Action potential graph

1a

the graph stars at the membranes resting potential ______mV

both voltage gated Na+ y K+ gates remain ______

the graph stars at the membranes resting potential (-70mV)

both voltage gated Na+ y K+ gates remain closed

2

_______ is applied

this triggers the ______ of a few ___ ____ Na+ gates

if it is strong enough, the voltage rises to what is called the _______ (_____mV)

stimulus is applied

this triggers the opening of a few non voltage Na+ gates

if it is strong enough, the voltage rises to what is called the threshold (-55mV)

3

once the ______ is reached, the _____ potential is triggered

voltage gated ___+ channels open, allowing even more ___+ to diffuse into the cell

the membrane polarity is reversed abruptly (______) —→ becomes more positvely charged

as more ___+ moves into the axon, the voltage soars to its peak (approximately ____mV)

once the threshold is reached, the action potential is triggered

voltage gated Na+ channels open, allowing even more Na+ to diffuse into the cell

the membrane polarity is reversed abruptly depolarization —→ becomes more positvely charged

as more Na+ moves into the axon, the voltage soars to its peak (approximately +35mV)

4

the peak voltage triggers _____ and inactivation of the voltage gated __+ channels

meanwhile the voltage gated K+ channel ______, allowing K+ to ______ out

membrane rapidly _________ as voltage drops back down

___+/___+ pump will also assist in _____ process by actively pumping 3 ___+ out of the axon for every 2 ___+ into the axon

______ takes approx 0.001s or 1ms. this time frame is known as the _______ period. an impulse ______ be activated during this time

4

the peak voltage triggers closing and inactivation of the voltage gated Na+ channels

meanwhile the voltage gated K+ channel opens, allowing K+ to diffuse out

membrane rapidly repolarizes as voltage drops back down

Na+/K+ pump will also assist in repolarization process by actively pumping 3 Na+ out of the axon for every 2K+ into the axon

repolarization takes approx 0.001s or 1ms. this time frame is known as the refractory period. an impulse cannot be activated during this time

5

a very brief undershoot of the resting potential (__________) results because K+ channels close slowly

a very brief undershoot of the resting potential (hyperpolarization) results because K+ channels close slowly

6

the membrane then returns to its ______ potential

the membrane then returns to its resting potential