Nucleophilic substitution
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7 Terms
Explain why J is a weaker base than K
lone pair on N
In J spread delocalised into ring
less available for donation in J
which statement is not correct
using an excess of bromoethane will prevent further reaction to form a mixture of amine products
one change to the reaction conditions that would increase the yield
decreased temperature or cold
less concentrated or dilute KOH
water as a solvent
one condition necessary for a high yield of product
elimination
KOH or NaOH
high temperature
concentrated
Alcohol as a solvent
write an equation for the reaction of NaBr with H3PO4 to produce HBr and Na3PO4 only
identify two toxic gases that are formed together with HBr when NaBr reacts with concentrated H2SO4
state the role of H2SO4 in the formation of these two toxic gases
3NaBr + H3PO4 —> 3HBr + Na3PO4
SO2 and Br2 identified
Concentrated sulfuric acid is an oxidising agent ; oxidises the Br- or NaBr or HBr
is an electron acceptor
elimination conditions necessary
elimination
hot ; ethanol
KOH or NaOH
high temperature ; concentrated ; ethanol solvent
heat under reflux
secondary alcohol condition
cold
dilute KOH
water as a solvent