PHYS GRIND QQ

0.0(0)
studied byStudied by 0 people
GameKnowt Play
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/99

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

100 Terms

1
New cards
term image
  1. Initial Launch Phase (Rocket Engine On):

    • The rocket engine does work on the satellite, increasing its kinetic energy (speed) and gravitational potential energy (altitude).

    • Total energy (mechanical energy) of the satellite-Earth system increases because energy is added by the engine.

  2. After Engine Shutoff (Elliptical Orbit):

    • In the elliptical orbit, the satellite's total energy remains constant (conserved) because no external forces do work (ignoring minimal atmospheric drag).

    • Energy transformations occur between kinetic and potential energy:

      • At perigee (closest to Earth), the satellite moves fastest (maximum kinetic energy, minimum potential energy).

      • At apogee (farthest from Earth), the satellite moves slowest (minimum kinetic energy, maximum potential energy).

2
New cards
term image
knowt flashcard image
3
New cards
term image
knowt flashcard image
4
New cards
term image
knowt flashcard image
5
New cards
term image
6
New cards
term image
knowt flashcard image
7
New cards
term image
knowt flashcard image
8
New cards
term image
knowt flashcard image
9
New cards
term image
knowt flashcard image
10
New cards
term image

B

11
New cards
term image
knowt flashcard image
12
New cards
term image
knowt flashcard image
13
New cards
term image
knowt flashcard image
14
New cards
term image
knowt flashcard image
15
New cards
term image
knowt flashcard image
16
New cards
term image

B - point of reflection is when flux is steepest, therefore greatest change in flux, therefore max EMF

17
New cards
term image

D. All the choices result in the same acceleration

Because the electric field is uniform, every electron between the plates experiences the same force (eEeE) and thus the same maximum acceleration (eEmemeeE), regardless of its starting point or initial motion.

18
New cards
term image

Option D correctly identifies that the motor in Test 1 reaches a higher speed, generating more back EMF, which opposes the current. In Test 2, the lower speed reduces back EMF, allowing more current to flow.

19
New cards
<p>Question B </p>

Question B

  1. Field from Wire 1 (1.0 A, left):

    B1=μ0I12πr=(4π×10−7)(1.0)2π(0.075)=2.67×10−6 TB1​=2πrμ0​I1​​=2π(0.075)(4π×10−7)(1.0)​=2.67×10−6T

    • Direction: Downwards (anticlockwise around Wire 1, right side).

  2. Field from Wire 2 (3.0 A, right):

    B2=μ0I22πr=(4π×10−7)(3.0)2π(0.075)=8.00×10−6 TB2​=2πrμ0​I2​​=2π(0.075)(4π×10−7)(3.0)​=8.00×10−6T

    • Direction: Upwards (anticlockwise around Wire 2, left side).

  3. Net Field at Midpoint:

    Bnet=B2−B1=5.33×10−6 T(upwards)Bnet​=B2​−B1​=5.33×10−6T(upwards)

Final Answer:
The magnetic field midway between the wires is 5.33×10−6 T5.33×10−6T upwards.

Why?

  • Both fields circulate anticlockwise when viewed from above.

  • At the midpoint:

    • Wire 1’s field points down (right side of Wire 1).

    • Wire 2’s field points up (left side of Wire 2).

  • The stronger field (B2B2​) dominates, giving a net upward field.

This opposition occurs because the midpoint is on opposite sides of the two wires, even though currents flow the same way.

20
New cards
term image
knowt flashcard image
21
New cards
term image
knowt flashcard image
22
New cards
term image
knowt flashcard image
23
New cards
term image
knowt flashcard image
24
New cards
term image
knowt flashcard image
25
New cards
term image

Since there are two motors contributing equally:

τtotal=2×τ1 motor=2nIAB.τtotal​=2×τ1 motor​=2nIAB.

<p>Since there are <strong>two motors</strong> contributing equally:</p><p><span>τtotal=2×τ1&nbsp;motor=2nIAB.<em>τ</em>total​=2×<em>τ</em>1&nbsp;motor​=2<em>nIAB</em>.</span></p>
26
New cards
term image
27
New cards
term image

B

28
New cards
term image
knowt flashcard image
29
New cards
<p><span>sketch on the graph about how the intensity will change with time if the plane polarised light is replaced with an unpolarised light source of equal intensity</span></p>

sketch on the graph about how the intensity will change with time if the plane polarised light is replaced with an unpolarised light source of equal intensity

The graph for unpolarized light is a horizontal line at half the peak polarized intensity because:

  1. The filter transmits a constant average (50%) of the random polarizations.

  2. Unpolarized light’s intensity is never higher than polarized light’s peak—it just doesn’t dip to zero.

<p>The graph for unpolarized light is a <strong>horizontal line at half the peak polarized intensity</strong> because:</p><ol><li><p class="ds-markdown-paragraph">The filter transmits a <strong>constant average</strong> (50%) of the random polarizations.</p></li><li><p class="ds-markdown-paragraph">Unpolarized light’s intensity is <strong>never higher</strong> than polarized light’s peak—it just doesn’t dip to zero.</p></li></ol><p></p>
30
New cards
31
New cards

Properties of an electric field

  • never intersect

  • perpendicular to the surface of the charge

  • magnitude of charge and the no. of field lines are proportional.

32
New cards

Uniform electric field formula

E = V.d.

<p>E = V.d. </p>
33
New cards

Force in an electric field

Stationary

  • F = Eq

  • W = Eq*d

Coming in from the side

  • KE = W = 1/2mv2

  • 1/2mv2 = qEd

34
New cards

Charges in mag. field - concept

Any moving charge has a magnetic field associated with it. A moving stream of electrons will experience a force inside a magnetic field.

Why?

= The stream of charged particles has its own magnetic field which interacts with the external magnetic field.

35
New cards

External magnetic field formula

F=bvqsintheta

36
New cards

Charges in magnetic field - pathways

The force on a charged particle in a magnetic field always at right angles to the velocity of the charged particles. This creates circular motion

R=mv/qb

37
New cards

Electric vs. magnetic field

Similarities and differences

38
New cards

Motor effect

A current carrying conductor in the presence of a magnetic field will experience a force

F = BILsintheta

39
New cards

Motor effect - variable changes the size of the force

Voltage

40
New cards

Variable —> changes direction of force of wire in magnetic field

Polarity of magnetic wire + direction of flow of positive charge relative to B.

41
New cards

Force between wires

<p></p>
42
New cards

Ampere + Newton’s third law of force between 2 wires

Ampere = the constant current which if maintained in two straight parallel conductors would produce between those conductor a force equal to 2×10-7Nm-1 length

Newton’s third law = if one wire applies a force to a second wire, the second wire will apply a force that is equal in magnitude and opposite in direction on the first wire.

43
New cards

DC Motor - definition + formulas

A device that transforms electrical potential energy into rotational KE through the application of a DC current

T = F.d

F = B.I.L

T = nIABsintheta

44
New cards

Components of a DC motor

  1. Split ring commutator = reverses the direction of current every 180 ensuring continuous turning occurs.

  2. Magnet = provides an external magnetic field in which the coil rotates

  3. Axle = provides a point of rotation for the armature. Transfers the rotational energy to another appliance

  4. Coil = carries current to produce mechanical energy

  5. Brush = acts as a conductive connection between SRC, armature, & power supply

  6. Battery = provides current

45
New cards
  1. Two ways the efficiency of the motor can be improved:

  2. Why electromagnets

  1. Reduce friction + add more coils

  2. To turn motor off + control its strength

46
New cards

Magnetic flux definition and formula

The measure of total magnetic field lines in a set area.

<p>The measure of total magnetic field lines in a set area. </p><p></p>
47
New cards

Magnetic flux density definition

Is a measure of how densely packed the flux lines are. (T)

48
New cards

Faraday’s law definition + formula

Faraday determined that the size of the EMF that is generated is proportional to the rate at which flux is cut. For EMF to be generated there must be relative movement between conductor and magnetic field.

<p>Faraday determined that the size of the EMF that is generated is proportional to the rate at which flux is cut. For EMF to be generated there must be relative movement between conductor and magnetic field. </p>
49
New cards

Lenz’s law

Emf generated by cutting flux will generate a current flow if a complete circuit is provided. When current is generated it will create a magnetic field that opposes the change.

Faraday’s law says that “cutting flux leads to voltage.” Electrical law says “but voltage only leads

50
New cards

Explain how a voltage is produced when the magnet is dropped into the coil?

When magnetic flux lines are cut by a conductor, the charges in the wire conductor experiences a force.

(Internal interacting with external magnetic field).

51
New cards

Steps in Lenz’s law

  1. EMF produced by cutting flux

  2. EMF drives current

  3. The current flowing creates its own magnetic field. This magnet will oppose the magnetic field.

52
New cards

Torque

Turning effect of a force

53
New cards

Back EMF

A motor has an applied EMF which drives current through coil. As the motor starts to spin the armature starts to cut flux. This means that the motor unintentionally acts as a generator. The EMF generated always opposes the applied EMF, due to Lenz’s law,

54
New cards

Lenz’s law and conservation of energy

Ensure that the induced current’s energy comes from the work done against the opposing force.

55
New cards

Eddy current’s role in magnetic breaking

  • Generate their own opposing magnetic field, resisting motion

  • Kinetic energy convert to heat, slowing the object.

56
New cards

Magnet falling through copper wire

  1. Eddy current: as magnet falls, its changing field induces eddy current in pipes.

  2. Opposing force: These magnet create a mag. field that opposes the magnet’s motion

    1. Energy loss: kinetic energy is dissipated as heat, reducing net acceleration S

57
New cards

AC induction motor

An AC induction motor is an electric motor where torque is generated by current induced in the rotor via electromagnetic interaction with the stator’s rotating magnetic field.

  • The stator’s AC-powered windings produce a rotating magnetic field.

  • This changing field induces a current in the rotor conductors (Faraday’s law).

  • The rotor’s current creates its own magnetic field, which opposes the stator’s field (Lenz’s law), producing torque.

58
New cards

Stator =

provides the external mag. field in which the rotor rotates

59
New cards

Rotor

comprises a series of conductors (metal bars) and the rotor rotates about the axis of the motor’s shaft.

  • Allows a current to flow from one side to the other side of the cage.

60
New cards

Steps in AC induction motor

  1. AC is supplied to the stator - the surrounding electromagnet

  2. produces an oscillating mag. field

  3. induces a current in the rotor

  4. turns the rotor into an electromagnet

  5. tries to oppose the stator field being generated (Lenz’s law)

  6. stator and rotor push against each other (mag. field)

  7. cause the rotor to return

61
New cards

Transformers

Simple devices that allow us to use an input voltage and make it into output voltage that is larger or smaller depending on the need. Ste

62
New cards

Step-up transformer

When the no. of coils in the secondary coil is larger

63
New cards

Step-down transformer

When the no. of turns in secondary is less than primary A

64
New cards

Primary coil - transformer

Receives an input voltage and induces a changing mag. field

65
New cards

Secondary coil - transformer

Produces a voltage based on the turn’s ratio, enabling efficient voltage transformation for electricity distribution

66
New cards

Soft core - transformer

Reduce eddy current loss and provide a low reluctance path for flux current.

67
New cards

Two applications in tansformer

Microwave ovens: step-up transformers increase the voltage to power the magnetron

Doorbell systems: step-down transformers reduce voltage for safe operation of the doorbell circuit.

68
New cards

Why is AC current required for the function of a transformer

AC— constant changing current

  • Creates a changing mag. field to induce a voltage in the secondary coil

69
New cards

Linkage between transformers + law of conservation of energy

Transformers uphold the law of conservation of energy by transferring electrical energy from one circuit to another with minimal loss. I

70
New cards

Ideal transformers

Would have no energy loss, meaning the energy output would exactly equal the energy input. However, real-world transformers always have some losses, making them less than 100% efficient.

71
New cards

Eddy current

Are spiral shaped currents that form within electrical conductors when they are placed inside a changing magnetic field.

72
New cards

Limitations of transformers

knowt flashcard image
73
New cards

Force vs torque graph in motor

knowt flashcard image
74
New cards

EMF graph between DC and AC generators

the emf is zero when the normal of the coil is perpendicular to the magnets

<p>the emf is zero when the normal of the coil is perpendicular to the magnets</p>
75
New cards

Why is a slip ring used in an AC generator

  • The current is already AC, so there is no need to reverse the current direction with a split ring.

  • A slip ring is used to preserve the AC current. Slip rings remain in contact with the brushes throughout the entire 360 rotation.

76
New cards

AC vs. DC generator

<p></p>
77
New cards

Transformer diagram

knowt flashcard image
78
New cards
term image

C

79
New cards
term image

A

80
New cards
term image
knowt flashcard image
81
New cards
term image
knowt flashcard image
82
New cards
term image
knowt flashcard image
83
New cards
term image
knowt flashcard image
84
New cards
term image
  1. Eddy Currents and Lenz's Law:

    • When a magnet moves through a copper pipe, it induces eddy currents in the pipe.

    • These currents create a magnetic field opposing the change (Lenz's Law), producing a drag force that resists the magnet's motion.

    • This drag force acts regardless of the magnet's orientation (North or South pole down).

<ol><li><p class="ds-markdown-paragraph"><strong>Eddy Currents and Lenz's Law</strong>:</p><ul><li><p class="ds-markdown-paragraph">When a magnet moves through a copper pipe, it induces <strong>eddy currents</strong> in the pipe.</p></li><li><p class="ds-markdown-paragraph">These currents create a <strong>magnetic field opposing the change</strong> (Lenz's Law), producing a <strong>drag force</strong> that resists the magnet's motion.</p></li><li><p class="ds-markdown-paragraph">This drag force acts <strong>regardless of the magnet's orientation</strong> (North or South pole down).</p></li></ul></li></ol><p></p>
85
New cards
term image
knowt flashcard image
86
New cards
term image
knowt flashcard image
87
New cards
term image
knowt flashcard image
88
New cards
term image
knowt flashcard image
89
New cards
<p>6 mark </p>

6 mark

knowt flashcard image
90
New cards
term image
knowt flashcard image
91
New cards
term image

B

the length of the rod will appear to contract. the factor by which it contracts is initially small, with the contracted length varying only slightly from the rest length, but increases as the speed approaches c.

92
New cards
term image

A

satellites have a lower speed and hence a lower KE at higher orbital radii

Potenial energy is greater at larger radii

93
New cards
term image

D

As the conductor rotates, all the charges in it undergo circular motion with their instantaneous velocity being tangential to the circle.

Apply the right hand palm rule, we find that positive charges always experience a force towards P, and negative charges always experience a force towards Q. This leads to a consistent emf along the length of the conductor

94
New cards
term image

D

<p>D</p>
95
New cards
term image
knowt flashcard image
96
New cards
term image
knowt flashcard image
97
New cards
term image
knowt flashcard image
98
New cards
term image
knowt flashcard image
99
New cards
term image

b

<p>b</p>
100
New cards
term image
knowt flashcard image