investigation 4: diffusion and osmosis

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Last updated 3:23 AM on 4/1/25
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1
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part 1: surface area and cells — basic setup

demonstrate relationship between SA and volume and how this ratio affects diffusion rates.

  • block of agar that has indicator dye that changes colour when pH drops

  • cut blue agar into 3 different block sizes with diff SA-volume ratios (SA:V)

  • each block is dropped into a solution & diffuses. Track the time it took to fully diffuse

2
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part 1: surface area and cells — results

larger SA = slowest diffusing time

  • high SA:V ratio is important for any cell that relies on high diffusion rate.

  • eg. the linings of ur small intestines and lungs have many folds in order to create the highest SA possible in the smallest amount of space

3
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Part 2: modelling diffusion and osmosis — basic setup

dialysis tubing, selectively permeable to water and some solutes

4
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Part 2: modelling diffusion and osmosis — results

when molarities are equal (eg 1 mol sucrose & 1 M NaCl) and the solution becomes lighter after 30 minutes for example, ionization constant from solute potential equation becomes the deciding factor. NaCl ionizes but sucrose doesn’t (i = 2). Thus water diffuses out of the bag into surrounding NaCl solution

5
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part 3: observing osmosis in living cells — basic setup

surcose solutions (0 mol to 3 mol) and use potato cores to find out the relative concentrations of these solutions. U can then calculate %change in weight of potato cores & get the water potential of potato tissue

bigger the difference in water potential between a cell and solution, the bigger the movement of water (into our out)

6
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part 3: observing osmosis in living cells — results

  • arrange change in weight from most negative to positive

    • very (-) means heavy loss of water

    • very (+) means heavy water gain (hypotonic), greater the weight, the lower the molarity of the solution

  • graph %changes in weight and find x intercept which indicates the molarity when there would be no net change in weight.

    • if water potential of the solution = cell water potential

<ul><li><p>arrange change in weight from most negative to positive</p><ul><li><p>very (-) means heavy loss of water</p></li><li><p>very (+) means heavy water gain (hypotonic), greater the weight, the lower the molarity of the solution</p></li></ul></li><li><p>graph %changes in weight and find x intercept which indicates the molarity when there would be no net change in weight. </p><ul><li><p>if water potential of the solution = cell water potential </p></li></ul></li></ul><p></p>

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