If f(1)\=-4 and f(6)\=9, then there must be a x-value between 1 and 6 where f crosses the x-axis.
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Average Rate of Change
Slope of secant line between two points, use to estimate instantanous rate of change at a point.
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Instantenous Rate of Change
Slope of tangent line at a point, value of derivative at a point
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Formal definition of derivative
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Alternate definition of derivative
limit as x approaches a of [f(x)-f(a)]/(x-a)
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When f '(x) is positive, f(x) is
increasing
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When f '(x) is negative, f(x) is
decreasing
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When f '(x) changes from negative to positive, f(x) has a
relative minimum
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When f '(x) changes from positive to negative, f(x) has a
relative maximum
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When f '(x) is increasing, f(x) is
concave up
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When f '(x) is decreasing, f(x) is
concave down
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When f '(x) changes from increasing to decreasing or decreasing to increasing, f(x) has a
point of inflection
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When is a function not differentiable
corner, cusp, vertical tangent, discontinuity
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Product Rule
uv' + vu'
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Quotient Rule
(uv'-vu')/v²
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Chain Rule
f '(g(x)) g'(x)
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y \= x cos(x), state rule used to find derivative
product rule
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y \= ln(x)/x², state rule used to find derivative
quotient rule
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y \= cos²(3x)
chain rule
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Particle is moving to the right/up
velocity is positive
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Particle is moving to the left/down
velocity is negative
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absolute value of velocity
speed
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y \= sin(x), y' \=
y' \= cos(x)
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y \= cos(x), y' \=
y' \= -sin(x)
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y \= tan(x), y' \=
y' \= sec²(x)
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y \= csc(x), y' \=
y' \= -csc(x)cot(x)
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y \= sec(x), y' \=
y' \= sec(x)tan(x)
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y \= cot(x), y' \=
y' \= -csc²(x)
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y \= sin⁻¹(x), y' \=
y' \= 1/√(1 - x²)
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y \= cos⁻¹(x), y' \=
y' \= -1/√(1 - x²)
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y \= tan⁻¹(x), y' \=
y' \= 1/(1 + x²)
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y \= cot⁻¹(x), y' \=
y' \= -1/(1 + x²)
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y \= e^x, y' \=
y' \= e^x
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y \= a^x, y' \=
y' \= a^x ln(a)
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y \= ln(x), y' \=
y' \= 1/x
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y \= log (base a) x, y' \=
y' \= 1/(x lna)
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To find absolute maximum on closed interval [a, b], you must consider...
critical points and endpoints
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mean value theorem
if f(x) is continuous and differentiable, slope of tangent line equals slope of secant line at least once in the interval (a, b)
f '(c) = \[f(b) - f(a)\]/(b - a)
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If f '(x) \= 0 and f"(x) \> 0,
f(x) has a relative minimum
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If f '(x) \= 0 and f"(x) < 0,
f(x) has a relative maximum
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Linearization
use tangent line to approximate values of the function
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rate
derivative
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left riemann sum
use rectangles with left-endpoints to evaluate integral (estimate area)
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right riemann sum
use rectangles with right-endpoints to evaluate integrals (estimate area)
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trapezoidal rule
use trapezoids to evaluate integrals (estimate area)
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\[(h1 - h2)/2]*base
area of trapezoid
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definite integral
has limits a & b, find antiderivative, F(b) - F(a)
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indefinite integral
no limits, find antiderivative + C, use inital value to find C
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area under a curve
∫ f(x) dx integrate over interval a to b
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area above x-axis is
positive
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area below x-axis is
negative
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average value of f(x)
\= 1/(b-a) ∫ f(x) dx on interval a to b
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If g(x) \= ∫ f(t) dt on interval 2 to x, then g'(x) \=
g'(x) \= f(x)
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Fundamental Theorem of Calculus
∫ f(x) dx on interval a to b \= F(b) - F(a)
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To find particular solution to differential equation, dy/dx \= x/y
separate variables, integrate + C, use initial condition to find C, solve for y
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To draw a slope field,
plug (x,y) coordinates into differential equation, draw short segments representing slope at each point
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slope of horizontal line
zero
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slope of vertical line
undefined
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methods of integration
substitution, parts, partial fractions
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use substitution to integrate when
a function and it's derivative are in the integrand
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use integration by parts when
two different types of functions are multiplied
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∫ u dv \=
uv - ∫ v du
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use partial fractions to integrate when
integrand is a rational function with a factorable denominator
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dP/dt \= kP(M - P)
logistic differential equation, M \= carrying capacity
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P \= M / (1 + Ae^(-Mkt))
logistic growth equation
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given rate equation, R(t) and inital condition when t = a, R(t) = y₁ find final value when t = b
y₁ + Δy = y
Δy = ∫ R(t) over interval a to b
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given v(t) and initial position t \= a, find final position when t \= b
s₁+ Δs = s
Δs = ∫ v(t) over interval a to b
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given v(t) find displacement
∫ v(t) over interval a to b
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given v(t) find total distance travelled
∫ abs[v(t)] over interval a to b
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area between two curves
∫ f(x) - g(x) over interval a to b, where f(x) is top function and g(x) is bottom function
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volume of solid with base in the plane and given cross-section
∫ A(x) dx over interval a to b, where A(x) is the area of the given cross-section in terms of x
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volume of solid of revolution - no washer
π ∫ r² dx over interval a to b, where r \= distance from curve to axis of revolution
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volume of solid of revolution - washer
π ∫ R² - r² dx over interval a to b, where R \= distance from outside curve to axis of revolution, r \= distance from inside curve to axis of revolution
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length of curve
∫ √(1 + (dy/dx)²) dx over interval a to b
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L'Hopitals rule
use to find indeterminate limits, find derivative of numerator and denominator separately then evaluate limit
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indeterminate forms
0/0, ∞/∞, ∞*0, ∞ - ∞, 1^∞, 0⁰, ∞⁰
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6th degree Taylor Polynomial
polynomial with finite number of terms, largest exponent is 6, find all derivatives up to the 6th derivative
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Taylor series
polynomial with infinite number of terms, includes general term
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nth term test
if terms grow without bound, series diverges
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alternating series test
lim as n approaches zero of general term \= 0 and terms decrease, series converges
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converges absolutely
alternating series converges and general term converges with another test
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converges conditionally
alternating series converges and general term diverges with another test
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ratio test
lim as n approaches ∞ of ratio of (n+1) term/nth term \> 1, series converges
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find interval of convergence
use ratio test, set \> 1 and solve absolute value equations, check endpoints
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find radius of convergence
use ratio test, set \> 1 and solve absolute value equations, radius \= center - endpoint
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integral test
if integral converges, series converges
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limit comparison test
if lim as n approaches ∞ of ratio of comparison series/general term is positive and finite, then series behaves like comparison series
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geometric series test
general term \= a₁r^n, converges if -1 < r < 1
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p-series test
general term \= 1/n^p, converges if p \> 1
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derivative of parametrically defined curve x(t) and y(t)
dy/dx = dy/dt / dx/dt
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second derivative of parametrically defined curve
find first derivative, dy/dx \= dy/dt / dx/dt, then find derivative of first derivative, then divide by dx/dt
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length of parametric curve
∫ √ (dx/dt)² + (dy/dt)² over interval from a to b
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given velocity vectors dx/dt and dy/dt, find speed
√(dx/dt)² + (dy/dt)² not an integral!
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given velocity vectors dx/dt and dy/dt, find total distance travelled
∫ √ (dx/dt)² + (dy/dt)² over interval from a to b
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area inside polar curve
1/2 ∫ r² over interval from a to b, find a & b by setting r \= 0, solve for theta
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area inside one polar curve and outside another polar curve
1/2 ∫ R² - r² over interval from a to b, find a & b by setting equations equal, solve for theta.