Wiskunde module 06 (4de)

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23 Terms

1
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co(beeldpunt A)

(cos α, sin α)

2
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sin α

3
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cos α

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4
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α=0°

(1,0)

cos α = 1

sin α = 0

tan α = 0

cot α = ∉ℝ

5
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α=90°

(0,1)

cos α = 0

sin α = 1

tan α = ∉ℝ

cot α = 0

6
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α=180°

(-1,0)

cos α = -1

sin α = 0

tan α = 0

cot α = ∉ℝ

7
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α=270°

(0,-1)

cos α = 0

sin α = -1

tan α = ∉ℝ

cot α = 0

8
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α=360°

(1,0)

cos α = 1

sin α = 0

tan α = 0

cot α = ∉ℝ

9
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α ligt in eerste kwartaal I

cos α = +

sin α = +

tan α = +

cot α = +

<p>cos α = +</p><p>sin α = +</p><p>tan α = +</p><p>cot α = +</p>
10
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α ligt in tweede kwartaal II

cos α = -

sin α = +

tan α = -

cot α = -

<p>cos α = -</p><p>sin α = +</p><p>tan α = -</p><p>cot α = -</p>
11
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α ligt in derde kwartaal III

cos α = -

sin α = -

tan α = +

cot α = +

<p>cos α = -</p><p>sin α = -</p><p>tan α = +</p><p>cot α = +</p>
12
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α ligt in vierde kwartaal IV

cos α = +

sin α = -

tan α = -

cot α = -

<p>cos α = +</p><p>sin α = -</p><p>tan α = -</p><p>cot α = -</p>
13
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co snijpunt raaklijn x=1 met het tweede been van de georiënteerde hoek α

co(K)=(1, tan α)

<p>co(K)=(1, tan α)</p>
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co snijpunt raaklijn y=1 met het tweede been van de georiënteerde hoek α

co(L)=(cot α, 1)

<p>co(L)=(cot α, 1)</p>
15
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rico van rechte OA

tan α

16
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grondformule goniometrie

cos2 α + sin2 α = 1

17
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gelijkwaardige hoeken

α + k *360°

sin: sin α

cos: cos α

tan: tan α

cot: cot α

18
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tegengestelde hoeken

sin: - sin α

cos: cos α

tan: - tan α

cot: - cot α

19
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supplementaire hoeken

180° - α

sin: sin α

cos: - cos α

tan: - tan α

cot: - cot α

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antisupplementaire hoeken

180° + α

sin: - sin α

cos: - cos α

tan: tan α

cot: cot α

21
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complementaire hoeken

90° - α

sin: cos α

cos: sin α

tan: cot α

cot: tan α

22
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anticomplementaire hoeken

90° + α

sin: cos α

cos: - sin α

tan: - cot α

cot: - tan α

23
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