Lecture 22: Mirrors and Snell's Law

0.0(0)
studied byStudied by 0 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/26

flashcard set

Earn XP

Description and Tags

23.1-23.5 Giancoli

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

27 Terms

1
New cards

ray model of light

light travels in straight lines, we represent light using rays which are straight lines emanating from each single point on an object, these rays entering the eye makes the image

2
New cards

Law of Reflection

angle of reflection is equal to the angle of incidence

3
New cards

when an object is placed in front of a plane mirror, its image appears to be…

behind the mirror

4
New cards

plane mirror image

5
New cards

Types of images

real image

virtual image

6
New cards

real image

when light rays actually pass through the image location

7
New cards

virtual image

when the light rays do not pass through the image location

8
New cards

Types of spherical mirrors

  • convex

  • concave

9
New cards

concave mirrors: parallel rays after reflection from a mirror converge at a point called…

the focal point

10
New cards

mirror equation

  • relates the object distance, image distance, and focal length of the mirror

1/d0 + 1/di = 1/f

  • 1/distance of object + 1/distance of reflected image = 1/distance to focal point

11
New cards

magnification equation

m = hi/ho = -di/do

  • hi = height of image

  • ho = height of the object

  • di = image distance

  • do = object distance

NOTE: negative sign indicates that the image is inverted

12
New cards

Convex mirrors

13
New cards

convex and concave mirrors table relating to mirror equation and magnification

14
New cards

If you look at yourself in a Christmas three ball with a diameter of 9cm when your face is 30 cm away from it, where is your image, is it real of virtual, is it upright or inverted?

real or virtual

to get radius, 9/2 = 4.5 cm

since mirror is convex, focal length will be neg and given by

  • f = r/2 = 4.5/2 = -2.25

object distance = distance from face to mirror

  • do = +30 cm

1/do + 1/di = 1/f

1/30 + 1/di = 1/-2.25 —> di = -2.1 cm

since distance is negative, the image is virtual (appears behind the mirror)

magnification

m= ho​/hi​​= −do​/di​​

m = -(2.1/30) = 0.07

therefore image is upright (positive magnification)

image is smaller by 7%

15
New cards

a concave mirror has a radius of 42 cm. an object is laced 84 cm in front of the mirror’s principal axis. Where is the image located?

f = r/2 = 42/2 - 21 cm

1/do + 1/di = 1/f

1/84 + 1/di = 1/21

di = 28

m = hi/ho = -di/do

m = -28/84 = -0.333

16
New cards

a dentist holds a concave mirror of r = 50 mm at a distance of 20 mm from a cavity in a tooth, what is the image of the cavity, what is the size of the image

1/do + 1/di = 1/f

  • f = d/2 = 50/2 = 25

  • 1/20 + 1/di = 1/25

  • di = -100 mm

m= -di/do = -(-100/20) = 5

image is virtual

17
New cards

index of refraction

  • light slows down when traveling through any medium

  • ratio of the speed of light in vacuum to the speed of light n the medium is called the index of refraction of he medium

  • n = c/v

    • c = speed of light in vacuum

    • v = speed of light in medium

18
New cards

The higher the index of refraction the…

slower light will travel through that material

19
New cards

what is refraction

  • light changes direction when crossing a boundary from one medium to another

20
New cards

refraction formula and theory

the angle of refraction depends on the speed of light in the two mediums (media) and the incident angle

  • sin theta1/sin theta2 = v1/v2

21
New cards

snells law

v = c/n

  • c = speed of light in vacuum

  • v = speed of light in medium

  • n = index of refraction

THEREFORE:

n1 sin(theta1) = n2 sin(theta2) [snell’s law]

  • n2 > n1 → towards the normal line

  • n2 < n1 → away from the normal line

22
New cards

a flashlight beam strikes a surface of a pane of glass (n =1.52) at 63 degrees to the normal, what is the angle of refraction

23
New cards

total internal reflection - fiber optics

  • when light passes into a medium whose n2 < n1, then theta-r > theta-i

  • there is an angle theta-i for which theta-r = 90 degrees

  • this is called the critical angle theta-c

  • if theta-i is larger than theta-c, no transmission occurs

  • this is called total internal reflection

24
New cards

n1 sin theta(1) = n2 sin theta(2)

  • as theta(1) increases so does theta(2)

  • at critical angle → theta(2) = 90 degrees

  • n1sin theta-c = n2 sin90

  • theta-c = inverse sine(n2/n1)

    • when theta 1 > theta-c LIGHT IS TOTALLY REFLECTED BACK INTO THE SAME MEDIUM

25
New cards

total internal reflection is the

principle behind fiber optics

26
New cards

Light will be transmitted along the fiber even if it is not

straight

27
New cards

image can be formed using

multiple small fibres