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Last updated 4:06 AM on 3/31/26
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8 Terms
1
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nNaOH = 0
[H30+] = root Ka x acid; pH = -log [H30+]
2
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nNaOH < na
na' = na - nNaOH; nb' = nNaOH; pH = pKa + log (nb'/na')
3
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nNaOH = na
[base]' = (na/Va+VNaOH); [OH-] = root Kb x [base]';
pH = 14 + log[OH-]
4
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nNaOH > na
[OH-] = (nNaOH - na / Va + VNaOH); pH = 14 + log [OH-]
5
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nHCl = 0
[OH-] = root Kb x base; pH = 14 + log [OH-]
6
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nHCl < nb
na' = nHCl; nb' = nb - nHCl; pH = (14 - pKb) + log (nb'/na')
7
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nHCl = nb
[acid]' = (nb / Vb + VHCl); [H30+] = root Ka x [acid]';
pH = -log [H30+]
8
New cards
nHCl > nb
[H30+] = (nHCl - nb / Vb + VHCl); pH = - log [H30+]
