Combustion Analysis and Stoichiometry

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These flashcards cover key concepts from the combustion analysis and stoichiometry lectures, specifically focusing on empirical formulas, the combustion process, and how to perform stoichiometric calculations.

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11 Terms

1
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What is combustion analysis used for?

It is used to determine the empirical formula of a compound by analyzing the products formed when a compound containing carbon, hydrogen, and oxygen is burned.

2
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What products are formed when burning carbon, hydrogen, and oxygen?

Carbon dioxide (CO2) and water vapor (H2O) are formed as products.

3
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In combustion analysis, how can the amount of carbon in the original compound be determined?

The amount of carbon can be determined by measuring the mass of CO2 produced; since each mole of CO2 contains one mole of carbon.

4
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What is an empirical formula?

An empirical formula is a simplified version of a chemical formula that shows the ratio of the elements in a compound in their lowest whole number ratio.

5
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How do you convert grams of a substance to moles?

To convert grams to moles, divide the mass of the substance by its molar mass.

6
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What is the term for the calculations used to relate the amounts of reactants and products in a chemical reaction?

Stoichiometry.

7
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When identifying the limiting reactant, what should you look for?

The limiting reactant is the reactant that is completely consumed first in a reaction, limiting the amount of products that can be formed.

8
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What is the relation between the moles of reactants and products in a balanced equation called?

The coefficients of the balanced equation represent the mole ratio between reactants and products.

9
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What is the formula to calculate the molarity of a solution?

Molarity (M) is calculated as moles of solute divided by liters of solution.

10
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What happens to the concentration during the dilution of a solution?

The concentration of the solution decreases as the volume increases when diluting with solvent.

11
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What is the formula used for dilution problems?

M1V1 = M2V2, where M is molarity and V is volume.