Rates of Reaction

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Last updated 2:16 PM on 5/10/25
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24 Terms

1
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Flask A = 1g Zn, 100cm3 1moldm-3 HCl at 35C

Flask B = 1g Zn, 100cm3 2moldm-3 HCl at 35C

Explain why the rate of reaction in Flasks A and B are different?

The concentration of the acid is higher in Flask B, so the frequency of collisions of acid particles with zinc is higher, resulting in a faster rate of reaction.

2
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Conc-Time graph for 1st Order Reactant

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3
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Conc-Time graph for 2nd Order Reactant

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4
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Conc-Time graph for 0th Order Reactant

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5
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Rate-Conc graph for 1st Order Reactant

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6
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Rate-Conc graph for 2nd Order Reactant

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7
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Rate-Conc graph for 0th Order Reactant

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8
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Arrhenius Equation

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9
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<p>What does each letter in the Arrhenius equation stand for?</p>

What does each letter in the Arrhenius equation stand for?

k = rate constant

A = pre-exponential factor (frequency factor)

e = base number of natural logarithms (SHIFT-ln on calculator)

Ea = Activation energy ( J mol⁻¹ )

R = Gas constant (8.314 J mol⁻¹ K⁻¹ )

T = Temperature in kelvin

10
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What's the effect on the value of k when the temperature is increased?

Increases k

More frequent collisions and more collisions have energy equal to or greater than the activation energy.

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What's the effect on the value of k when the activation energy is increased?

Decreases k

Fewer collisions have energy equal to or greater than the activation energy.

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What's the effect on the value of k when the pre-exponential factor is decreased?

Less frequent collisions

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Logarithmic Form of Arrhenius Equation

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Compare the log form of Arrhenius Equation with a straight line:

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15
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What does the gradient of the graph (m) represent?

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16
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What does the y-intercept of the graph (c) represent?

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17
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How to work out Ea from the graph?

Gradient = -Ea/RT

Ea = -Gradient × R

18
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How to calculate A?


lnk = -Ea/RT + lnA

lnA = lnk + Ea/RT

A = elnA

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Ea the subject


Ea = RT (lnA - lnk)

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A the subject


A = k * eEa/RT

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T the subject

<p></p>
22
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<p>Use the results from the student’s experiments to deduce the rate equation for this reaction. Justify your reasoning.</p>

Use the results from the student’s experiments to deduce the rate equation for this reaction. Justify your reasoning.

Straight line through origin 1st order wrt BrO3-

Between expt 1 and 2, [H+] x 2, rate x 4

Rate ∝ [H+] 2 , so 2nd order wrt H+

When [H+] constant and [BrO3-] x2 and [Br-] x 2, rate x 4

Since BrO3 - is first order, doubling [Br- ] has doubled rate, so it is 1st order wrt Br-

Rate = k [BrO3-][Br-][H+]2

23
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How to calculate rate constant (k) from a graph?

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24
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What is the rate constant (k) for this radioactive decay?

The half life is 1.25 × 109 years

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