(a/b)>0 when
signs of a and b are the same
|a|=b when
a=b or -a=b
|a|>b when
a>b or a<-b
|a|<b when
-b<a<b
|a| can be rewritten as
a, x≥0
-a, x<0
√(x²)
|x| or ±x
f(x)= |x-a|
x-a, x≥a
-(x-a), x<a
a³+b³
(a+b)(a²-ab+b²)
a³-b³
(a-b)(a²+ab+b²)
the slopes of 2 parallel lines are
equal
the slopes of 2 normal lines (perpendicular) are
negative reciprocals
the equation of a line with slope m passing through (a,b) is
y-b=m(x-a)
the equation of a line with slope m and y-intercept b is
y=mx+b
the distance between 2 points (a,b) and (c,d) is
√((a-c)²+(b-d)²)
the restriction on the domain of (a/b) is
b≠0
the restriction on the domain of √(x) is
x≥0
the restriction on the domain of ln(x) is
x>0
a function is even if
symmetric to y-axis, or when the point (a,b) is on the graph, so is the point (-a,b), or f(-x)=f(x)
a function is odd if
symmetric to origin, or when the point (a,b) is on the graph, so is the point (-a,-b), or f(-x)=-f(x)
sin(2x)=
2sinxcosx
sinxcosx=
(1/2)sin(2x)
cos(2x)=
1-2sin²x
2cos²x-1
cos²x-sin²x
the pythagorean identities are
sin²x+cos²x=1
tan²x+1=sec²x
cot²x+1=csc²x
the quotient identities are
tanx=(sinx/cosx)
cotx=(cosx/sinx)
the reciprocal identities are
cscx=(1/sinx)
secx=(1/cosx)
cotx=(1/tanx)
when substitution yields (0/0) in a limit, you should try
factoring, expanding, common denominator, multiply by the conjugate, one of the 2 known trig identities, L’Hopital’s rule
in order to approach a limit from the right of a point c, write
lim
x→c⁺
in order to approach a limit from the left of a point c, write
lim
x→c⁻
limits fail to exist when
the function approaches a different value from the left and right, the function is unbounded (approaches +∞ or -∞), or the function oscillates
lim 1/(x-a) =
x→a⁺
+∞
lim 1/(x-a) =
x→a⁻
-∞
(a constant)/(a very small number)
+∞ or -∞
vertical asymptotes occur when
the denominator equals 0, but the numerator is not equal to 0
holes in a graph occur when
both the numerator and denominator are equal to 0 and there is not a vertical asymptote
lim (sinx/x) =
x→0
1
lim (sinx/x) =
x→∞
0
lim (1-cosx)/x =
x→0
0
lim {[f(x)]²}
x→c
{lim [f(x)]}²
x→c
lim {f[g(x)]}
x→c
f {lim [g(x)]}
x→c
0 * (nonzero/0) is
not equal to zero; simplify to find the limit
horizontal asymptotes occur when
lim f(x) = L ; the asymptote is y=L
x→±∞
If f(x)= P(x)/Q(x), with P(x) and Q(x) as polynomial functions, the possible asymptotes are
HA: y=0, if the degree of numerator is less than the degree of denominator
HA: y=ratio of leading coefficients, if the numerator and denominator have the same degree
OA: y=quotient after long division
the 3 conditions for continuity are
lim f(x) = lim f(x)
x→c⁻ x→c⁺
f(c) is defined
lim f(x) = f(c)
x→c
the Squeeze Theorem for a limit says that
if f(x)≤g(x)≤h(x), and limx→c f(x)= L= limx→c h(x), then limx→c g(x)=L.
the Intermediate Value Theorem states
If f(x) is continuous on the closed interval [a,b] and k is between f(a) and f(b), then there exists at least one number c in [a,b] such that f(c)=k
indeterminate forms
0/0
∞/∞
∞-∞ or (-∞)-(-∞) or ∞+(-∞);
1^∞ or 1^-∞
0^0
∞^0 or (-∞)^0
0*∞ or 0*(-∞)
not indetererminate
∞+∞=∞
(-∞)+(-∞)=-∞
0/∞ =0
a*∞=∞
a/∞ = 0
∞/0 [check vertical asymptotes]