principles - chemical formulae, equations and calculations

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without all the experiments from the moles test

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19 Terms

1
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what is Mr

relative molecular mass (sum of Ar)

2
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what is Ar

the atomic mass - from periodic table - protons + neutrons

3
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what is Mr

the molecular mass - sum of Ars

4
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define mol

the unit for amount of a substance

5
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mass = ___ x ___

mass = Mr x moles

6
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percentage yield = ___ / ____ (x____%)

percentage yield = actual yield (g) / theoretical yield (g) x100%

7
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why would you get less product than theoretically (3)

  • loss of reactants in transfer

  • side reactions

  • some reactions are reversible, they reverse

    • not everything reacted under heat ()

8
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define empirical formula

the simplest whole number ratio of atoms in a compound

9
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how to find empirical formula (Mg - 2.4, O - 1.6) the table

Mg

O

mass

2.4

1.6

Ar

24

16

moles

0.1

0.1

ratio

1

(divide all by smallest number)

1

10
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what is molecular formula

the actual number of atoms of each element in a molecule of the compound

11
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general, how to find molecular formula

first find empirical formula

find Mr of empirical formula, compare that with given Mr of molecular thing

always a multiple of the empirical, what needs to be multiplied up

12
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concentration moles formula

moles = concentration (mol/dm3) x volume (dm3)

13
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gas volume moles formula

moles = gas volume (dm3) / 24

1 mole takes up 24dm3 at room tempw

14
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how to go from mol/dm3 to g/dm3 and vice versa

the logic also

  • To go from g/dm3 to mol/dm3: Divide by the molar mass in grams

  • To go from mol/dm3 to g/dm3: Multiply by the molar mass in grams

<ul><li><p>To go from g/dm<sup>3</sup> to mol/dm<sup>3</sup>: Divide by the molar mass in grams</p></li><li><p>To go from mol/dm<sup>3</sup> to g/dm<sup>3</sup>: Multiply by the molar mass in grams</p></li></ul><p></p><p></p>
15
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why do all gasses 1 mole = 24dm3

because the volume is essentially the same as the particles are so small their actual size is negligible, space in between creates the volume

16
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24 dm3 in cm3

24 000 cm3

17
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concentration formula with mass - g/dm3 conc.

18
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how to find excess reagent, general steps

chemical formula is the correct one

compare formula moles with moles used in experiment

compare the ratios - where one reactant is ā€˜used moreā€˜ in the experiment than in the formula, it is in excess

same if there is not enough of one irl reactant vs the ratio, thatā€™s the limiting reagent so the other is in excess

19
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Mg + 2Hcl ā†’ MgCl2 ā†’ H2O

0.3 mol reacts with 0.3 mol of Hcl, which is in excess

check notes

its Mg in Excess