Motion in a Straight line

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formula for acceleration

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32 Terms

1

formula for acceleration

(Final Velocity - Starting Velocity)/ time

<p>(Final Velocity - Starting Velocity)/ time</p>
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2

formula for speed

speed = distance / time

<p>speed = distance / time</p>
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3

formula for average speed

Average speed = total distance / total time

<p>Average speed = total distance / total time</p>
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4

distance is a _ quantity, it is always _

scalar, positive

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5

displacement does not depend on _, it is a _ quantity
how to find it using a graph

path, vector
area of velocity - time graph

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<p>average speed = <br>Savg for equal time interval <br>Savg for equal distance</p>

average speed =
Savg for equal time interval
Savg for equal distance

total distance / total time
S1 + S2 / 2
2 S1 S2 / S1 + S2

<p>total distance / total time<br>S1 + S2 / 2 <br>2 S1 S2 / S1 + S2</p>
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<p>uniform motion</p>

uniform motion

equal distance in equal time in one direction
uniform velocity: avg v = instantaneous v

<p>equal distance in equal time in one direction <br>uniform velocity: avg v = instantaneous v</p>
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8

when a = 0

S = vt
uniform motion (constant velocity)

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9
<p>equations of motion</p>

equations of motion

v = u + at
S = ut + (1/2) at^2
v^2 - u^2 = 2aS

<p>v = u + at <br>S = ut + (1/2) at^2 <br>v^2 - u^2 = 2aS</p>
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10

motion under gravity: non uniform motion with uniform acceleration
object is dropped from some height
T, vt, vground, v avg

T = sq root (2H / g)
vt = gt, vground = sq root (2gH)
vavg = sq root (gH / 2)

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11

river downstream
meaning, t =

Vman is same as Vriver (direction)
t = S / vm + vr

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12

river upstream
meaning, t =

Vman is opposite to Vriver (direction)
t = S / vm - vr

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Important Terms

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19

Acceleration avg

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20

Average Velocity

Only valid when constant Acceleration

<p>Only valid when constant Acceleration</p>
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21
<p>Velocity mid </p>

Velocity mid

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22

Gallileo’s ratio in 1sec, 2sec and 3 sec

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Gallileo’s ratio in 1st, 2nd and 3rd

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Displacement time graph

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Motion under gravity

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Time of flight
Velocity at ground

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<p>distance and displacment?</p>

distance and displacment?

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