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review lecture quiz

Last updated 2:03 AM on 1/23/23
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13 Terms

1
New cards
For a two-sided hypothesis test we wish to know if

A.

A population average increased

\n

B.

A population average changed

\n

C.

A population average decreased

\n

D.

Your professor is member of the population of drunken slobs

\n
\n A population average changed

\n
2
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A two sided test has

A.

Not Equal in Ho

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B.

Not Equal in Ha

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C.

Not Equal in both Ho and Ha

\n

D.

None of Above
Not Equal in Ha
3
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1. For the material on Slide 4 of Review Lecture 3, the risk that a sample average of 3.6 or less would be observed if mu is actually 3.8 is

\
A.

2\.3%

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B.

3\.6%

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C.

3\.8%

\n

D.

Not provided

\n
\n 2.3%
4
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For a two-sided hypothesis test, we would reject Ho if x-bar is

A.

Much less than the mu from Ho, only

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B.

Much more than the mu from Ho, only

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C.

Much different than the mu from Ho

\n

D.

All of the above
\n Much different than the mu from Ho
5
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For a two-sided test, the interpretation from the definition of the p-value of "as extreme or more extreme" means that the p-value is calculated using the area under the bell shaped curve...

A.

Only on the low side of the real number line

\n

B.

Only on the high side of the real number line

\n

C.

On the high and low side of the real number line

\n

D.

All of the above
On the high and low side of the real number lin
6
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The p-vlaue for a ONE sided test is (be careful)

A.

Twice the value of a two sided test

\n

B.

Half the value of a two sided test

\n

C.

The same as the value of a two sided test

\n

D.

Non of the above
B.

Half the value of a two sided tes
7
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The p-vlaue for a TWO sided test is

Twice the value of a one sided test

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Half the value of a one sided test

\n

The same as the value of a one sided test

\n

Non of the above
Twice the value of a one sided test
8
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1. If you don't know the average of the population then your best esimate is

\
A.

sigma

B.

x-bar

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C.

s

\n

D.

None of the above

\n

E.

All of the above

\n
x-bar
9
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Which of the following is true

A.

The central limit thoerem allows us to estimate the distance from xbar to mu so we can only use it for hypothesis testing

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B.

The central limit thoerem allows us to estimate the distance from xbar to mu so we can use it for hypothesis testing and confidence intervals

\n

C.

The central limit thoerem allows us to estimate the distance from xbar to mu so we can only use it for confidence intervals

\n

D.

Non of the above
\n The central limit thoerem allows us to estimate the distance from xbar to mu so we can use it for hypothesis testing and confidence intervals
10
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The form of a confidence interval is

A.

(upper estimate, lower estimate)

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B.

lower estimate )( upper estimate

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C.

(lower estimate, upper estimate)

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D.

None of the above
\n (lower estimate, upper estimate)
11
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We CANNOT use the confidence interval to evaluate a one-sided hypothesis test because

A.

For a confidence interval the location of the risk is on the upper and lower side of the real number line and the same is true for a one-sided hypothesis test

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B.

For a confidence interval the location of the risk is on the upper and lower side of the real number line and for a one-sided hypothesis test it is located on only one side of the real number line

\n

C.

None of the above

D.

All of the above
For a confidence interval the location of the risk is on the upper and lower side of the real number line and for a one-sided hypothesis test it is located on only one side of the real number line

\n
12
New cards
What are the two condition necessary to use a confidence interval to evaluate a hypothesis test question

A.

One-sided test; confidence=1-alpha for the particulars of the problem

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B.

One-sided test; confidence not =1-alpha for the particulars of the problem

\n

C.

Two-sided test; confidence=1-alpha for the particulars of the problem

\n

D.

Two-sided test; confidence not =1-alpha for the particulars of the problem

\n
\n Two-sided test; confidence=1-alpha for the particulars of the problem

\n
13
New cards

1. Testing for Ho:mu(Y)=mu(O); Ha:mu(Y) not= mu(O) is the same thing as evaluating Ho:mu(Y)-mu(O)=0; Ha:mu(Y)-mu(O) not = 0

\
A.

True

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B.

False

\n

\
\n True