Organic chemistry reactions

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Alkane combustion reaction

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72 Terms

1

Alkane combustion reaction

Complete : results in CO2 forming

Incomplete results in CO or C forming

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2

What causes free radical substitution of alkanes

UV radiation

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3

Define homolytic fission

Homolytic fission is a type of chemical bond cleavage in which a covalent bond breaks, and each atom retains one of the shared electrons. This results in the formation of two free radicals, each with an unpaired electron.

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4

Define free radical

A free radical is an atom, molecule, or ion that contains an unpaired electron. It is highly reactive as they are unstable.

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5

Free radical substitution steps

Initiation: photochemical homolytic fission of the bond between two halogen atoms due to incident UV radiation.

Propogation: Free radical + Molecule

Termination: Free radical + Free radical

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6

Why are alkenes reactive

  • Pi bond is weaker than sigma bond

  • double bond is electron dense

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7

Alkene addition reaction types

  • Halogenation

  • Hydrohalogenation

  • Hydrogenation

  • Hydration

  • Polymerisation

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8

Halogenation reaction + condition

no condition

<p>no condition</p>
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9

Hydrohalogenation reaction + condition

Heat

<p>Heat</p>
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10

Hydrogenation reaction + condition

150°C + Ni

<p>150<span>°C + Ni </span></p>
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11

Hydration reaction + condition

Concentrated sulfuric acid + heat

<p>Concentrated sulfuric acid + heat</p>
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12

Polymerisation reaction + condition

High temp + pressure + catalyst

<p>High temp + pressure + catalyst</p>
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13

Combustion of alcohols…

completely and selectively oxidises the carbon atom attached to the -OH group

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14

Alcohol oxidation catalyst and colour change

KMnO4 / H+ (aq) + heat

Purple → Clear

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15

Primary alcohol oxidation reaction

Primary Alcohol → Aldehyde → Carboxylic acid

note: You don’t need to know the intermediate step!

<p>Primary Alcohol → Aldehyde → Carboxylic acid</p><p></p><p>note:<strong> You don’t need to know the intermediate step!</strong></p>
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16

Secondary alcohol oxidation

Alcohol → Ketone

<p>Alcohol → Ketone</p>
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17

Tertiary alcohol oxidation

resistant to oxidation

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18

Esterification reaction + catalysts

Alcohols react with carboxylic acid to form esters in a condensation reaction.

Condition: Heat + conc. H2SO4

<p>Alcohols react with carboxylic acid to form esters in a condensation reaction.</p><p>Condition: Heat + conc. H2SO4</p>
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19

conditions for sigma bonds

  • two S-orbitals

  • one S-orbital and P-orbitals

  • Two P- orbitals in the same axis

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20

Pi bonds

  • not as strong as sigma bonds

  • overlap of Py and Pz orbitals lengthways

  • occurs when two atoms come close to each other

  • double / triple bonds are electron dense

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21

Define stereoisomers

A compound with the same structural formula, but arranged differently in space

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22

Define cis-trans isomer

When two compounds have the same structural formula, but groups are arranged differently around a double bond or ring

<p>When two compounds have the same structural formula, but groups are arranged differently around a <strong>double bond or ring</strong></p>
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23

Why are cis-trans isomers configurational and not conformational?

The double bond or ring restricts the rotation

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24
<p>Which cis-trans isomer has a higher boiling point and why?</p>

Which cis-trans isomer has a higher boiling point and why?

Cis-ethene, because of the assymetrical distribution of charge forming dipoles, meaning it has both LDF and dipole-dipole intermolecular forces.

Trans-ethene on the other hand is symmetrical in distribution of charge and hence is a non-polar molecule, and only has weaker LDF.

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25

How do you determine priority in naming cis-trans isomers

higher molecular mass = higher priority

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26

E/Z naming system

Cis = Z

Trans = E

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27

What is needed to exhibit optical isomerism

There must be four different groups attached to a Carbon ‘centre’

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28

What type of reaction is esterification

Condensation

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29

Define Chiral

non-superimposable mirror image (assymetric)

<p>non-superimposable mirror image (assymetric)</p>
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30

Define enantiomer

one of a pair of optical isomers, which are mirror images of each other

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31

Define racemic mixture

an equimolar mixture of two enantiomers (mirror pair) of chiral compounds

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32

Plane polarised light

light that vibrates in one plane only, radiation can be polarised at different rotations depending on which enantiomer it passed through in the pair

<p>light that vibrates in one plane only, radiation can be polarised at different rotations depending on which enantiomer it passed through in the pair</p>
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33

Define optically active

optically active means the compound is capable of polarising the plane of light

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34

Physical and chemical properties of enantiomers

Physical: identical except rotation of plane polarisation

Chemical: Identical for reactions with compounds which are not optically active. Enantiomers may react differently with optically active compounds.

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35

Diastereomers

  • cis-trans whilst exhibiting optical isomerism

  • not mirror images

  • can have multiple chiral centres

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36

Conformational isomers

  • rapidly interconverts between staggered and eclipsed conformation at room temperature due to low energy difference

  • converts via rotation about the single bond

<ul><li><p>rapidly interconverts between staggered and eclipsed conformation at room temperature due to low energy difference</p></li><li><p>converts via rotation about the single bond</p></li></ul>
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37

Types of nucleophilic substitution and conditions

Primary halogenoalkanes → Sn2 reaction

Tertiary halogenoalkanes → Sn1

Secondary halogenoalkanes → Sn1 + Sn2 mix

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38

Draw out an Sn2 reaction

if its chiral it inverts like an umbrella

<p>if its chiral it inverts like an umbrella</p>
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39

What does bimolecular and unimolecular reaction mean for the rate

Bimolecular - two species are involved in the rate determining step.

Unimolecular - one species involved

Sn2 reactions are bimolecular as the nucleophile and the halogen move in the same step. So the concentration of both species matters - Rate = k[halogenoalkane][nucleophile]

Sn1 is not because only the concentration of the initial species matters. Rate = k[halogenoalkane]

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40

Define steric effect

how readily the compounds can be substituted in regards to ‘space’

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41

energy level diagrams of Sn1 and Sn2 reactions

knowt flashcard image
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42

Define heterolytic fission

Covalent bond breaks, electron pair goes to the same side

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43

Draw out an Sn1 reaction

REFER TO HETEROLYTIC FISSION WHEN EXPLAINING

<p>REFER TO <strong>HETEROLYTIC FISSION</strong> WHEN EXPLAINING</p>
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44

What affects the rate of nucleophilic substitution

  • structure

  • halogen

  • nucleophile

  • solvent

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45

How does struture affect rate of nucleophilic substitution

Sn2: steric effects (space)

Sn1: positive inductive effects stabilises carbocation

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46

How does halogen affect rate of nucleophilic substitution

R-I > R-Br > R-Cl > R-F

higher atomic mass = faster rate of reaction

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47

how does nucleophile affect rate of nucleophilic substitution

Sn2: more negative = faster reaction. e.g OH- > H2O

Sn1: no effect because it is not in the Rate Determining Step (RDS)

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48

What is a polar protic and polar aprotic solvent

Protic - can participate in H-bonding (e.g. water)

Aprotic - can’t participate in H-bonging (e.g. Propanone)

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49

How does solvent affect rate of nucleophilic substitution

  • Sn1 favoured by protic polar - as it is a good ionizing solvent and thus stabilises the carbocation

  • Sn2 favoured by aprotic polar - as it is not good at solvating the nucleophile and thus it’s easier to attack the nucleus

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50

Why do alkenes undergo electrophilic addition

  • 120 degree bond angle

  • double bond is electron dense, therefore attractive to electrophiles

<ul><li><p>120 degree bond angle</p></li><li><p>double bond is electron dense, therefore attractive to electrophiles</p></li></ul>
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51

Draw the ethene + bromine mechanism and explain it

  • bromine is polarised by electron rich double bond

  • Br2 splits forming Br+ and Br-

  • Br+ (electrophile) attacks double bond, attaching to it (slow/RDS)

  • unstable carbocation reacts with Br- (fast)

<ul><li><p>bromine is polarised by electron rich double bond</p></li><li><p>Br2 splits forming Br+ and Br-</p></li><li><p>Br+ (electrophile) attacks double bond, attaching to it (slow/RDS) </p></li><li><p>unstable carbocation reacts with Br- (fast)</p></li></ul>
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52

What is the bromine test used for

determining whether a hydrocarbon is saturated (single bonds) or unsaturated

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53

Draw out the ethene + hydrogen bromide reaction mechanism

similar to ethene + bromine mechanism

<p>similar to ethene + bromine mechanism</p>
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54

Draw out assymetric electrophilic addition and explain why it occurs

When the double bond is not in the middle, 2 different carbocation intermediates can be formed.

<p>When the double bond is not in the middle, 2 different carbocation intermediates can be formed.</p>
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55

Define positive inductive effects

  • alkyl group (alkane minus a hydrogen) can push electron density away from themselves

  • greater positive inductive effects mean the carbocation is more stable, hence mechanism (b) is preffered over (a)

<ul><li><p>alkyl group (alkane minus a hydrogen) can push electron density away from themselves</p></li><li><p>greater positive inductive effects mean the carbocation is more stable, hence mechanism (b) is preffered over (a)</p></li></ul>
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56

Markovnikov’s rule

The hydrogen will attach to the carbon that is already bonded to the greater number of hydrogens

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57

why does benzene undergo electrophilic substitution

  • simplest aromatic hydrocarbon compound (or arene)

  • Carbon to carbon bonds have a bond order of 1.5

  • delocalised structure of pi bonds around its ring

  • highly unsaturated, however doesnt behave like other alkanes

  • highly stable, more likely to undergo substitution (so as to not lose stability from delocalised pi electrons)

  • ring is electron dense, so it attracts electrophiles

  • delocalised electrons seek electrophiles, forming a new bond, losing a H → electrophilic substitution

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58

Draw out and explain the Nitration of benzene mechanism

catalyst: Conc. H2SO4 + heat

  • electron pair of benzene attracted to Nitronium as it is a strong electrophile

  • Disrupts the delocalised electron ring

  • NO2+ and hydrogen temporarily attached to unstable carbocation intermediate

  • electrons from C-H bond are used to reform the arene ring, losing the H+ and forming nitrobenzene (appears as yellow oil)

  • H+ released reacts with HSO4- to form H2SO4 again

<p>catalyst: Conc. H2SO4 + heat</p><ul><li><p>electron pair of benzene attracted to Nitronium as it is a strong electrophile</p></li><li><p>Disrupts the delocalised electron ring</p></li><li><p>NO2+ and hydrogen temporarily attached to unstable carbocation intermediate</p></li><li><p>electrons from C-H bond are used to reform the arene ring, losing the H+ and forming nitrobenzene (appears as yellow oil)</p></li><li><p>H+ released reacts with HSO4- to form H2SO4 again</p></li></ul>
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59

Reduction vs oxidation in organic chem

Most reduced: more hydrogens

Most oxidised: more oxygens

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60

Draw out Reduction reactions of carbonyl compounds

Primary and secondary alcohol oxidation can be reversed by adding reducing agents

all reactions done in acidic conditions

<p>Primary and secondary alcohol oxidation can be reversed by adding reducing agents</p><p>all reactions done in acidic conditions</p>
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61

What are the reducing agents for carbonyl compounds

  1. NaBH4 (Sodium borohydride) in aqeous or alcoholic solution, or

  2. LiAlH4 (Lithium aluminium hydride) in anhydrous conditions, e.g. dry ether followed by aqeous acid.

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62

Draw and explain the reduction of nitrobenzene reaction mech-anism

C6H5NO2 (nitrobenzene) can be reduced to C6H5NH2 (phenylamine) in a 2 step process.

  1. C6H5NO2 reacts with a mixture of Sn/Conc. HCL under heat. Acidic conditions protonate the product, phenylammonium ions (C6H5NH3+)

  2. C6H5NH3+ is reacted with NaOH to remove the H+ and form C6H5NH2

<p>C6H5NO2 (nitrobenzene) can be reduced to C6H5NH2 (phenylamine) in a 2 step process.</p><ol><li><p>C6H5NO2 reacts with a mixture of Sn/Conc. HCL under heat. Acidic conditions protonate the product, phenylammonium ions (C6H5NH3+)</p></li><li><p>C6H5NH3+ is reacted with NaOH to remove the H+ and form C6H5NH2</p></li></ol>
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63

Define synthetic routes

series of discrete steps involved in the production of organic compounds

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64

Define retro-synthesis

Working backwards from a desired target molecule

target molecule → precursor → starting materials

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65

What is an electrophile

An electrophile is an electron-deficient species that can accept electron pairs from a nucleophile. Electrophiles are lewis acids.

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66

Explain why a hydroxide is a better nucleophile than water

A hydroxide ion is a better nucleophile than water because it has a negative charge, making it more electron-rich and reactive in nucleophilic reactions. Water is less nucleophilic due to its neutral charge and lower reactivity.

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67

NaOH (aq) + R-X (nucleophilic substitution)

Rate of Sn1 > Sn2

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68

Curly arrows and fishhooks

Heterolytic fission: Curly arrows

Homolytic fission: fish hook

emphasise this on all mechanism diagrams

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69

list halogenoalkanes, alkanes, and alkenes in order of reactivity

Alkenes > Halogenoalkanes > Alkanes

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70

explain distillation and reflux and why its used for alcohols

  • Distillation: Separates components based on boiling points. Aldehyde (lower boiling point) vaporizes first.

  • Reflux: Prevents loss of volatile components by condensing vapors back into the reaction mixture.

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71

NaBH4 (sodium borhydride)

catalyst for reducing aldehydes and ketones to primary/secondary alcohols

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72

LiAlH4 (lithium aluminium hydride)

catalyst for reducing carboxylic acids

stronger than NaBH4, cannot be stopped at aldehyde stage, goes straight primary alcohol hole

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