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"p" denotes the -log has already been taken
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[H⁺] to pH
-log[H⁺]
pH to pOH
14-pOH
pOH to [OH⁻]
10-ᵖᴼᴴ
[OH⁻] to [H⁺]
1×10⁻¹⁴/[OH⁻]