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Chapter 9: Infinite Series
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nth term test
condition(s) of convergence: N/A
condition(s) of divergence: the limit as n approaches infinity of the sequence (an) is not equal to 0
this test cannot be used to show convergence
geometric series test
condition(s) of convergence: 0 < |r| < 1
condition(s) of divergence: |r| >= 1
sum of the series: S = a/(1 - r)
telescoping series test
condition(s) of convergence: the limit as n approaches infinity of the sequence (an) is equal to L
condition(s) of divergence: N/A
sum of the series: S = a1 - L
p-series test
condition(s) of convergence: p > 1
condition(s) of divergence: 0 < p <= 1
alternating series test
condition(s) of convergence: the series must be alternating AND 0 < an + 1 <= an AND the limit as n approaches infinity of the sequence (an) is equal to 0
condition(s) of divergence: N/A
remainder: |Rn| <= an+1
integral test
condition(s) of convergence: the integral from 1 to infinity of f(x)dx converges
condition(s) of divergence: the integral from 1 to infinity of f(x)dx diverges
note: must also meet the standards of an = f(n) = f(x) being positive AND continuous
remainder: 0 < Rn < the integral from n to infinity of f(x)dx
carreon note: his least favorite because it’s really complicated
root test
condition(s) of convergence: the limit as n approaches infinity of the nth-root of the absolute value of the sequence (|an|) is less than 1
condition(s) of divergence: the limit as n approaches infinity of the nth-root of the absolute value of the sequence (|an|) is greater than 1 (or = infinity)
inconclusive when the limit as n approaches infinity of the nth-root of the absolute value of the sequence (|an|) is equal to 1
carreon note: only use this when the entire series it raised to the nth power
ratio test
condition(s) of absolute convergence: the limit as n approaches infinity of the absolute value of the following term over the previous term (|an + 1/an|) is less than 1
condition(s) of divergence: the limit as n approaches infinity of the absolute value of the following term over the previous term (|an + 1/an|) is greater than 1
inconclusive when the limit as n approaches infinity of the absolute value of the following term over the previous term (|an + 1/an|) is equal to 1
carreon note: if the series contains a factorial, use this test
direct comparison test
condition(s) of convergence: 0 < an <= bn AND the infinite series of bn converges
condition(s) of divergence: 0 < bn <= an AND the infinite series of bn diverges
limit comparison test
condition(s) of convergence: the limit as n approaches infinity of an/bn is equal to L AND the infinite series of bn converges
condition(s) of divergence: the limit as n approaches infinity of an/bn is equal to L AND the infinite series of bn diverges
note: L must be positive and finite
carreon note: his favorite (as opposed to its counterpart) because it has fewer steps