Topic 6b - Reversible Reactions

Physical reactions vs chemical reactions

All physical reactions are reversible

• changes of state

• Dissolving/crystal

Most chemical reactions are not

A small selection of chemical reactions are reversible

What are all reactions

Exothermic in one direction and endothermic in the other

Reversible reactions

They can be represented like this:

A+B⇌C+D

The double arrow means reversible

• Initially rate of forward reaction is high, lots of A+B to collide

• Over time the forward rate of reaction decreases as less A+B. But backwards rate increases

• Eventually we reach equilibrium, this is when the forward and backward rates are equal, the reaction continues but we observe no further change. This only happens in a closed system

What happens to concentration and rate of reaction for: A+B⇌C+D

• At the start of the reaction the concentration and rate of the forward reaction (A+B) are high where as the concentration and rate of the reverse reaction (C+D) is zero

• As the reaction continues the concentration and rate of the forward reaction (A+B) are reducing where as the concentration and rate of the reverse reaction (C+D) are increasing

• When equilibrium is reached the concentration and rate of the forward reaction (A+B) and reverse (C+D) reactions are both constant

Why do we alter the position of equilibrium and how do we do this

We can alter the position of equilibrium to favour one of the reactions

We can do this by altering one of three conditions:

• temperature

• Catalyst

• Pressure

What is a closed system

If a reversible reaction takes place in a closed system then a state of equilibrium will always be reached. It’s a system with a closed lid, to prevent reactants escaping

What was the name of the chemist that looked at this

Le Chatelier’s

How does temperature affect the position of equilibrium

If we increase the temperature we favour the endothermic direction as there is more energy for the reaction to take in

How temperature affects the position of equilibrium for this reaction:

• Increase in temp favours endothermic diversion

• In this reaction the backwards reaction is endothermic

• Equilibrium shifts to favour this reaction to produce more N2 + H2 (Exo →)

How does pressure affect the position of equilibrium

If we increase the pressure that the reaction is happening at then the reaction will favour the reaction that produces less molecules

How does pressure affect the position of equilibrium for this reaction

• For this reaction, this is the forwards reaction as it produces less molecules (4→2)

• Equilibrium shifts to favour this reaction, we produce more NH3

What do catalysts do to any chemical reaction

• Speed it up by offering an alternative energy pathway with lowered activation energy requirement

• This is exactly the same for reversible reactions, except that the catalyst speeds up both reactions equally

How does catalysts affect the position of equilibrium

It doesn’t! Adding a catalyst has no impact on the position of equilibrium and does not favour either the forward or reverse reactions. However, we do reach equilibrium faster

Exam Eg:

A+B⇌C+D

Explain why the position of the equilibrium lies to the right

More of C than A+B

Exam Eg:

CH4 + H2O ⇌ CO + 3H2

Energy change = +206 (endo)

1) If the temp of this equilibrium was increased, what would happen to the equilibrium yield of hydrogen? - explain why

2) If the pressure of this equilibrium was increased, what would happen to the equilibrium yield of hydrogen? - explain why

1) More H2, why? - increase in temp favours endothermic, this is the → reaction, makes more H2

2) Less H2, why? - increase in pressure favours reaction that produces less molecules in this reaction ←

Exam Eg:

CO + H2O ⇌ CO2 + H2

Energy change = -42 (exo)

1) If the temp of this equilibrium was increased, what would happen to the equilibrium yield of hydrogen? - explain why

2) If the pressure of this equilibrium was increased, what would happen to the equilibrium yield of hydrogen? - explain why

1) Less H2, why? - temperature favours endothermic diversion In ← less H2

2) Stay the same, why? - same number of molecules on both sides

Exam Eg

CO2 + 3H2 ⇌ CH3OH + H2O

If steam was removed from the equilibrium mixture, what happens to the equilibrium yield of methanol? - explain why

Make more methanol, why? - replace lost H2O