planes, cross product, and span

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29 Terms

1
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plane through p with normal vector n consists of

all points r such that r→ - p→ orthogonal to n

<p>all points r such that r→ - p→ orthogonal to n</p>
2
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vector form of plane

n→ • (r→ - p→) = 0

3
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scalar form of plane

ax + by + cz = d

4
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line can be described by a point p on line and a normal vector n orthogonal to line; line consists of all r such that

n→ • (r→ - p→) = 0 i.e. ax + by = c

5
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how to find parallel planes

find one point on each plane by moving 1 unit in direction ± n

normalize n, points are p ± normalized n

planes are n→ • ((x y z) - p1 or p2) = 0

6
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cross product

vector orthogonal to u and v (that are not parallel); u x v = (a2b3 - a3b2 | -(a1b3 - a3b1) | a1b2 - a2b1)

7
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-a x b =

b x a

8
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right hand rule

curl fingers from a to b, thumb is direction of a x b

9
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a x b = 

det ( i j k in first column | components of u in second | components of v in third)

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k (a x b) =

ka x b = a x kb

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a x (b + c) =

a x b + a x c

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(b + c) x a =

b x a + c x a

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a x a =

0

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length of cross product

||a x b|| = ||a||||b||sinθ

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direction n of cross product

n is a unit vector perpendicular to both a and b by the right hand rule

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a • (a x b) =

0

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b • (a x b) =

0

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area of a parallelogram

||a x b||

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volume of parallelepiped

area of the base || a x b|| * ||c||cosθ where θ is the angle between c and a x b and c is the vector forming slanted height thing

<p>area of the base || a x b|| * ||c||cosθ where θ is the angle between c and a x b and c is the vector forming slanted height thing</p>
20
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determinant of 3 × 3 matrix = 

|det [ a b c ]| = volume of parallelepiped

21
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span of vectors

all possible linear combos of those vectors

22
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span (a, b) =

{ ta + sb | t, s are real}

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span of two vectors is the xy-plane if

they are NOT collinear

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span of two vectors is a line if

they ARE collinear

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span of two vectors is a point if

both are zero vector

26
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plane containing a point and a line

find line’s direction vector and vector connecting given point to any point on line, then cross product is the normal vector of the plane

27
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equation through point perpendicular to a line

direction vector of line becomes normal vector of plane, then just plug in point

28
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vector parallel to plane intersection

cross product of two planes’ normal vectors

29
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better volume of a parallelepiped

|a•(b x c)|

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