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Equilibrium
refers to systems that have opposing processes happening at the same time and rate
almost all reactions are reversible at certain conditions
represented by ⇌
⇌ represents that the equation is both
going in the forwards direction to products and back towards reactants; considered dynamic
at equilibrium the rate of the forward reaction is equal to
the rate of the reverse reaction
some reactions “favor” products or reactants more than the other resulting in
one side of the reaction having a higher [] than the other
forward favored reaction
25 25 → 50
backwards favored reaction
50 50 → 25
Le Chetalier
when a system experiences stress the equilibrium will shift to relieve the stress
Factors that cause a shift
Pressure change (only for gases)
Concentration change (volume changes for gas)
Temperature change
Pressure (P)
equilibrium systems involving gases the total mol of gas on the reactant side and product side must be unequal
If P increases the [] of all the species in the reaction
in order to reduce the stress the reaction will shift torward the side with fewer moles
changing P or adding an inert gas (such as a noble gas) will not affect the equilibrium constant
will go to side with least amount of moles when increasing pressure
Concentration
A + B ⇌ C + D
increase [] of one species in a system stresses equilibrium and will result in a shift away from the increase []
If [] of A or B is increased it will cause ⇌ to shift toward right
If [] of C or D is increased it will cause ⇌ to shift toward left
A decrease in [] will cause the equilibrium to shift toward to decrease species, if [A] decreases the ⇌ will shift left
Changing the [] will not affect the ⇌ constant
Temperature
endo: heat + A + B ⇌ C (increasing heat = shift right) (decrease = left)
exo: A + B ⇌ C + heat (decreasing heat =shift right) (increasing = left)
increasing heat go away/ decreasing heat go towards
change in temp will affect the equilibrium constant
only way to change ⇌ constant
Equilibrium constant [] of reactants and products
nA + mB ⇌ xC + yD
where n, m ,x, and y are the coefficients used to balance the chemical equation
assume initial [] of C and D are both zero since none to start
initial [] of A and B are at their max at start of reaction
as the system reacts and reaches equilibrium the concentration will undergo no more changes
Equilibrium constant (K)
shows us the mathematical relationship between products and reactants
determined with just the balanced equation of the system at equilibrium
K= [C]^x[D]^y / [A]^n [B]^m
if [] known of products and reactants in reaction you can use equilibrium expression to calculate K
about equilibrium expression/constant
equilibrium is always temp dependent
only aqueous and gaseous substances are used it the equilibrium expression
Solids/liquids never in equilibrium expressions
Keq is how you show aq []
Ksp is how you show the solubility product constant for ions
only for dissolving a solid
the lower the K value the higher the equilibrium [] of the reactants
Keq < 1 favor
reactants
Keq > 1 favor
products
Molarity=
mol solute/L solution
[Brackets] refers to
concentration of your substances
Ice Table
used to organize equilibrium calc info
acronym that stands for initial concentration, change in concentration, and equilibrium concentration
Reaction, Initial, Change, Equilibrium
solubility equilibrium
many ionic compounds dissolve only a little in H2O
we use concept of solubility equilibrium to quantify the degree of solubility
equilibrium = rate of dissolving is equal to rate of precipitation
write the solubility product constant Ksp expression for this “reaction”, remembering that solids not included
Solubility Product constant
the smaller the Ksp, the less soluble the compound is
The Common Ion Effect
a common ion is an ion that is found in both compounds in solution
The lowering of the solubility of an ionic compound by adding a common ion is called the common ion effect
If common ion, will lower the Ksp
AgCl(s) ⇌ Ag + Cl in Cl solution (equilibrium shifted left)
how can K be changed
temperature change (only thing that changes the value of K)
do catalysts affect the equilibrium?
no
if an endothermic reaction at equilibrium were placed in an ice bath, what would be the effect (A + heat ⇌ B)
more reactants (heat decreasing, so shift left)
What is true of the rates of the forward and reverse reactions at equilibrium?
they are equal, a catalyst affects both equally, and temperature changes both
Things are more soluble when
Ksp is closer to 1
Dynamic equilibrium
equation going both forwards and reverse
How does catalyst affect equilibrium?
lowers the activation energy for the reactions
LeChatelier’s Principle
when a system experiences stress the equilibrium will shift to relieve the stress
increase side=favor opposite
decrease side=favor same side
pressure only affects gas (P increases = favors less mol)
Equilibrium constant
products divided by reactants to the coefficient power
What is the meaning of the magnitude of Keq?
Keq<1 favors reactants
Keq>1 favors products
How is Keq writen if any species is a pure liquid or solid?
not shown in it
how can Keq be changed
temperature change
Equilibrium position
the reactants or products will be favored
Solubility product constant
start with solid and put in H2O so reactant is (s) and products are (aq)
What is the meaning of the magnitude of Ksp?
the larger the value (x10^x) or greater the more soluble it is (more free floating ions)
the smaller the value, the more insoluble it is (less free floating ions)