Studied by 1 personNondisjunction
________ is caused by: error in homolog separation in anaphase I and sister chromatid separation in anaphase II.
Trisomy
________: three chromosomes in a gamete.
Polyploidy
________: entire extra set of chromosomes; common in plants.
Genetic map
________: an ordered list of loci along a chromosome.
Barr body
________: the inactive, condensed X chromosome.
Fruit
________ flies produce 100s of offspring, new generation every 2 weeks, only 3 autosomal and 1 sex chromosome.
Trisomy X
________: shows no difference from the normal XX.
Nondisjunction
________: gametes having one extra and one less chromosome.
wild type
the normal/most common phenotype in natural populations
mutant
the opposite of wild type
sex-linked/X-linked
genes located on sex/X chromosome
Genetic map
an ordered list of loci along a chromosome
genetic map was constructed by
Sturtevant, Morgans student
linkage map
created by associating frequencies of recombinants along the chromosomes
For a female to express a recessive sex-linked allele, she must be
homozygous recessive
hemizygous
only one locus(one X to be expressed)
X-linked recessive disorders
re-green color blindness, Duchenne muscular dystrophy, hemophilia
X-inactivation
only one of two X chromosomes are active in each cell
Barr body
the inactive, condensed X chromosome
Calico cats are only female, only male when
XXY (Klinefelters)
Nondisjunction
gametes having one extra and one less chromosome
Nondisjunction is caused by
error in homolog separation in anaphase I and sister chromatid separation in anaphase II
aneuploidy
abnormal chromosome number
trisomy
three chromosomes in a gamete
monosomy
one chromosome
polyploidy
entire extra set of chromosomes; common in plants
trisomy 21
down syndrome
Klinefelters
extra X chromosome
Jacobs syndrome
extra Y chromosome
trisomy X
shows no difference from the normal XX
Turners Syndrome
monosomy X
Cri du chat
deletion in chromosome 5
Leukemia
reciprocal translocation
Note 
Flashcard (138)