Chem fundamentals (unit 1)

studied byStudied by 0 people
0.0(0)
Get a hint
Hint

Matter

1 / 67

encourage image

There's no tags or description

Looks like no one added any tags here yet for you.

68 Terms

1

Matter

Physical material; anything with mass that takes up space

New cards
2

Pure substances

Matter that has a definite composition, one that does not change, and has distinct properties. They can only be separated by chemical reactions.

New cards
3

Elements

Pure substances that cannot be decomposed into simpler substances.

New cards
4

Atoms

The smallest building block of matter. Each element is composed of 1 type of atom.

Ex: C

New cards
5

Molecules

2+ atoms, can be same or different.

ex: O2, H2O

New cards
6

Compounds

Pure substances composed of 2+ different elements. They can only be separated chemically.

Ex: H2O

New cards
7

Physical properties

Can be observed without changing the identity or composition of matter. They are the result of IMFAs between structures.

ex: melting point and color

New cards
8

Intensive properties

Properties that are independent of quantity.

ex: boiling point, odor

New cards
9

Extensive properties

Properties that are dependent on quantity.

Ex: mass, volume

New cards
10

Chemical properties

Observed by destroying substance, they result from chemical reactions.

New cards
11

Mixtures

A combo of 2+ pure substances. Each substance maintains its own properties. Mixtures can be separated into its pure substances.

New cards
12

Homogeneous mixtures

Mixtures that are uniform throughout. The components are evenly distributed. They look pure but they aren’t since they aren’t chemically combined

New cards
13

Solution

Homogeneous mixture with small particles that don't scatter light.

ex: brass, copper sulfate (aq)

New cards
14

Colloid

Homogeneous mixture with large particles that scatter light.

ex: milk

New cards
15

Heterogeneous mixtures (suspensions)

Mixtures that aren't evenly distributed, you can see layers/each part

ex: wood, granite, rice pudding

New cards
16

Physical change

Changes physical appearance, not composition.

ex: ice to water is a state change

New cards
17

Chemical change

Substance changes into a different substance.

ex: heat of combustion, flammability

New cards
18

Distillation

Process that depends on the boiling points to separate mixtures.

ex: boiling NaCl and water. Water evaporates, leaving NaCl behind

New cards
19

Chromatography

Process that depends on the differing size and polarity of substances to separate mixtures.

New cards
20

Filtration

Process of pouring a mix of solids and liquid through filter paper to separate them. The liquid passes through, solid stays behind

ex: coffee

New cards
21

Dalton’s atomic theory:

  1. Each element is composed of extremely small particles (atoms)

  2. All atoms of a given element are identical to each other

    1. All O2 atoms are the same, all N2 atoms are the same

  3. Atoms of 1 element can’t be changed into atoms of different elements by chemical reactions.

    1. O2 can’t turn into N2

  4. Compounds are formed when atoms of more than 1 element chemically combine.

    1. O + N (elements)→NO (compound)

New cards
22

Law of conservation of mass:

matter isn’t created or destroyed, just rearranged

New cards
23

Law of constant composition/definite proportion:

given compounds always have same elements in the same proportion. The ratios are fixed

ex: water is always H2O, a 2:1 ratio of H to O

New cards
24

Law of multiple proportions:

compounds with different ratios of the same atoms are different

ex: H2O2 is different from H2O

New cards
25

Democritus:

made first atomic model in 400 BC

proposed that all matter is made up of atoms (small, solid, indivisible particles)

Model: ball

<p>made first atomic model in 400 BC</p><p>proposed that all matter is made up of atoms (small, solid, indivisible particles)</p><p>Model: ball</p>
New cards
26

Dalton:

determined that each element is made up of atoms, created atomic theory

model: ball

New cards
27

Thomson:

through cathode ray tube experiments, determined that there are negatively charged electrons

because electrons contribute a small fractions of atom’s mass, they are small

model: plum pudding

<p>through cathode ray tube experiments, determined that there are negatively charged electrons</p><p>because electrons contribute a small fractions of atom’s mass, they are small</p><p>model: plum pudding</p>
New cards
28

Rutherford:

discovered protons and nucleus

Most of the atom’s mass comes from dense + nucleus and most of the volume is empty space (electron cloud)

model: nuclear

<p>discovered protons and nucleus</p><p>Most of the atom’s mass comes from dense  + nucleus and most of the volume is empty space (electron cloud)</p><p>model: nuclear</p>
New cards
29

Chadwick:

through nuclear bombardment, he found the neutron

New cards
30

Beta radiation

high speed electrons with charge -1

New cards
31

Alpha radiation

charge: +2

New cards
32

Gamma radiation

high energy, no mass, no charge

New cards
33

Nucleus:

contains protons and neutrons with an overall + charge.

very small and dense (1x10^-15 m)

New cards
34

Electron cloud:

contains negatively charged electrons

almost no mass but most of atom volume (1-5 x10^-10 m)

New cards
35

Angstrom:

1x10^-10m=100pm

New cards
36

Atomic mass unit (amu)= __g

1.66054x10^-24 g

New cards
37

Proton:

1.0073amu (1amu)

+1

New cards
38

Electron:

5.486x10^-4amu (0amu)

-1,

New cards
39

Neutron:

1.0087amu (1amu)

0

New cards
40

Isotopic Notation

A= mass #

Z=atomic #

q=charge

<p>A= mass #</p><p>Z=atomic #</p><p>q=charge</p>
New cards
41

mass number

protons+neutrons

New cards
42

Isotopes:

same # protons but different # neutrons, differing mass numbers

New cards
43

atomic number

just protons, used to identify element

New cards
44

Charge in isotope notation

#protons vs electrons

New cards
45

1amu=____g

1.66054x10^-24 g

New cards
46

1g=____amu

6.02x10^23 amu

New cards
47

How to calculate atomic mass

the number from the periodic table is dependent on isotopic abundance

Σ (isotope mass)(isotope abundance)

Ex: 9/16 atoms have a mass of 70, 6/16 have a mass of 72, 1/16 have mass of 74

AM=70(9/16)+72(6/16)+74(1/16)=71amu

New cards
48

Spectrometer

  1. Get atoms into gas phase and convert them into ions (cations)

  2. When gas phase cations made, they’re accelerated towards negative grid

  3. Only a narrow beam of ions can pass

  4. Beam passes through magnet poles that deflect ions

  5. Ions separated into their masses (isotopes)

New cards
49

Mass spectroscopy:

uses spectrometer to determine the mass of an element/molecule

Provides mass of ions and relative abundance, allows us to calculate atomic mass

New cards
50

Periods:

the rows

New cards
51

Groups:

the columns

New cards
52

Molecular vs empirical formula

molecule is the actual # of atoms in a molecule while empirical is the smallest ratio

Molecular: H2O2

Empirical: HO

New cards
53

Formula weight

the sum of each atomic weight in a substance

FW of H2O: 2(1.008)+1(16)=18.016 g

New cards
54

% composition

the mass contributed by each element

% comp= #atoms of element (atomic weight) /formula weight x100

New cards
55

How to get the empirical formula from % of each element

Base the calculation on 100.g of compound. It’s easier

Determine # moles of each element for 100.g of compound

Divide each mole value by the smallest mole value to get the ratio

Multiply by the integer to get a whole number formula

New cards
56

How to get molecular formula from empirical

whole # multiple=molecular weight/empirical formula weight

Then multiply empirical formula by that multiple

New cards
57

Combustion analysis to get empirical formula

  1. Use mass of CO2 to find the amount of C in organic substance

  2. Use mass of H2O to find amount of H in organic substance

  3. If there’s oxygen in the organic, subtract Cmass and Hmass to get Omass by itself

  4. Once you have masses of each element, proceed like before, get mole substance ratios

New cards
58

Coefficients:

the relative # of molecules in a reaction

  • Ex: 2H2 +O2 →2H2O shows 2 molecules of H2 reacting with 1 molecule of O2 to form 2 molecules H2O

New cards
59

Limiting Reactant

Reactant that limits how much product is formed. Once LR runs out, the reaction stops

New cards
60

Theoretical yield:

quantity of product calculated to form (100% completion, no error)

New cards
61

Experimental yield

Quantity of product that actually formed in lab

New cards
62

Percent yield

How much product you got compared to the true amount

experimental/theoretical x100 = ___%

New cards
63

Percent error

How far off you were from the theoretical value

exp-theo/theo x 100 = ± ___%

New cards
64

Molarity

Concentration of moles/L

New cards
65

Dilution

Adding water to make a concentration lower

C₁V₁=C₂V₂

New cards
66

Titration

combining solution with unknown concentration w reagent of known concentration

New cards
67

Equivalence point:

where stoich equivalent quantities are brought together

New cards
68

Indicator

dye that changes color as passing equivalence point

New cards

Explore top notes

note Note
studied byStudied by 7 people
... ago
5.0(1)
note Note
studied byStudied by 12 people
... ago
5.0(1)
note Note
studied byStudied by 21 people
... ago
4.0(1)
note Note
studied byStudied by 32 people
... ago
5.0(1)
note Note
studied byStudied by 8 people
... ago
5.0(1)
note Note
studied byStudied by 9 people
... ago
5.0(1)
note Note
studied byStudied by 31 people
... ago
5.0(1)
note Note
studied byStudied by 357 people
... ago
5.0(5)

Explore top flashcards

flashcards Flashcard (24)
studied byStudied by 21 people
... ago
5.0(1)
flashcards Flashcard (51)
studied byStudied by 28 people
... ago
4.0(1)
flashcards Flashcard (198)
studied byStudied by 7 people
... ago
5.0(1)
flashcards Flashcard (34)
studied byStudied by 2 people
... ago
5.0(1)
flashcards Flashcard (39)
studied byStudied by 4 people
... ago
5.0(1)
flashcards Flashcard (61)
studied byStudied by 379 people
... ago
4.6(28)
flashcards Flashcard (116)
studied byStudied by 13 people
... ago
5.0(1)
flashcards Flashcard (65)
studied byStudied by 2352 people
... ago
4.6(14)
robot