1/22
Looks like no tags are added yet.
Name | Mastery | Learn | Test | Matching | Spaced | Call with Kai |
|---|
No analytics yet
Send a link to your students to track their progress
monotonic sequence
always increasing or decreasing
bounded sequences
upper and lower bound (if both are true then then an is bounded)
infinite series
n=1 SUM infinity an = a1 + a2 +a3 … an
an gives the value of the nth term in the sequence
partial sum
Sn = a1 + a2 + a3 …
If partial sum converges then the infinite series converges
Value the infinite series converges to is equal to lim n→ infinity of Sn
geometric series converges to
(ark) / (1-r) where (ark) is the first term in the series
geometric series reminder
be careful of (-n) powers because it can flip R (common ratio)
geometric series written as
aorn
a1rn-1
a2rn-2
nth term test
Lim n→ infinity = 0 because series could converge or diverge
if it doesnt equal zero then it diverges
REVERSE ISNT TRUE THOUGH; IF IT DIVERGES YOU CAN’T ASSUME WHAT THE LIMIT IS
sometimes you have to use l’hopitals to evaulate limit
integral test CONDITIONS
ALWAYS CHECK FOR: positive, continuous, decreasing
“limit of the series” means just take the limit of an
if limit is finite then BOTH CONVERGE if not BOTH DIVERGE
dont forgettt
you can put them into your calculator
partial sums using: math 0
DONT FORGET NOTATION
watch the integral bounds and the limit for the improper integral
limit comparison test conditions
BOTH AN AND BN MUST BE POSITIVE
limit comparison test
BOTH converge or BOTH diverge
absolute/conditional convergence
if abs value of an converges than an also converges (absolute); if the abs value version diverges and the normal converges its conditional; if both diverge its divergent
when solving for interval of convergence make sure to
test the endpoints
alternating series error bound
error is less than the 1st term left off (aka the next term)
lagrange error bound
MAX f (n+1)(z)(x-c)n+1 / (n+1)!
radius/int of convergence
use ratio test; (dont forget abs value)
if its <1 then it converges to an interval
= 0 converges R (-infinity, infinity) — all real numbers
>1 converges to center x=c
Taylor/Maclaurin Series
applies for f(x) if it’s differentiable for every order
ex
1 + x + x²/2! + x³/3! … sum x^n / n!
sinx
x - x³ / 3! + x^5 / 5! + … sum (-1)nx2n+1 / (2n+1)!
cosx
1 - x2 / 2! + x^4 / 4! + … sum (-1)nx2n / (2n)!
1 / (1+x)
1 - x + x² - x³ + … + sum (-1)2 xn