Untitled

Flashcards covering projectile motion problems, including range, time of flight, velocity vectors, and angle of projection.

How do you calculate the maximum horizontal range of a projectile?

The maximum horizontal range is found when the projection angle is 45 degrees. Use the formula R = (v^2 * sin(2*theta)) / g, where v = 39.2 m/s and g is the acceleration due to gravity (approximately 9.8 m/s^2).

How do you determine time of flight, horizontal range, and max height given initial velocity and angle of projection?

First, determine the initial vertical and horizontal velocity components. Then, use kinematic equations to find the time of flight, horizontal range, and maximum height.

A ball is thrown with 5 m/s at an angle of projection 37°. What are the initial and final velocities in vector form?

u = 4î + 3ĵ; v = 4î - 3ĵ

A ball is thrown with 50 m/s at an angle of projection 37°. What is the vertical velocity and speed after 2s?

Vertical velocity vector: 40ĵ + 10ĵ; Speed: √40² + 10²

A ball is thrown with 50 m/s at an angle of projection 37°. What is the displacement vector and displacement after 2s?

Displacement vector: 80î + 40ĵ; Displacement: √80² + 40²

For projectile motion from ground to ground, if the maximum height (H) equals the horizontal range (R), what is the angle of projection?

θ = tan⁻¹(4)

For projectile motion from ground to ground, given a maximum height of 30√3 m and a horizontal range of 120 m, what are the initial velocity and angle of projection?

θ = 60° and u = 37.2 m/s