simple harmonic motion

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Last updated 4:44 PM on 11/20/25
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92 Terms

1
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Period (TT) is defined as __, and its SI unit is __.

The time taken for one complete cycle of motion; seconds (s)

2
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Frequency (ff) is defined as __, and its SI unit is __.

The number of cycles per second; Hertz (Hz)

3
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The mathematical relationship between period and frequency is given by the equation __.

f=1Tf = \frac{1}{T}

4
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The Hertz (Hz) is defined as __.

One cycle per second.

5
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The maximum displacement from the equilibrium position is called __.

Amplitude (AA)

6
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A phase shift (ϕ\phi) in the context of SHM equations is used to __.

Indicate the initial angle or displacement in oscillation.

7
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The defining characteristic of Simple Harmonic Motion is that the acceleration is __.

Proportional to the displacement and directed towards the equilibrium position.

8
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For an object on a spring undergoing SHM, the two factors that only affect the period and frequency are and .

Mass (mm) of the object and spring constant (kk).

9
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In Simple Harmonic Motion, the period and frequency are __ dependent on the amplitude (AA).

Not.

10
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The force that acts on a mass attached to a spring obeys and is given by the equation .

Hooke's Law; F=kxF = -kx

11
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The generalized equation for position (x(t)x(t)) as a function of time for a simple harmonic oscillator is __.

x(t)=Aimesextcos(βt+ϕ)x(t) = A imes ext{cos}(\beta t + \phi)

12
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The relationship between angular frequency (ω\omega) and the period (TT) is given by __.

ω=2πT\omega = \frac{2\pi}{T}

13
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The equation for maximum velocity (v<em>maxv<em>{max}) in terms of amplitude (AA) and angular frequency (ω\omega) is ___.

vmax=Aωv_{max} = A \omega

14
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The equation for maximum acceleration (a<em>maxa<em>{max}) in terms of amplitude (AA) and angular frequency (ω\omega) is ___.

amax=Aω2a_{max} = A \omega^2

15
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The equations for the period (TT) and angular frequency (ω\omega) for a mass on a spring relate to the mass (mm) and force constant (kk) as follows: and .

T=2πmkT = 2\pi \sqrt{\frac{m}{k}} and ω=km\omega = \sqrt{\frac{k}{m}}

16
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The force of gravity (mgmg) affects a mass oscillating on a vertical spring by __ compared to a horizontal spring.

Adding an additional static force on the spring, which modifies the equilibrium position.

17
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The angular frequency (ω\omega) or period (TT) of a vertical spring system due to gravity, because .

Does not change; the system's motion still follows Hooke's Law and the characteristics of SHM.

18
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The two forms of energy that oscillate in an SHM system are and .

Potential energy (UU) and kinetic energy (KK).

19
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The general equation for total mechanical energy (E<em>TotalE<em>{Total}) of an SHM system is ___.

ETotal=U+KE_{Total} = U + K

20
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Without dissipative forces, the total energy of the SHM system __.

Remains constant.

21
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The equation for the potential energy (UU) stored in a spring is __, and the position generally defined as U=0U=0 is __.

U=12kx2U = \frac{1}{2} k x^2; at the equilibrium position (x=0x=0).

22
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In oscillation, the kinetic energy (KK) is maximum at __. The velocity (vv) at these points is __.

The equilibrium position; maximum velocity (vmaxv_{max}).

23
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In oscillation, the potential energy (UU) is maximum at __. The velocity (vv) at these points is __.

The maximum displacement; velocity is zero.

24
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The maximum total energy (E<em>TotalE<em>{Total}) is expressed in terms of the spring constant (kk) and amplitude (AA) as follows: ___.

ETotal=12kA2E_{Total} = \frac{1}{2} k A^2

25
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The force (FF) is related to the slope of the potential energy graph (UU vs. xx) as __.

F=dUdxF = -\frac{dU}{dx}

26
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The equation for the magnitude of the velocity (v|v|) at any position (xx) during SHM using energy conservation is __.

v=2m(ETotalU)|v| = \sqrt{\frac{2}{m}(E_{Total} - U)}

27
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In the context of the potential energy curve (UU vs. xx), a stable equilibrium point is defined as __.

A point where a small disturbance results in forces that restore the system to equilibrium.

28
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If disturbed from an unstable equilibrium point, an object __.

Will move further away from the equilibrium position.

29
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If the amplitude (AA) of a simple harmonic oscillator is decreased, the and will be affected.

Total energy decreases; maximum velocity decreases.

30
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In the energy transformation of a block-spring system from maximum positive displacement (x=+Ax=+A) to equilibrium position (x=0x=0), the potential energy and kinetic energy .

Decreases; increases.

31
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The type of motion used to model Simple Harmonic Motion (SHM) is __.

Uniform circular motion.

32
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The physical setup to demonstrate the connection between circular motion and SHM involves __, __, and __.

A peg, a disk, and a lamp.

33
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The part of the uniform circular motion that corresponds to the SHM of an oscillating block is __.

The projection of the point moving in circular motion onto the vertical axis.

34
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In this model, the disk must turn at a constant angular frequency (ω\omega) that is equal to __ from the oscillating system.

The angular frequency (ω\omega).

35
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If the disk has a radius rr, rr represents __ in the context of SHM.

The amplitude (AA) of oscillation.

36
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The equation for the position (x(t)x(t)) of the shadow as a function of time in the rotating peg model is __.

x(t)=rcos(ωt)x(t) = r \cos(\omega t)

37
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The tangential velocity of the peg around the circle for a block on the spring equals to __.

The velocity (vv) of the block.

38
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The velocity of the shadow is equal to which component of the peg's velocity is __.

The horizontal component.

39
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The equation for the velocity (vv) of the shadow (or the SHM object) as a function of time is __.

v=Aωsin(ωt)v = -A \omega \sin(\omega t)

40
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The relationship between the maximum velocity (v<em>maxv<em>{max}) of the SHM object and the radius (AA) and angular frequency (ω\omega) is given by ___.

vmax=Aωv_{max} = A \omega

41
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The equation for the acceleration (aa) of the shadow (or the SHM object) as a function of time is __.

a=Aω2cos(ωt)a = -A \omega^2 \cos(\omega t)

42
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The position equation for the shadow uses cos(ωt)\cos(\omega t) because __.

At t=0t=0, the projection starts at maximum displacement (x=+Ax=+A).

43
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An example of an object that undergoes uniform circular motion is __.

A point on the edge of a rotating wheel.

44
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If the angular speed of the rotating disk is doubled, the period will and the frequency will .

Halve; double.

45
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The two forces acting on the bob of a simple pendulum are and .

Tension in the string; gravitational force.

46
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The small angle approximation is necessary for a simple pendulum because __.

It allows the restoring force to be directly proportional to the displacement.

47
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The equation for the period (TT) of a simple pendulum is __.

T=2πLgT = 2\pi \sqrt{\frac{L}{g}}

48
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The period of a simple pendulum is independent of and .

Mass of the bob; amplitude of the swing.

49
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A simple pendulum can measure the acceleration due to gravity (gg) by __.

Measuring the period and rearranging the period equation.

50
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A physical pendulum differs from a simple pendulum by __.

Its mass is distributed and not concentrated at a point.

51
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The force of gravity effectively acts on a physical pendulum at __.

The center of mass.

52
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The equation for the period (TT) of a physical pendulum is __ in terms of its moment of inertia (II) and the distance from the pivot to the center of mass (LL).

T=2πImgLT = 2\pi \sqrt{\frac{I}{mgL}}

53
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In the physical pendulum equation, LL represents __.

The distance from the pivot point to the center of mass.

54
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The period equation for a physical pendulum reduces to the period equation for a simple pendulum by __.

Assuming that the moment of inertia simplifies under certain conditions.

55
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A torsional pendulum uses __ as a restoring force/torque.

Torsional spring force.

56
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The variable κ\kappa (kappa) is called and its SI units are .

The torsional constant; N·m/radian.

57
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The equation for the period (TT) of a torsional pendulum is __.

T=2πIκT = 2\pi \sqrt{\frac{I}{\kappa}}

58
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The period of a torsional pendulum is dependent on __.

The moment of inertia (II) of the system.

59
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The primary reason real-world oscillations seldom follow true SHM is __.

Dissipative forces such as friction and air resistance.

60
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In damped harmonic motion, the amplitude (AA) __ over time.

Decreases.

61
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Non-conservative damping forces remove energy from an oscillating system primarily by __.

Doing work against the motion.

62
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For a system with small damping, the period and frequency __ compared to those of SHM.

Change only slightly.

63
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For small velocity, the mathematical relationship for the damping force (F<em>DF<em>D) is given by ___.

FD=bvF_D = -b v, where bb is the damping constant.

64
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The differential equation for the net force on a mass undergoing damped harmonic motion is __.

md2xdt2+bdxdt+kx=0m\frac{d^2x}{dt^2} + b\frac{dx}{dt} + kx = 0

65
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The equation for the position (x(t)x(t)) of a damped harmonic oscillator is __.

x(t)=A<em>0eb2mtcos(ω</em>dt+ϕ)x(t) = A<em>0 e^{-\frac{b}{2m}t} cos(\omega</em>d t + \phi)

66
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The term A<em>0eb2mtA<em>0 e^{-\frac{b}{2m}t} represents ___ in the position equation of a damped harmonic oscillator.

The exponentially decaying amplitude over time.

67
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The equation for the angular frequency (ω\omega) of a damped harmonic oscillator is given as __.

ω=ω02(b2m)2\omega = \sqrt{\omega_0^2 - \left(\frac{b}{2m}\right)^2}

68
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The natural angular frequency (ω<em>0\omega<em>0) is defined as ___.

ω0=km\omega_0 = \sqrt{\frac{k}{m}}

69
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The three damping regimes (types of damping) are __, __, and __.

Under damped, critically damped, and over damped.

70
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For a system to be considered underdamped, the mathematical relationship between the damping constant (bb), mass (mm), and spring constant (kk) must be __.

b < 2\sqrt{mk}.

71
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The motion of an underdamped system is characterized by __.

Oscillation with gradually decreasing amplitude.

72
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The condition for a system to be critically damped is when the relationship between damping constant (bb), mass (mm), and spring constant (kk) is __.

b=2mk.b = 2\sqrt{mk}.

73
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The key characteristic of critically damped motion is __, and a common example where it is desirable is __.

The system returns to equilibrium in the least time without oscillating; car shock absorbers.

74
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The motion of an overdamped system is described as __.

Returning to equilibrium without oscillating more slowly than a critically damped system.

75
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There is a maximum value for the damping constant (bb) beyond which the angular frequency (ω\omega) becomes a complex number because __.

Excessive damping occurs, preventing oscillation.

76
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A critically damped system is often desired for car shock absorbers because __.

It brings the system back to equilibrium quickly without oscillation.

77
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Forced oscillations are defined as __.

Oscillations occurring when a periodic driving force is applied to a system.

78
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The natural frequency (ω<em>0\omega<em>0) of a system is defined as ___.

The frequency at which a system oscillates when not subjected to a driving force.

79
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The phenomenon of resonance is defined as __.

The increase in amplitude of oscillation when the driving frequency matches the natural frequency.

80
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For a system to resonate, the driving frequency (ω\omega) and the natural frequency (ω<em>0\omega<em>0) must be ___.

Equal.

81
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A real-world example of resonance is __.

A swing being pushed at the right time.

82
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The equation for the periodic driving force (F<em>dF<em>d) used in the model of forced oscillations is ___.

F<em>d=F</em>0extcos(ωt)F<em>d = F</em>0 ext{cos}(\omega t)

83
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The differential equation for the net force on a mass undergoing forced and damped harmonic motion is __.

md2xdt2+bdxdt+kx=Fdm\frac{d^2x}{dt^2} + b\frac{dx}{dt} + kx = F_d

84
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The equation for the amplitude (AA) of a forced oscillator's steady-state motion is __.

A=F<em>0/m(ω</em>02ω2)2+(bmω)2A = \frac{F<em>0/m}{\sqrt{(\omega</em>0^2 - \omega^2)^2 + (\frac{b}{m}\omega)^2}}

85
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As the driving frequency (ω\omega) approaches the natural frequency ($\omega0), the denominator in the amplitude equation ___.

Decreases, causing amplitude to increase significantly.

86
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The equation for the maximum amplitude (A<em>maxA<em>{max}) is given as ___, and the relationship between the two frequencies at this point is __.

A<em>max=F</em>0/mbmA<em>{max} = \frac{F</em>0/m}{\frac{b}{m}}; ω=ω0\omega = \omega_0.

87
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The amount of damping (bb) affects the maximum amplitude achieved at resonance by __.

Reducing the maximum amplitude as damping increases.

88
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As damping decreases, the width of the resonance curve (amplitude vs. driving frequency) __.

Narrows.

89
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The term used for the narrowness of the resonance curve is __, and this property is desirable in systems like a radio tuner because __.

Quality Factor (QQ); it allows for precise tuning to a specific frequency.

90
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The equation for the Quality Factor (QQ) is given as __ in terms of natural angular frequency ($\omega_0) and the spread of angular frequency (Δω\Delta\omega).

Q=ω0ΔωQ = \frac{\omega_0}{\Delta \omega}

91
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A singer must match the natural frequency of a crystal glass to make it shatter because __.

The glass will resonate and amplify the vibrations until it breaks.

92
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In the forced oscillation system, the motion that occurs before the system reaches its steady-state periodic motion is called __.

Transitional motion.