Notes from Chemsheets ppt= precipitate NFR= no further reaction
[Fe(H2O)6]2+
green solution
[Cu(H2O)6]2+
blue solution
[Fe(H2O)6]3+
orange solution due to hydrolysis to [Fe(H2O)5(OH)]2+
[Al(H2O)6]3+
colourless solution
[Fe(H2O)6]2+ and NaOH
[Fe(H2O)4(OH)2]
(dark) green ppt
XS: NFR
[Cu(H2O)6]2+ and NaOH
[Cu(H2O)4(OH)2]
blue ppt
XS: NFR
[Fe(H2O)6]3+ and NaOH
[Fe(H2O)3(OH)3]
brown ppt
XS: NFR
[Al(H2O)6]3+ and NaOH
[Al(H2O)3(OH)3]
white ppt
XS: NFR
[Fe(H2O)6]2+ and NH3
[Fe(H2O)4(OH)2]
(dark) green ppt
XS: NFR
[Cu(H2O)6]2+ and NH3
[Cu(H2O)4(OH)2]
blue ppt
XS: [Cu(H2O)2(NH3)4]2+
deep blue solution
[Fe(H2O)6]3+ and NH3
[Fe(H2O)3(OH)3]
brown ppt
XS: NFR
[Al(H2O)6]3+ and NH3
[Al(H2O)3(OH)3]
white ppt
NFR
[Fe(H2O)6]2+ and Na2CO3
FeCO3
green ppt
[Cu(H2O)6]2+ and Na2CO3
CuCO3
blue-green ppt
[Fe(H2O)6]3+ and Na2CO3
[Fe(H2O)3(OH)3]
brown ppt + CO2 bubbles
[Al(H2O)6]3+ and Na2CO3
[Al(H2O)3(OH)3]
white ppt + CO2 bubbles
[Fe(H2O)6]2+ and conc. HCl
[FeCl4]2-
yellow solution
[Cu(H2O)6]2+ and conc. HCl
[CuCl4]2-
green solution
[Fe(H2O)6]3+ and conc. HCl
[FeCl4]-
yellow solution
[Al(H2O)6]3+ + HCl
[AlCl4]-
colourless solution
If you add HCl to the [Cu(H2O)4(OH)2] formed CuSO4 + NaOH, why does the precipitate redissolve?
H+ will react with OH- from complex ion. [OH-] decreases, so equilibrium shifts to LHS to increase OH- formed and ppt redissolves.