Magnetism

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Last updated 11:58 PM on 4/2/26
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17 Terms

1
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<p>Magnetic Force of a Charged Particle</p>

Magnetic Force of a Charged Particle

Fmag = |q|vBsin(θ)

2
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<p><strong><u>Right hand rule</u></strong> for <strong>F<sub>mag</sub>, v, B</strong></p>

Right hand rule for Fmag, v, B

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<p>Charged particle in magnetic field (B)</p>

Charged particle in magnetic field (B)

  • Charge spins in circles

  • Opposite charge would make Fmag in opposite direction

<ul><li><p>Charge spins in circles</p></li><li><p><strong><u>Opposite charge</u></strong> would make <strong>F<sub>mag</sub> in opposite direction</strong></p></li></ul><p></p>
4
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Can a magnetic field (B) do work on a particle?

5
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<p>Radius of particle path</p>

Radius of particle path

r = ( m v ) / ( |q| B)

  • a particle in w/ vinitial at an angle will move in a helical path

6
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<p>Magnetic Force of Current-Carrying Wire</p>

Magnetic Force of Current-Carrying Wire

Fmag = ILBsinθ

  • Fmag perpendicular to I

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<p><strong><u>Right hand rule</u></strong> for <strong>F<sub>mag</sub>, I, B</strong></p>

Right hand rule for Fmag, I, B

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<p>Two vertical sides of current-carrying wires</p>

Two vertical sides of current-carrying wires

  • right side force is going out of page, left side force is going into page

  • On vertical sides: Forces are equal in magnitude, but opposite in direction

  • Creates torque

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<p>Torque on current carrying loop</p>

Torque on current carrying loop

𝜏 = NIABsinθ

  • A = area, N = # of turns/loops

  • torque increases as # of loops increases (N), if current ( I ) increases

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<p>Direction of magnetic field due to Current carrying wire r<strong><u>ight hand rule</u></strong></p>

Direction of magnetic field due to Current carrying wire right hand rule

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11
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<p>Ampere’s Law</p>

Ampere’s Law

∑BΔL = μo Ienclosed

μo = 1.26 × 10-6

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Ampere’s Law to solve for B

B = (μoI) / (2πr)

  • 2πr is circumference

13
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<p>Currents in <strong><u>same direction</u></strong></p>

Currents in same direction

  • forces come towards each other

  • magnetic field in opposite directions (both going CW or CCW)

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<p>Currents in <strong><u>opposite direction</u></strong></p>

Currents in opposite direction

  • forces go away from each other

  • magnetic field in same directions (one going CW other going CCW)

15
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Fmag equation for two current-carrying wires

Fmag = (μoI1I2) / (2πd)

  • d = 2 * circumference

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Magnetic Field of a Current Loop / Bar Magnet (Bloop)

Bloop = (NμoI) / (2R)

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<p>Magentic Field of a solenoid (B<sub>solenoid</sub>)</p>

Magentic Field of a solenoid (Bsolenoid)

Bsolenoid = (oI) / L = μonI

  • n = # of turns / unit length (N/L)

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