the square of the orbital period (T) is directly proportional to the cube of the radius T^2 ∝ r^3
2
New cards
T^2 ∝ r^3 derivation step 1
when an object orbits a mass, it experiences a gravitational force towards the centre of the mass this acts as a centripetal force, due to the circular motion of orbits this means we can equate gravitational force to centripetal force mv^2/r = GMm/r^2
3
New cards
T^2 ∝ r^3 derivation step 2
rearrange the equation to make v^2 the subject v^2 = GM/r
4
New cards
T^2 ∝ r^3 derivation step 3
velocity is the rate of change of displacement this means you can find v in terms of radius (r) and orbital period (T): v = 2πr/T ——> v^2 = 4π^2r^2/T^2 (because the diameter of a circle is 2πr and the object will travel this distance in one orbital period
5
New cards
T^2 ∝ r^3 derivation step 4
substitute the equation for v^2 in terms of r and T into the original equation (from step 2) 4π^2r^2/T^2 = GM/r
6
New cards
T^2 ∝ r^3 derivation step 5
rearrange to make T^2 = 4π^2/GM x r^3
as 4π^2/GM is a constant, this shows that T^2 ∝ r^3
7
New cards
what is the total energy of an orbiting satellite made up of?
its kinetic and potential energy - it's constant
8
New cards
total energy of a satellite
kinetic energy + potential energy
9
New cards
escape velocity
the minimum velocity an object must travel at in order to escape the gravitational field at the surface of a mass