Halogenalkanes: Free Radical Substitution and Ozone A Level Chemistry

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Last updated 1:23 PM on 11/1/22
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19 Terms

1
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Write an overall equation for the reaction between methane and chlorine to make chloromethane and ?

Name the mechanism
CH₄ + Cl₂ → CH₃Cl + HCl

Free Radical Substitution
2
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What is a RADICAL?
A species that contains an UNPAIRED ELECTRON
3
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Name the three stages of Free Radical Substitution and state what species react and forms at each stage
Initiation:
molecule → two radicals
Propagation (P1 & P2):
molecule+radical→molecule₊radical
Termination:
radical+radical→molecule
4
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What condition is needed for initiation?
High Energy UV
5
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During Free Radical Substitution, what molecule is produced for each Hydrogen atom that is substituted for a halogen?
Hydrogen halide (ie HCl)
6
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Write equations for initiation, propagation and termination for the reaction between methane and chlorine to form chloromethane
Initiation: Cl₂→2Cl∙
Propagation 1: CH₄ + Cl∙→HCl + ∙CH₃
Propagation 2: Cl₂ + ∙CH₃ → CH₃Cl + Cl∙
Termination (possible steps include):
∙CH₃ + ∙CH₃ → CH₃CH₃
∙CH₃ + Cl∙ → CH₃Cl
Cl∙ + Cl∙ → Cl₂
7
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Write equations for initiation, propagation and termination for the reaction between chloromethane and chlorine to form dichloromethane
Initiation: Cl₂→2Cl∙
Propagation 1: CH₃Cl +Cl∙→HCl+ ∙CH₂Cl
Propagation 2: Cl₂+∙CH₂Cl→CH₂Cl₂+Cl∙
Termination (possible steps include):
∙CH₂Cl + ∙CH₂Cl → CH₂ClCH₂Cl
∙CH₂Cl + Cl∙ → CH₂Cl₂
Cl∙ + Cl∙ → Cl₂
8
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Which two steps do I add together (and cancel) to produce the overall equation?
Propagation 1 & 2
Propagation 1: CH₄ + Cl∙→HCl + ∙CH₃
Propagation 2: Cl₂ + ∙CH₃ → CH₃Cl + Cl∙
Overall : CH₄ + Cl₂→HCl + CH₃Cl
9
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State the harmful effects of high energy UV light
Skin cancer
Damage to eyes
(and possible crop damage)
10
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What is a CFC?
ChloroFluoroCarbon
11
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Why are CFCs less reactive on earth than alkanes
Because the C-F bond is very strong
12
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What happens to CFCs in the upper atmosphere when they are exposed to high energy UV light?
What is this step called?
The C-Cl bond is broken by the high energy uv light to form Cl∙ (chlorine radical/chlorine atom)
Initiation step
13
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Why does the C-Cl bond break but the C-F bond does not break in the upper atmosphere
Because the C-F bond is much stronger than the Cl bond.
There is not enough energy in the UV light to break the C-F bond.
14
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Write an initiation equation for CClF₃
CClF₃ → ∙CF₃ + ∙Cl
15
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Write the two propagation equations for the reaction between chlorine radical and ozone
P1: Cl∙ + O₃→ClO∙ + O₂
P2: ClO∙ + O₃ → Cl∙ + 2O₂
16
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What is the OVERALL equation for the breakdown of ozone by chlorine radicals
2O₃→3O₂
17
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Why is the reaction between a chlorine radical ozone considered CATALYTIC?
Because the Cl∙ (Chlorine radical) is used in one step and regenerated in another.
18
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What is the equation for the NATURAL formation and breakdown of ozone in the upper atmosphere
O∙ + O₂ ⇌O₃
19
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What are the safer alternatives to CFCs and why are they safer?
HCFCs (HydroChloroFluoroCarbons)
HFCs (HydroFluoroCarbons)
The HCFCs and HFCs contain C-H bonds which break more easily. These molecules have mostly broken down BEFORE they reach the ozone layer, so they do not form radicals