8.2 - Transfer of genetic information

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Last updated 8:16 PM on 3/20/26
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21 Terms

1
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What is the definition of genotype & phenotype?

  • Genotype: the combination of alleles an organism possesses

  • Phenotype: the observable characteristics of an individual, determined by both genotype & environment

2
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What is an allele?

Different forms of a particular gene, found at the same locus (position) on a chromosome

<p>Different forms of a particular gene, found at the same locus (position) on a chromosome </p>
3
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What is the definition of dominance & recessive?

  • Dominance: a trait which is present if an individual has at least one copy of the allele

  • Recessive: a trait which is only present when an individual has two copies of the allele & can be masked by a dominant allele

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What is the definition of codominance & multiple alleles?

  • Codominance: two dominant alleles for a gene in a heterozygous organism equally contribute to the phenotype

  • Multiple alleles: a gene with more than two alleles which can code for a characteristic

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What is the definition of homozygote & heterozygote?

  • Homozygote: an organism which has two of the same versions of a gene (i.e. both alleles are dominant or recessive)

  • Heterozygote: an organism which has two different versions of the same gene (i.e. one allele is dominant, the other is recessive)

6
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Draw a genetic cross diagram for two heterozygous parents with blue eyes & determine the offspring’s ratio:

  • (B) = blue allele

  • (b) = brown allele

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7
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What is a pedigree diagram?

Can be used to trace the pattern of inheritance of a specific trait through generations of a family. They can provide information, such as:

  • whether a trait is caused by a dominant or recessive allele

  • whether a trait is more likely to be inherited by males or females

  • the genotype of individuals in the family

  • the probability that an individual in the family will inherit a trait

<p>Can be used to trace the pattern of inheritance of a specific trait through generations of a family. They can provide information, such as:</p><ul><li><p>whether a trait is caused by a dominant or recessive allele</p></li><li><p>whether a trait is more likely to be inherited by males or females</p></li><li><p>the genotype of individuals in the family</p></li><li><p>the probability that an individual in the family will inherit a trait </p></li></ul><p></p>
8
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The pedigree diagram traces the inheritance of albinism through several generations. (A) = normal allele; (a) = albinism allele

Using the pedigree chart, deduce & explain the following:

  1. the type of allele that causes albinism

  2. the genotype of individuals 9 & 7

  3. the possible genotypes of 10 & 11

Question 1:

  • Albinism is caused by a recessive allele

  • Person number 9 is an affected individual, despite parent 6 & 7 being unaffected

  • 6 & 7 must both be carriers of the recessive allele & 9 has inherited one recessive allele from each parent

Question 2:

  • The genotype of person 9 must be homozygous recessive (aa) & the genotype of 7 must be heterozygous (Aa)

  • Person 9 is a affected individual with albinism; as this is determined by the recessive allele, they must have two copies of the albinism allele

  • Person 7 must be heterozygous, as he does not have albinism but has passed on the recessive allele to person 9

Question 3:

  • The possible genotypes of 10 & 11 are heterozygous (Aa) or homozygous dominant (AA)

  • They are both unaffected individuals, so must possess at least one dominant allele (A), however, it is possible they each might have inherited a recessive alle (a) from one parent (both parents must have a copy of the recessive allele for person 9 to have albinism)

<p><strong><u>Question 1:</u></strong></p><ul><li><p>Albinism is caused by a recessive allele</p></li><li><p>Person number 9 is an affected individual, despite parent 6 &amp; 7 being unaffected</p></li><li><p>6 &amp; 7 must both be carriers of the recessive allele &amp; 9 has inherited one recessive allele from each parent</p></li></ul><p><strong><u>Question 2:</u></strong></p><ul><li><p>The genotype of person 9 must be homozygous recessive (aa) &amp; the genotype of 7 must be heterozygous (Aa)</p></li><li><p>Person 9 is a affected individual with albinism; as this is determined by the recessive allele, they must have two copies of the albinism allele</p></li><li><p>Person 7 must be heterozygous, as he does not have albinism but has passed on the recessive allele to person 9</p></li></ul><p><strong><u>Question 3:</u></strong></p><ul><li><p>The possible genotypes of 10 &amp; 11 are heterozygous (Aa) or homozygous dominant (AA)</p></li><li><p>They are both unaffected individuals, so must possess at least one dominant allele (A), however, it is possible they each might have inherited a recessive alle (a) from one parent (both parents must have a copy of the recessive allele for person 9 to have albinism) </p></li></ul><p></p>
9
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How are non-interacting, unlinked genes inherited?

Can be monohybrid or dihybrid:

  • monohybrid = a phenotypic characteristic is controlled by a single gene

  • dihybrid = two phenotypic characteristics are controlled by two different genes present on two different chromosomes

10
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What is meant by autosomal linkage?

Two or more genes are located on the same (non-sex) chromosome:

  • in this case, only one homologous pair is needed for all four alleles to be present

  • for genes that aren’t linked, two homologous pairs are needed

11
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What is an example of autosomal linkage?

Drosophila (fruit flies):

  • colour & wing length are autosomally linked, meaning they are inherited pairs

12
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Explain why are autosomally linked genes are inherited in pairs, referring to meiosis

  • Genes on the same chromosome, particularly those closest together, are unlikely to undergo recombination (i.e. independent assortment & crossing over) during meiosis

  • Therefore, they are inherited as if they were the same gene

13
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What is meant by sex-linkage & give an example?

An allele is located on one of the sex chromosomes, meaning its expression depends on the sex of the individual (e.g. haemophilia)

14
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Why are males more likely to express a recessive sex-linked allele than females?

  • Most sex-linked alleles are located on the X chromosome

  • Therefore, males only get one copy of the allele (i.e. XY), so will express this characteristic even if it’s recessive

  • Since females get two alleles (i.e. XX), this is less likely

15
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What is the chi-squared test?

A statistical test to find out whether the difference between observed & expected data is due to chance or a real effect

16
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What are the key ideas for the chi-squared test?

  • Observed (O): what you counted for each phenotype/class

  • Expected (E): what you should get from the genetic ratio, scaled to your total

  • X2 compares O & E across categories → smaller X2 usually means differences could be due to chance

  • Degrees of freedom (df) = number of categories - 1

  • Decision rule at p= 0.05

    • if X2 is less than critical value → accept

    • if X2 is greater than or equal to the critical value → reject

17
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What is the formula for the chi-squared test?

(apply to each category, then sum):

<p>(apply to each category, then sum):</p><p></p>
18
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What is the step-by-step method for chi-squared?

  1. State the genetic hypothesis & its expected ratio

  2. Find expected counts: multiply each ratio fraction by the total

  3. Compute (O - E)2 / E for each category & add them to get total X2

  4. Work out degrees of freedom: df = number of categories - 1

  5. Use the critical values table (usually p = 0.05) to decide accept/reject

<ol><li><p>State the genetic hypothesis &amp; its expected ratio</p></li><li><p>Find expected counts: multiply each ratio fraction by the total</p></li><li><p>Compute (O - E)<sup>2</sup> / E for each category &amp; add them to get total X<sup>2</sup></p></li><li><p>Work out degrees of freedom: df = number of categories - 1</p></li><li><p>Use the critical values table (usually p = 0.05) to decide accept/reject </p></li></ol><p></p>
19
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Answer this chi-squared question:

Monohybrid 3:1 expected. Observed in 200: 140 dominant, 60 recessive. Test at p = 0.05

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20
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Answer this chi-squared question:

Dihybrid 9:3:3:1 expected. Observed in 256: 150, 60, 30, 16. Test fit at p = 0.05

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21
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Answer this chi-squared question:

1:2:1 genotype ratio expected in an F2 (e.g. AA:Aa:aa). Observed in 160: 30AA, 100Aa, 30aa. Test at p = 0.05

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