AP Chemistry Unit 8 Notes: Acids, Bases, Buffers, pH/pKa, and Titrations

5.0(2)
Studied by 48 people
0%Unit 8 Mastery
0%Exam Mastery
Build your Mastery score
multiple choiceAP Practice
Supplemental Materials
call kaiCall Kai
Card Sorting

1/24

Last updated 3:11 PM on 3/12/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

25 Terms

1
New cards

Brønsted–Lowry acid

A species that donates a proton (H+) in a reaction.

2
New cards

Brønsted–Lowry base

A species that accepts a proton (H+) in a reaction.

3
New cards

Conjugate acid–base pair

Two species that differ by exactly one proton; an acid forms its conjugate base after donating H+, and a base forms its conjugate acid after accepting H+.

4
New cards

Strong acid

An acid that essentially fully ionizes in water (e.g., HCl, HNO3), so [H3O+] is determined directly from concentration (after dilution/mixing).

5
New cards

Weak acid

An acid that partially ionizes in water and establishes an equilibrium (e.g., HF, CH3COOH), requiring Ka-based equilibrium calculations.

6
New cards

Acid dissociation constant (K_a)

Equilibrium constant for a weak acid in water: HA + H_2O ightleftharpoons A^{-} + H_3O^+, with K_a = \frac{[H_3O^+][A^{-}]}{[HA]} . Larger K_a means a stronger weak acid.

7
New cards

Base dissociation constant (K_b)

Equilibrium constant for a weak base in water: B + H_2O ightleftharpoons BH^+ + OH^{-}, with K_b = \frac{[BH^+][OH^-]}{[B]} . Larger K_b means a stronger weak base.

8
New cards

K_a–K_b relationship (conjugates)

For a conjugate acid–base pair HA/A^{-} at a given temperature: K_a\cdot K_b = K_w (so pK_a + pK_b = pK_w).

9
New cards

Neutralization

An acid–base reaction where acid and base react to form water and (usually) a salt; often treated as going to completion for strong acid/strong base.

10
New cards

Net ionic equation (strong acid–strong base)

The essential reaction in strong acid–strong base neutralization: H3O++OH2H2OH_3O^+ + OH^- \rightarrow 2H_2O.

11
New cards

Weaker acid/base pair favored

Acid–base equilibria tend to favor formation of the weaker acid and weaker base; for HA + B^{-} ightleftharpoons A^{-} + HB, K = \frac{K_a(HA)}{K_a(HB)}.

12
New cards

Buffer

A solution that resists pH change when small amounts of strong acid/base are added; requires a conjugate acid–base pair in comparable amounts.

13
New cards

Buffer components (HA/A−)

A common buffer is made from a weak acid (HA) and its conjugate base (A−), present in significant/comparable amounts (often from the acid plus its salt).

14
New cards

Buffer response to added strong acid

Added H_3O^+ is consumed by the base component: A^{-} + H_3O^+ ightarrow HA + H_2O, reducing the pH change.

15
New cards

Buffer response to added strong base

Added OH− is consumed by the acid component: HA + OH− → A− + H2O, reducing the pH change.

16
New cards

Henderson–Hasselbalch equation

For an HA/A− buffer: pH = pKa + log([A−]/[HA]); after adding acid/base, the ratio is often computed using moles because dilution cancels in the same total volume.

17
New cards

Half-equivalence point

In a weak acid–strong base titration, the point where half the initial HA has been converted to A−, so [A−] = [HA] and pH = pKa.

18
New cards

Buffer capacity

How much strong acid/base a buffer can absorb before pH changes significantly; increases with larger total amounts (higher concentrations) of HA and A−.

19
New cards

pH

A logarithmic measure of acidity based on hydronium: pH=log([H3O+])\text{pH} = -\log([\text{H}_3\text{O}^+]); a 1-unit change corresponds to a 10×10\times change in [H3O+][\text{H}_3\text{O}^+].

20
New cards

pOH

A logarithmic measure of basicity: pOH = −log([OH^-]); related to pH through K_w.

21
New cards

Ion-product constant of water (K_w)

At 25^{ extcirc}C, K_w = [H_3O^+][OH^-] = 1.0 imes10^{-14}, linking hydronium and hydroxide concentrations.

22
New cards

pK_w and the pH + pOH relationship

pK_w = −log(K_w) = 14.00 at 25^{ extcirc}C, so pH + pOH = 14.00 (temperature-dependent).

23
New cards

pKa

The log form of Ka: pKa = −log(Ka). Smaller pKa means a stronger acid (larger Ka).

24
New cards

Equivalence point (titration)

The point in a titration where acid and base have reacted in the exact stoichiometric ratio (moles neutralized match the reaction coefficients); not the same as endpoint.

25
New cards

Endpoint (titration)

The experimental indicator color-change point used to signal completion; it should be close to the equivalence point but is not defined by stoichiometry.