AP Physics 1 Full Review (Unit 7 - Unit 8)

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59 Terms

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Hooke’s Law

Fs = -kΔx

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Equilibrium point on a spring is _

Where it rests when FNET = 0

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Simple Harmonic Motion (SHM)

  • Special case of periodic motion with a restoring force pulling back to equilibrium

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Restoring Force

Force causing the net acceleration (for a spring —> spring force)

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Equation for restoring force for a spring

-kΔx = ma

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What is the restoring force for a pendulum?

Force of the earth

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Restoring force is proportional to __

Distance from equilibrium point

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Frequency

Number of cycles that happen in a given time period (Hertz Hz) (Cycles per second)

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Period (T)

f = 1/T

How much time passes for one cycle

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Period relationship with length, mass, and gravity (Pendulum)

  • As length increases, so does the period

  • As mass increases, the period remains constant

  • As gravity increases, the period decreases

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Equation for period of a pendulum

Tp = 2π Square root(l/g)

l = length

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Period relationship with mass, spring constant, and gravity (Spring)

  • As mass increases, the period increases

  • As k increases, the period decreases

  • As gravity increases, the period remains constant

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Equation for Period of a Mass-Spring System

Ts = 2π Square root(m/k)

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Ideal Pendulum

0 friction

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Linear action makes slope __

useful in some way usually

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SHM Features

1) Energy conserved

2) Restoring force = unbalanced force acting towards equilibrium

3) Object equation = x = Acos(2πft)

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Object’s position in SHM equation

x = A cos(2πft)

A = Amplitude

f = Frequency

t = time

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When acceleration is changing, use __

Energy

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Spring max Potential Energy equation

Us max = ½ kA²

Where there is no kinetic energy and it’s at amplitude position

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Kinetic Energy is ___ when at the equilibrium of a vertical spring

Greatest

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Energy of a pendulum equation

EP = ½ mv² + mgh

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Energy of a horizontal spring equation

Ehs = ½ mv² + ½ kx²

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Energy of a vertical spring equation

Evs = ½ mv² + ½ kx² + mgh

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Equation for mechanical energy

ME = K + U

K = Kinetic Energy

U = Potential Energy

Conservation of Energy

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Ballistic Pendulum

Bullet shot into a block to make it swing

  • Increase Speed, increase Amplitude, Period stays constant

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Volume

  • Space occupied

  • Measured with graduated cylinder

  • V = lwh

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Density (ρ)

  • Amount of matter per space

  • Measured with Hydrometer (or calculated)

  • ρ = m/v

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Weight

  • Force of gravity on object (N)

  • Measured with spring scale

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Extensive properties definition

Properties that depend on the amount of matter (m, V, w)

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Intensive properties definition

Properties that depend on type of matter (density (ρ))

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Fluid states of matter

Liquid and gas

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Liquid properties

  • Mass, volume, and density constant

  • Shape is variable

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Equation for density (ρ)

ρ = m/v

units: kg/m³

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Gas properties

  • Mass constant

  • Volume, density, shape = variable

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Common density values

Air: ½ kg/m³

Water: 1000 kg/m³

Salt Water: 1030 kg/m³

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Slope of a m vs. V graph

Density (ρ)

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Pressure equation

P = F/A

Pressure = Force per Area

Units: N/m² = Pascal (Pa)

SCALAR

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Atmospheric Pressure

1.0 × 10^5 Pa

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Atmosphere puts __ on water

Pressure

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Equation for pressure exerted by a fluid

P = P0 + ρgh

P = Absolute pressure (Pa)

P0 = Atmospheric Pressure (Pa)

ρ = Fluid density (kg/m³)

g = GFS (N/kg) —> for MCQs use g=10

h = Fluid depth (m)

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Gauge Pressure

ρgh = gauge pressure (Pa)

ρ = fluid density

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Archimedes’ Principle

Buoyant Force = weight of displaced fluid

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Equation for Buoyant Force (Fb)

Fb = ρVg

ρ = density of fluid

V = Volume of fluid displaced

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Change in pressure equation (ΔPBA)

ΔPBA = ρgd

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Buoyant Force is caused by __

Difference in Pressure

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Floating definition

Stationary with Fb = Fg

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Ratio between V and ρ of a cube and water

VW/Vc = ρcW

Tells how much of cube is submerged

Ex) 40% submerged = 400 (kg/m³) / 1000 kg/m³)

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Conservation Laws (Fluids) for mass and energy

Mass: Continuity Equation

Energy: Bernoulli’s Principle

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Conservation of Mass (Fluid)

Same amount must pass through a point per second (speed can change)

Volume and Mass of liquid system conserved

Fluid Flow Rate Q = Volume/time

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Ideal Fluid

Water assumed to be incompressible

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Fluid Flow Rate (Q)

Q = Volume/Time (m³/s)

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Continuity Equation

A1V1 = A2V2

A - Cross-sectional area

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What kind of fluids can be used with Continuity Equation

Ideal/Incompressible fluids

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Bernoulli’s Equation Relationships

  • As Cross section decreases, Speed increases and Pressure decreases

  • As Vertical position increases (down), Pressure increases

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Bernoulli’s Equation

P1 + ρgy1 + ½ ρV1² = P2 + ρgy2 + ½ ρV2²

Statement of Conservation of Energy

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Pressure as pipe goes up and narrows

A1v1 = a2V2

P1 > P2

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Pressure as pipe goes down and widens

A1 < A2

V1 > V2

P1 < P2

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Torricelli’s Theorem definition

Specific application of Bernoulli’s Equation

Container with a hole at a specified location at a specified height that sends fluid in projectile motion

<p>Specific application of Bernoulli’s Equation</p><p>Container with a hole at a specified location at a specified height that sends fluid in <strong>projectile motion</strong></p>
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Torricelli’s Theorem

P1 + ρgy1 + ½ ρv1² = P2 + ρgy2 + ½ ρv2²

v = velocity

v2 = Square root(2gΔy)

<p>P<sub>1</sub> + ρgy<sub>1</sub> + ½ ρv<sub>1</sub>² = P<sub>2</sub> + ρgy<sub>2</sub> + ½ ρv<sub>2</sub>²</p><p>v = velocity</p><p>v<sub>2</sub> = Square root(2gΔy)</p>