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Practice flashcards for SHM concepts: defining equations, energy, phase, pendulums, damped and forced oscillations, and the link between SHM and circular motion.
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The acceleration in SHM is directly proportional to the displacement x and directed toward the fixed point, so a = -w² x
-ω^2
The restoring force in SHM is F = _ x.
-k
At the equilibrium position in SHM, the acceleration is _.
0
At the equilibrium position in SHM, the resultant force is _.
0
The total energy E in SHM is constant and equals E = _.
1/2 m ω^2 A^2
The displacement in SHM is x = _(ωt + φ).
A sin
The velocity in SHM is v = _.
ω A cos(ωt + φ)
The acceleration in SHM is a = _ x.
-ω^2
The phase constant ∅ depends on the initial condition and gives the value of x when t = _.
0
If at t = 0, x = +A, the phase ∅ equals _.
π/2
At x = ±A, the velocity v = _.
0
The potential energy in SHM is U = _.
1/2 m ω^2 x^2
The kinetic energy in SHM is K = _.
1/2 m v^2
Total energy E in SHM is E = _.
1/2 m ω^2 A^2
For SHM, F = - dU/dx implies F = _ x.
In the SHM–Uniform Circular Motion relation, the angle is θ = _ t.
ω
For a simple pendulum (small angle), ω^2 = _.
g/L
For a mass-spring system, ω^2 = _.
k/m
The period of a mass-spring system is T = _.
2π sqrt(m/k)
The horizontal spring-mass oscillator period is independent of the force of gravity, i.e., T is independent of _.
gravity
Damped oscillations cause amplitude to _ with time.
decrease
Underdamped: the system still _.
oscillates
Critical damping returns to equilibrium in the shortest time without .
oscillation
Overdamping returns to equilibrium with a very long time to return without undergoing any .
oscillation
In free oscillations with no damping, the amplitude is .
constant
In forced oscillations, the frequency of the driven oscillation equals the frequency of the .
driving force
Resonance occurs when the driving frequency equals the natural frequency, causing the amplitude to .
increase dramatically
The maximum speed in SHM is vmax = .
ω A
The maximum acceleration in SHM is amax = A.
ω^2
The angular frequency for a simple pendulum is ω = _ when considering small angles.
√(g/L)
The time-period for a simple pendulum at small angles is T = _.
2π sqrt(L/g)
For a mass–spring SHM, ω = _ and T = 2π sqrt(m/k).
√(k/m)
The period of a horizontal mass–spring oscillator is independent of the gravitational acceleration because gravity acts only in the vertical direction and does not affect the horizontal restoring force, so T is independent of _.
gravity
In the relationship between SHM and Uniform Circular Motion, θ = _ t.
ω t
In a damped oscillator with increasing damping, the resonance peak amplitude tends to and the resonant frequency shifts to a _ frequency.
decrease; lower