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Alkane
Only single bonds; C(n)H(2n+2)

Alkene
Has double bonds; C(n)H(2n)

Alkyne
Has triple bonds; C(n)H(n)

Cyclic alkane
C(n)H(2n)

Aromatic hydrocarbons (arenes)
C6H5

halohydrocarbons
R-X (F, Cl, Br, I)

alcohol
R-OH

ether
R-O-R

aldehyde
R-C=O-H

ketone
R-C=O-R

ester
RCOOR

amine
R-NH2

carboxylic acid
R-COOH

phenol
Benzene ring with -OH

acyl halide
RCOX

amide
RCONH2

nitrile
R-C=-N

First order rate law
Rate = k[A]
Integrated Rate: ln[A] = -kt + ln[A]0
Half life: t(1/2) = ln(2)/k
Plot of ln([A]) is linear
![<p>Rate = k[A]</p><p>Integrated Rate: ln[A] = -kt + ln[A]0</p><p>Half life: t(1/2) = ln(2)/k</p><p>Plot of ln([A]) is linear</p>](https://assets.knowt.com/user-attachments/b3ea73ee-83fd-4ff2-952e-617ed890437b.png)
Second order rate law
Rate = k[A]^2
Integrated Rate: 1/[A] = kt + 1/[A]0
Half life: t(1/2) = 1/k[A]0
Plot of 1/[A] is linear
![<p>Rate = k[A]^2</p><p>Integrated Rate: 1/[A] = kt + 1/[A]0</p><p>Half life: t(1/2) = 1/k[A]0</p><p>Plot of 1/[A] is linear</p>](https://assets.knowt.com/user-attachments/01776aff-6466-4d9c-a3e3-5f8bf1ef18da.png)
Zero order rate law
Rate = k
Integrated rate = [A] = -kt + [A]0
Half life: t(1/2) = [A]0/2k
Plot of [A] is linear
![<p>Rate = k</p><p>Integrated rate = [A] = -kt + [A]0</p><p>Half life: t(1/2) = [A]0/2k</p><p>Plot of [A] is linear</p>](https://assets.knowt.com/user-attachments/d775d0e6-71ac-43e7-9801-2aa32e3bd799.png)