1/21
Revision of basic formulae and concepts, useful for JEE/IAT and Boards.
Name | Mastery | Learn | Test | Matching | Spaced |
---|
No study sessions yet.
In Standard Projectile Motion, What is the formula for total time of flight?
T=\dfrac{2u_y}{g}=\dfrac{2u\sin\theta}{g}
In Standard Projectile Motion, What is the formula for maximum height reached?
H=\dfrac{u_y²}{2g}=\dfrac{u²\sin²\theta}{2g}
In Standard Projectile Motion, What is the formula for Range of flight?
R=u_x\cdot T=\dfrac{2u_xu_y}{g}=\dfrac{u²\sin2\theta}{g}
What should the angle of projection be for maximum range in standard projectile motion?
\theta=45^\circ
What is the formula for Maximum Range in Standard Projectile Motion?
R_{max}=\dfrac{u²}{g}
For same initial velocity, what is the condition for two angles of projection resulting in the same range?
\theta_1+\theta_2=90^\circ
What is the horizontal component of velocity of a projectile (showing standard projectile motion) at any time t?
v_x=u_x=u\cos\theta
What is the vertical component of velocity of a projectile (showing standard projectile motion) at any time t?
v_y=u_y-gt=u\sin\theta-gt
What is the angle made from the horizontal by a projectile (showing standard projectile motion) at any time t?
\alpha=\tan^{-1}\Big(\dfrac{v_y}{v_x}\Big)=\tan^{-1}\Big(\dfrac{y}{x}\Big)
What is the equation of trajectory for standard projectile motion? (two of them)
y=x\tan\theta-\dfrac{gx²}{2u²\cos²\theta}=x\tan\theta-\dfrac{gx²}{2u_x²}=x\tan\theta\Big(1-\dfrac{x}{R}\Big)
If equation of trajectory for a standard projection motion is given as y=ax-bx², then what is the range of the projectile motion?
R=\dfrac{a}{b}
What is the formula for height of the tower a projectile is projected from, when time of flight and initial velocity are given?
-h=u_yT-\frac12gT²=u\sin\theta\ T-\frac12gT²
What is the formula for range of projectile when it is projected from a tower, when time of flight is given?
R=u_xT=u\cos\theta\ T
When a projectile is projected horizontally from a tower, what is the formula for total time of flight?
T=\sqrt{\dfrac{2h}{g}}
When a projectile is projected horizontally from a tower, what is the formula for horizontal range of flight??
R=uT=u\sqrt{\dfrac{2h}{g}}
What is the key thing to remember when analyzing projectile motion on an inclined plane?
Both components of u will be retarded by g.
On a plain inclined at angle \theta, what is the formula for time of flight of a projectile projected at angle \alpha from the plane?
T=\dfrac{2u_y}{a_y}=\dfrac{2u\sin\alpha}{g\cos\theta}
On a plain inclined at angle \theta, what is the formula for maximum height (from the plane) of a projectile projected at angle \alpha from the plane?
H=\dfrac{u_y²}{2a_y}=\dfrac{u²\sin²\alpha}{2g\cos\theta}
On a plain inclined at angle \theta, what is the formula for Range (along the plan) of a projectile projected at angle \alpha from the plane?
R=u\cos\alpha\cdot T\pm\frac{1}{2}g\sin\theta\cdot T²
When the projectile is projected up the plane, use minus sign
When projectile is projected down the plain, use plus sign.
When a projectile is projected from a moving trolley (speed v_T at an angle \theta, What is the formula for the horizontal component of initial velocity of the projectile?
u_x=u\cos\theta+v_T
When a projectile is projected from a moving trolley (speed v_T at an angle \theta, What is the formula for the range velocity of the projectile?
R=(u\cos\theta+v_T)\cdot T
When a projectile is projected from a moving trolley (speed v_T at an angle \theta, What is the condition for maximum Range of the projectile?
\dfrac{dR}{d\theta}=0, then solve for maximisation