Op-Amps

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Last updated 10:39 PM on 1/1/26
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16 Terms

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What does an Op-Amp do?

An Operational Amplifier essentially scales an input signal (Vin) to an output signal (Vout) by a factor of A.


Vin = | V- - V+ |

<p>An Operational Amplifier essentially scales an input signal (V<sub>in</sub>) to an output signal (V<sub>out</sub>) by a factor of A.</p><p><br>V<sub>in</sub> = | V<sub>-</sub> - V<sub>+ </sub>|</p>
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Key features of an Op - Amp

  • Active device, so has two power supplies
    {+VCC and -VEE}

  • Output signal (Vout) can only range between +VCC and -VEE.

    • Usually ±15V

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Ideal Op-Amp Characteristics

  • Rin = Infinite Ohms

    • Leads to Iin = 0A

  • Rout = 0 Ohms

  • Open loop Gain (A) is infinite

  • A is independent of frequency

  • Ideal Op-Amp is also unaffected by temperature

  • Infinite slew rate

    • Change in Vin leads to instant change in Vout


THIS IS ONLY FOR IDEAL OP AMPS

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Virtual Short

For an ideal Op-Amp:

  • A → Infinity

  • Vout → Finite Value

  • V+ = V- {Signifies a virtual short}

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Types of Amplifiers

  1. Inverting Op-Amp

  2. Summing Op-Amp

  3. Transresistance Op-Amp

  4. Integrator

  5. Differentiator

  6. Voltage Follower

  7. Non-Inverting Op-Amp

  8. Transconductance Op-Amp

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Inverting Op-Amp

Inverts the polarity of an input voltage

<p>Inverts the polarity of an input voltage</p>
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Summing Op-Amp

Sums multiple input voltages together

<p>Sums multiple input voltages together</p>
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Transresistance Op-Amp

A Current-to-Voltage converter

<p>A Current-to-Voltage converter</p>
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Integrator

Output voltage is the integral of input voltage

  • -1/RC is a constant

Also acts like a lowpass filter

<p>Output voltage is the integral of input voltage</p><ul><li><p>-1/RC is a constant</p></li></ul><p>Also acts like a lowpass filter</p>
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Problem/Solutions with an Integrator in real life

Problem:

  1. At low frequencies, loop gain goes to infinity

Solutions:

  1. Use Large values of R and C

  2. Zero output regularly, but placing a switch across the capacitor

  3. Add a large resistor across the capacitor

    • {This is now just an inverting amplifier at low frequencies, not an integrator}

<p>Problem:</p><ol><li><p>At low frequencies, loop gain goes to infinity</p></li></ol><p></p><p>Solutions:</p><ol><li><p>Use Large values of R and C</p></li><li><p>Zero output regularly, but placing a switch across the capacitor</p></li><li><p>Add a large resistor across the capacitor</p><ul><li><p>{This is now just an inverting amplifier at low frequencies, not an integrator}</p></li></ul></li></ol><p></p>
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Differentiator

Output voltage is the derivative of the Input Voltage

  • -RC is a constant

Also acts as a highpass filter

<p>Output voltage is the derivative of the Input Voltage</p><ul><li><p>-RC is a constant</p></li></ul><p>Also acts as a highpass filter</p>
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Problem/Solution with a Differentiator in real life

Problem:

  • High gain at high frequencies, and can lead to unstable output

Solution:

  • Place a resistor in series with input capacitor
    {Acts as an inverting Op-Amp at high frequencies, not a differentiator}

<p>Problem:</p><ul><li><p>High gain at high frequencies, and can lead to unstable output</p></li></ul><p>Solution:</p><ul><li><p>Place a resistor in series with input capacitor <br>{Acts as an inverting Op-Amp at high frequencies, not a differentiator}</p></li></ul><p></p>
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Voltage Follower

Ensures Output Voltage = Input Voltage

Acts as a buffer

<p>Ensures Output Voltage = Input Voltage</p><p></p><p>Acts as a buffer</p>
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Non-Inverting Op-Amp

Output voltage is a positive multiple (A) of the Input Voltage

A is the gain

<p>Output voltage is a positive multiple (A) of the Input Voltage</p><p>A is the gain</p>
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Transconductance Op-Amp

A Voltage-to-current converter

<p>A Voltage-to-current converter</p>
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Input Bias Current

In real life, the terminals on the Op-Amps have a current flowing through them

This can be compensated by connecting a specific resistor (RB) where the input bias current goes to 0A.

<p>In real life, the terminals on the Op-Amps have a current flowing through them</p><p></p><p>This can be compensated by connecting a specific resistor (R<sub>B</sub>) where the input bias current goes to 0A.</p>