and equal volume of sample being tested and Benedict’s reagent

  • Heat the mixture in an electric water bath at 100^ for 5 minutes

  • Observe the colour of the precipitate formed

50
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Positive result for reducing sugars.

Colour changes from green to yellow to orange to brown to brick red depending on quantity of sugar.

51
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Describe Benedict’s test for non-reducing sugars.

  • Negative test for reducing sugar

  • Hydrolyse non-reducing sugars with an equal volume of dilute HCL

  • Heat in a boiling water bath for 5 minutes

  • Add sodium hydrogen carbonate to neutralise the acid

  • Re-test resulting solution with Benedict’s reagent

  • Observe colour of precipitate formed

52
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Positive result for non-reducing sugars.

Colour change from green to yellow to orange to brown to brick red depending on quanitity of sugar.

53
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Food test for proteins

Biuret test.

54
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Describe the Biuret test

Add a few drops of biuret reagent to sample.

55
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Positive result of Biuret test.

Colour change from pale blue to purple.

56
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Describe iodine-potassium iodide test for starch.

Add iodine-KI solution, orange to blue-black if starch present.

57
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Describe the emulsion test for fats and oils.

Add ethanol and shake allowing mixture to settle, add equal volume of water and observe mixture.

58
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Positive result of emulsion test.

White cloudy emulsion forms.