Keywords and definitions for NCEA Level 3 calculus, 3.6 (Differentiation) and 3.7 (Integration)
f(x)= ln(x)
f’(x)= 1/x
f(x)= e^ax
f’(x)= ae^ax
f’(x)=e^ax
f(x)=e^ax/a
f(x)= sin(x)
f’(x)= cos(x)
f(x)= cos(x)
f’(x)= -sin(x)
f(x)= tan(x)
f’(x)= sec²(x)
f(x)= sec(x)
f’(x)= sec(x)tan(x)
f(x)= cosec(x)
f’(x)= -cosec(x)cot(x)
f(x)= cot(x)
f’(x)= -cosec²(x)
Product Rule
y’=uv’+u’v
Quotient Rule
y’= (u’v-v’u)/v²
Chain Rule
(u(v))’=u’(v)v’
Concave up
f’(x) is increasing
Concave down
f’(x) is decreasing
Stationary point
f’(x)=0
Local minimum
f’’(x)>0
Local maximum
f’’(x)<0
Area between two curves
[(lower curve)’-(upper curve)’]
Tangent line
Straight line with same gradient as a point.
Normal line
Straight line perpendicular to the tangent line.
s(t)
displacement
v(t)
velocity
a(t)
acceleration
Continuous
A function is one continuous line, it can be drawn without lifting the pen
Differentiable
A function is continuous, and with no corners or sharp points (it is all one function)
c
Constant of integration
Area under curves bound by x-axis
Integrate with respect to y
Area under curves bound by y-axis
Integrate with respect to x
Calculate distance
Area under displacement graph
Finding gradient
Differentiate then substitute in known point
Finding equation of tangent
Find (x,y) using original function. Differentiate and substitute x to find gradient. Use y-y1=m(x-x1) to find equation
Finding equation of normal
Find (x,y) using original function. Differentiate and substitute to find tangent gradient. Divide this by -1 to find normal gradient. Use y-y1=m(x-x1) to find equation
Integration by substitution
Substitute u=g(x), find dx=du/u. If needed, find x=g(u). Substitute and integrate. Substitute g(x) back in for u.
Differentiate parametric function
dy/dx=dy/dt * dt/dx
Cancel out e
ln both sides
Cancel out ln
e^ both sides
Integrating differential equations
Get wanted variable on one side, integrate both sides. Simplify wanted variable using e. Substitute in known values to solve for unknown. Then substitute to find answer.
Differentiation involving geometric shapes
Find known derivative and write as a function of known functions (e.g. dV/dt=dV/dr*dr/dt). Solve.
Area above x-axis
Positive (add together)
Area below x-axis
Negative (subtract from)
Average area under sine/cosine graph
0
Secant line
Straight line connecting two points on a curve
Exponential growth/decay
y=Ae^kt