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Bernoulli Equation
First order ODE of the form y’ + py = qya, where a =/= 0 or 1
Set v = y1-a
Find y and y’ in terms of v
Substitute v for y
Use integrating factor
Integrate
Substitute y for v
Isolate y
Theory of Existence & Uniqueness for 1st Order IVP
{ y’ + py = q
{ y’ = f(x,y)
{ y(a) = b
If there exists an interval I around x=a where p & q are continuous, then there exists (f is continuous) only one (df/dy is continuous) solution to the IVP over all of I
autonomous equation
RHS not dependent on independent variable that the variable of interest is made derivative WRT
Bifurcation diagram
xy graph where y is population at equilibrium and x is rate of population depletion
Schaefer Model
Ps = 0 & K(1-E/r)
Ym is where E = R/2
equivalent integral equation
Given y’ = f(x,y)
y(x) = int from 0 to x of f(s, y(s)) ds
Method of Successive Approximation / Picard Iteration
y0(x) = 0
y1(x) = int 0 to x of f(s, y0(s))ds
yn(x) = int 0 to x of f(s, yn-1(s))ds
Find sigma notation, prove it is successive by induction, and convert into elementary function
Principle of Superposition
Any linear combination of solutions for a linear homogeneous equation is also a solution
Theorem of Existence & Uniqueness for 2nd Order Linear IVP
{ y’’ + py’ + qy = f(x)
{ y(x0) = a
{ y(x0) = b
If p, q, and f are continuous in an interval I around x-, then only one solution exists to the IVP over all of I
equidimensional equation
equation that fits the substitution
y = xa
y’ = axa-1
y” = a(a-1)xa-2
Euler’s Identities
cos(x) = ½(eix + e-ix)
sin(x) = ½(eix - e-ix/i)
Wronskian
det of y1(x) y2(x)
. y’1(x) y’2(x)
Abel’s Theorem
Given two solutions y1 and y2 of linear homogeneous ODE in interval I,
if they are linearly independent, then
W(y1, y2)(x) ≠ 0, ∀ x ∈ I
if they are linearly dependent,
W(y1, y2)(x) = 0, ∀ x ∈ I
Solving second order homogeneous IVP
Find two linearly independent solutions
Verify with Abel’s Theorem
Apply ICs
Solve for constants
Find I, interval around x0, where p & q are continuous
constant coefficient 2nd order equation
Substitute y = rerx
repeated roots 2nd order eq
multiply first solution by x to get second solution
complex conjugate root 2nd order eq
Use eix = cos(x) + i sin(x)
Set C3 to C1 + C2 and C4 to i(C1 - C2)