1/14
Looks like no tags are added yet.
Name | Mastery | Learn | Test | Matching | Spaced | Call with Kai |
|---|
No analytics yet
Send a link to your students to track their progress
Formulas for Q (charge)
Q = It
Q = ±Ne (± can be optional sometimes)
Q = CV
Define Coulomb
amount of charge when 1 amp flows for 1 second
Define potential difference
the energy transferred per unit charge between two points in a circuit
Define Volt
1 joule per coulomb
V = W/Q
state Ohms law
current is directly proportional to voltage and inversely proportional to resistance
V = IR
Power equations
P = IV
P = I2R
P = V2/R
P = E/t
Define resistivity
An intrinsic material property measuring how strongly a substance opposes electric current flow. Equal to the resistance R of a specimen, multiplied by its cross-sectional area A, and divided by its length l
rho = RA/ l
Resistivity vs Resistance
Resistance - Depends on shape, size, and material (e.g., a long wire has high resistance).
Resistivity - Depends only on the material (e.g., copper has low resistivity regardless of its size).
EMF vs Potential
(EMF) is the total energy provided by a source (like a battery) per unit charge, acting as the "cause" of current. V = E -Ir
Potential difference (PD) is the energy dissipated by a unit charge passing between two points in a circuit
Define drift velocity
Drift velocity is the average velocity of charged particles due to an electric field
I = nevA
Where I = current, n = number of charge carriers per unit volume (m-3) , v = the mean drift velocity of the electrons /m s^-1, A = area (m2)
Derive I = nqvA

Explain how terminal potential difference , internal resistance and ideal source are related in a practical source of electromotive force (EMF) such as an alkaline battery.
A practical source has internal resistance r, so some energy is lost inside the source when current flows. The e.m.f. ε represents the total energy supplied per unit charge, while the terminal potential difference V is the energy available to the external circuit.
When current flows, a voltage drop Ir occurs inside the source. Therefore,
V=ε−Ir
For an ideal source, r=0 so V=ε