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Diameter
A portion of the circumference
Arc
Chord
Line from centre perp to the chord
Line from centre to midpt. of chord
Angle at centre= 2 X angle at circum
angle in semi circle
Prove a diameter
Angles subtended by a chord of the circle, on the same side of the chord are equal
<s in the same seg
Equal chords subtend equal angles at the circumference of the circle. |
equal chords; equal angles |
Equal chords subtend equal angles at the centre of the circle. |
equal chords; equal angles |
Equal chords in equal circles subtend equal angles at the circumference of the circles. |
equal circles; equal chords; equal angles |
The opposite angles of a cyclic quadrilateral are supplementary |
opp angles of cyclic quad |
Prove cyclic quad:
If the opposite angles of a quadrilateral are supplementary, then the quadrilateral is cyclic. |
opp angles quad supp OR converse opp angles of cyclic quad |
The exterior angle of a cyclic quadrilateral is equal to the interior opposite angle. |
ext angles of cyclic quad |
Prove cyclic quad:
If the exterior angle of a quadrilateral is equal to the interior opposite angle of the quadrilateral, then the quadrilateral is cyclic. |
ext angles = int opp angles OR converse ext angles of cyclic quad |
Two tangents drawn to a circle from the same point outside the circle are equal in length |
Tans from common pt OR Tans from same pt |
The angle between the tangent to a circle and the chord drawn from the point of contact is equal to the angle in the alternate segment. |
tan chord theorem |
Prove line is a tangent:
If a line is drawn through the endpoint of a chord, making with the chord an angle equal to an angle in the alternate segment, then the line is a tangent to the circle. |
converse tan chord theorem OR angles between line and chord |
Prove Line is a tangent
;Line from centre to tangent forms a 90 degree angle
tan perp to radius/diam
Congruent Figures
Figures that have the same size and shape.
Similar Figures
Figures that have the same shape but not necessarily the same size.
Equilateral Triangle
A triangle with all three sides and all three angles equal (each angle is 60 degrees).
The interior angles of a quadrilateral add up to 360°. |
sum of angles in quad |
The opposite sides of a parallelogram are parallel. |
opp sides of parm |
Prove a parallogram:
If the opposite sides of a quadrilateral are parallel, then the quadrilateral is a parallelogram. |
opp sides of quad are || |
The opposite sides of a parallelogram are equal in length. |
opp sides of parm |
Prove Parallelogram
If the opposite sides of a quadrilateral are equal , then the quadrilateral is a parallelogram. |
opp sides of quad are = OR converse opp sides of a parm |
The opposite angles of a parallelogram are equal. |
opp angles of parm |
Prove parallelogram:
If the opposite angles of a quadrilateral are equal, then the quadrilateral is a parallelogram. |
opp angles of quad are = OR converse opp angles of a parm |
The diagonals of a parallelogram bisect each other. |
diag of parm |
Prove parallelogram:
If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram. |
diags of quad bisect each other OR converse diags of a parm |
Prove parallelogram:
If one pair of opposite sides of a quadrilateral are equal and parallel, then the quadrilateral is a parallelogram. |
pair of opp sides = and || |
Given 🔺ABC with PQ//BC
Conclusion: AP/PB=AQ/QC - Line // side of 🔺
AP/PB=AQ/QC
PB/AP=QC/AQ
What can this ratio also be written as?
AB:BC (m:n)
AB/BC (m/n)
Given: 🔺ABC with AP/PB=AQ/QC
Conclusion: PQ//BC -Line divides 2 sides of 🔺 in prop
Same perp height
Ratio of areas=Ratio of bases
Common angle; parallel lines
Ratio of areas=(Ratio of corresponding sides)²
Area of 🔺ABC= Area of 🔺DBC=Area🔺PQR
same base;same height
🔺CAT///🔺DOG
C=D
A=O
T=G
Ratio of the sides are equal
CA/DO = CT/DG = AT/OG
IF TRIANGLES ARE SIMILAR THEIR SIDES ARE?
IN PROPORTION
If you are given: AB/AC =BC/CD and you should prove this..you need to find the triangle first… what two methods can you use?
Are the top/bottom of the fraction able to create a reasonable triangle
Are the left/right sides of the fraction able to create a reasonable triangle
Theorem 3: 🔺ABC///🔺PBA///🔺PAC
reason: Line from right angle vertex perp hypotenuse
Proof of theorem 1:
Solution to proof:
Proof of Theorem 2:
Proof:
Theorem 3 :
Proof: