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Alkanes
saturated hydrocarbons containing single covalent bonds, C-C and C-H bonds in alkane molecules as o-bonds
General formula Cn H2n+2
Sigma bonds
formed from the overlap of orbitals directly between the bonding atoms); free rotation of the o-bond, sigma bonds can freely rotate
explanation of the tetrahedral shape and bond angle around each carbon atom in alkanes in terms of electron pair repulsion
In alkane molecules each carbon atom is surrounded by 4 bonded pairs of electrons, the 4 bonded pairs repel each other equally resulting in a tetrahedral shape around each carbon atom and bond angles at 109.5
explanation of the variations in BPs of alkanes with different carbon chain length in terms of induced dipole-dipole interactions (London forces)
As the carbon chain length increases BPs increase as there are more electrons and more points of contact between molecules
The strength of london forces between molecules increases
More energy is needed to break IMFs
explanation of the variations in BPs of alkanes with different branching in terms of induced dipole-dipole interactions (London forces)
As branching in isomers of alkanes increases BPs decreases
There are fewer points of contact between the molecules
The strength of london forces between molecules decreases
Less energy is needed to break IMFs
Solubility (not in spec)
alkanes are non polar molecules and don't dissolve in polar solvents like water, they will mix however with non polar solvents
the low reactivity of alkanes with many reagents in terms of the high bond enthalpy of the σ-bonds present
The C-C and C-H sigma bonds are very strong and hard to break, these bonds have a high bond enthalpy
the low reactivity of alkanes with many reagents in terms of the very low polarity of the σ-bonds present
The C-C and C-H bonds are non polar, very low polarity as there is little difference in electronegativity between C and H atoms
complete combustion of alkanes, as used in fuels
Fuels are substances that can be burnt in oxygen to release heat energy, although alkanes are relatively unreactive many alkanes react exothermically with oxygen and make good fuels
Complete combustion
in an unlimited supply of oxygen, alkanes burn completely to produce CO2 and water in an exothermic reaction - complete combustion
the incomplete combustion of alkane fuels in a limited supply of oxygen
in a limited supply of oxygen incomplete combustion occurs, the hydrogen in the hydrocarbon still forms water , the carbon only undergoes partial oxidation to form carbon monoxide, unburnt carbon particles can be released as carbon particles (soot)
resulting potential dangers from CO
Carbon monoxide is a toxic gas that binds to haemoglobin in red blood cells preventing haemoglobin from carrying oxygen around the body, CO is difficult to detect as it is colourless and odourless
the reaction of alkanes with chlorine and bromine by radical substitution using ultraviolet radiation
Methane reacts with chlorine in the presence of of UV radiation by radical substitution, overall reaction: CH4 + Cl2 —> CH3Cl + HCl
including a mechanism involving homolytic fission and radical reactions in terms of initiation, propagation and termination
the radical substitution mechanism proceeds by 3 steps initiation, propagation, termination
Initiation
UV provides energy for homolytic fission of chlorine molecules producing highly reactive chlorine radicals (Cl•) , in imitation step radicals are made
Cl2 —> 2Cl •
Propagation
proceeds by two reactions producing the HCl and CH3Cl products, in propagation step radicals react with molecules to form new molecules and radicals
Chlorine radicals react with methane to form HCl and methyl radicals (CH3•)
Methyl radicals react with chlorine to form CH3Cl and
Summary of propagation
Radicals are being consumed then being regenerated, propagation can carry on as a chain reaction, provided that there is a constant supply of reactants CH4 and Cl2 and a supply of UV, in the first reaction Cl• reacts and CH3• forms, if you add equations for the two propagation reactions you get overall equation for the reaction
Termination
in each termination step two radicals react together to form a new molecule this happens naturally if two radicals collide and react , reaction then stops as there is no longer a constant supply of radicals, there are 3 possible termination reactions involving Cl• and CH3• radicals,
3 equations
Cl• + Cl• —> Cl2
•CH3 + Cl• —> CH3Cl
•CH3 + •CH3 —> C2H6
the limitations of radical substitution in organic synthesis by the formation of a mixture of organic products, in terms of further substitution and reactions at different positions in a carbon chains
Number 1- limitation in organic synthesis because a large mixture of the products can be formed
limitation 2
Further substitution- the CH3Cl product still contains hydrogen atoms and these hydrogen atoms can be replaced by further substitution with chlorine to produce a mixture of other products
Limitation 3
Formation of structural isomers: for alkanes with a chain of 3 or more carbon atoms substitution can take place at different positions along the carbon chain giving a mixture of structural isomers
EQ
Explain why the initiation step is an example of homolytic fission
The breaking of a Br-Br bond forms two radicals
The breaking of a Br-Br bond one electron from the bond pair goes to each atom
Explain the potential danger of incomplete combustion
Carbon monoxide gas is toxic
Determining whether the portable heater containing 600g of butane HC and consumes 5000 cm*3 of O2 at RTP is safe to use
Write out the equation for complete combustion of butane to determine how many moles needed of butane and oxygen for complete combustion to happen. Calculate moles needed of oxygen using molar gas vol and that and if the moles of oxygen needed is smaller than the moles of oxygen present: incomplete combustion will take place, it is not safe to use