Gr11-12 Euclidean geometry concepts

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50 Terms

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Diameter

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<p>A portion of the circumference</p>

A portion of the circumference

Arc

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Chord

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Line from centre perp to the chord

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Line from centre to midpt. of chord

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Angle at centre= 2 X angle at circum

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angle in semi circle

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Prove a diameter

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<p>Angles<span> </span>subtended<span> </span>by<span> </span>a<span> </span>chord<span> </span>of<span> </span>the<span> </span>circle,<span> </span>on<span> </span>the<span> </span>same<span> </span>side<span> </span>of<span>  the chord are equal</span></p>

Angles subtended by a chord of the circle, on the same side of the chord are equal

<s in the same seg

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Equal chords subtend equal angles at the circumference of the circle.

equal chords; equal angles

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Equal chords subtend equal angles at the centre of the circle.

equal chords; equal angles

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Equal chords in equal circles subtend equal angles at the circumference of the circles.

equal circles; equal chords; equal angles

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<table style="minWidth: 25px"><colgroup><col></colgroup><tbody><tr><td colspan="1" rowspan="1"><p>The<span> </span>opposite<span> </span>angles<span> </span>of<span> </span>a<span> </span>cyclic<span> </span>quadrilateral<span> </span>are<span> supplementary</span></p></td></tr></tbody></table>

The opposite angles of a cyclic quadrilateral are supplementary

opp angles of cyclic quad

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Prove cyclic quad:

If the opposite angles of a quadrilateral are supplementary, then the quadrilateral is cyclic.

opp angles quad supp  OR

converse opp angles of cyclic quad

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<table style="minWidth: 25px"><colgroup><col></colgroup><tbody><tr><td colspan="1" rowspan="1"><p>The<span> </span>exterior<span> </span>angle<span> </span>of<span> </span>a<span> </span>cyclic<span> </span>quadrilateral<span> </span>is<span> </span>equal<span> </span>to<span> </span>the<span> interior</span></p><p>opposite<span> angle.</span></p></td></tr></tbody></table>

The exterior angle of a cyclic quadrilateral is equal to the interior

opposite angle.

ext angles of cyclic quad

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Prove cyclic quad:

If the exterior angle of a quadrilateral is equal to the interior opposite angle of the quadrilateral, then the quadrilateral is cyclic.

ext angles = int opp angles OR

converse ext angles of cyclic quad

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<table style="minWidth: 25px"><colgroup><col></colgroup><tbody><tr><td colspan="1" rowspan="1"><p>Two<span> </span>tangents<span> </span>drawn<span> </span>to<span> </span>a<span> </span>circle<span> </span>from<span> </span>the<span> </span>same<span> </span>point<span> </span>outside<span> the</span></p><p>circle<span> </span>are<span> </span>equal<span> </span>in<span> length</span></p></td></tr></tbody></table>

Two tangents drawn to a circle from the same point outside the

circle are equal in length

Tans from common pt OR

Tans from same pt

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<table style="minWidth: 25px"><colgroup><col></colgroup><tbody><tr><td colspan="1" rowspan="1"><p>The<span> </span>angle<span> </span>between<span> </span>the<span> </span>tangent<span> </span>to<span> </span>a<span> </span>circle<span> </span>and<span> </span>the<span> </span>chord<span> </span>drawn<span> from</span></p><p>the<span> </span>point<span> </span>of<span> </span>contact<span> </span>is<span> </span>equal<span> </span>to<span> </span>the<span> </span>angle<span> </span>in<span> </span>the<span> </span>alternate<span> segment.</span></p></td></tr></tbody></table>

The angle between the tangent to a circle and the chord drawn from

the point of contact is equal to the angle in the alternate segment.

tan chord theorem

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Prove line is a tangent:

If a line is drawn through the endpoint of a chord, making with the

chord an angle equal to an angle in the alternate segment, then the line is a tangent to the circle.

converse tan chord theorem OR

angles between line and chord

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Prove Line is a tangent

;Line from centre to tangent forms a 90 degree angle

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tan perp to radius/diam

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Congruent Figures

  • Figures that have the same size and shape.

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Similar Figures

  • Figures that have the same shape but not necessarily the same size.

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Equilateral Triangle

  • A triangle with all three sides and all three angles equal (each angle is 60 degrees).

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The interior angles of a quadrilateral add up to 360°.

sum of angles in quad

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The opposite sides of a parallelogram are parallel.

opp sides of parm

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Prove a parallogram:

If the opposite sides of a quadrilateral are parallel, then the

quadrilateral is a parallelogram.

opp sides of quad are ||

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The opposite sides of a parallelogram are equal in length.

opp sides of parm

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Prove Parallelogram

If the opposite sides of a quadrilateral are equal , then the quadrilateral is a parallelogram.

opp sides of quad are = OR

converse opp sides of a parm

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The opposite angles of a parallelogram are equal.

opp angles of parm

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Prove parallelogram:

If the opposite angles of a quadrilateral are equal, then the quadrilateral is a parallelogram.

opp angles of quad are = OR

converse opp angles of a parm

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The diagonals of a parallelogram bisect each other.

diag of parm

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Prove parallelogram:

If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.

diags of quad bisect each other

OR

converse diags of a parm

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Prove parallelogram:

If one pair of opposite sides of a quadrilateral are equal and parallel,

then the quadrilateral is a parallelogram.

pair of opp sides = and ||

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<p>Given <span data-name="small_red_triangle" data-type="emoji">🔺</span>ABC with PQ//BC</p>

Given 🔺ABC with PQ//BC

Conclusion: AP/PB=AQ/QC - Line // side of 🔺

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AP/PB=AQ/QC

PB/AP=QC/AQ

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What can this ratio also be written as?
AB:BC (m:n)

AB/BC (m/n)

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<p>Given: <span data-name="small_red_triangle" data-type="emoji">🔺</span>ABC with AP/PB=AQ/QC </p>

Given: 🔺ABC with AP/PB=AQ/QC

Conclusion: PQ//BC -Line divides 2 sides of 🔺 in prop

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<p>Same perp height</p>

Same perp height

Ratio of areas=Ratio of bases

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<p>Common angle; parallel lines</p>

Common angle; parallel lines

Ratio of areas=(Ratio of corresponding sides)²

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<p>Area of <span data-name="small_red_triangle" data-type="emoji">🔺</span>ABC= Area of <span data-name="small_red_triangle" data-type="emoji">🔺</span>DBC=Area<span data-name="small_red_triangle" data-type="emoji">🔺</span>PQR</p>

Area of 🔺ABC= Area of 🔺DBC=Area🔺PQR

same base;same height

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<p><span data-name="small_red_triangle" data-type="emoji">🔺</span>CAT///<span data-name="small_red_triangle" data-type="emoji">🔺</span>DOG</p>

🔺CAT///🔺DOG

C=D
A=O
T=G

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<p>Ratio of the sides are equal</p>

Ratio of the sides are equal

CA/DO = CT/DG = AT/OG

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IF TRIANGLES ARE SIMILAR THEIR SIDES ARE?

IN PROPORTION

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If you are given: AB/AC =BC/CD and you should prove this..you need to find the triangle first… what two methods can you use?

  1. Are the top/bottom of the fraction able to create a reasonable triangle

    1. Are the left/right sides of the fraction able to create a reasonable triangle

<ol><li><p>Are the top/bottom of the fraction able to create a reasonable triangle</p><ol><li><p>Are the left/right sides of the fraction able to create a reasonable triangle</p></li></ol></li></ol>
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<p>Theorem 3: <span data-name="small_red_triangle" data-type="emoji">🔺</span>ABC///<span data-name="small_red_triangle" data-type="emoji">🔺</span>PBA///<span data-name="small_red_triangle" data-type="emoji">🔺</span>PAC</p>

Theorem 3: 🔺ABC///🔺PBA///🔺PAC

reason: Line from right angle vertex perp hypotenuse

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<p>Proof of theorem 1:</p>

Proof of theorem 1:

Solution to proof:

<p>Solution to proof: </p>
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<p>Proof of Theorem 2:</p>

Proof of Theorem 2:

Proof:

<p>Proof: </p>
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<p>Theorem 3 :</p>

Theorem 3 :

Proof:

<p>Proof:</p>