for the class at IWA; includes info from previous chapter to make sure everyone knows it for our test
general equations for sine and cosine graphs
f(x) = Asin(Bx-C)+D and Acos(Bx-C)+D
What does A mean in an equation?
Amplitude (how far the graph goes up, how far the graph goes down)
What does B mean in an equation?
Frequency (number of cycles in 2pi; when B=1 there is one cycle in 2pi)
What does D mean in an equation?
vertical shift
What is the phase (horizontal) shift in a sin/cos equation?
C/B
Period in a sin/cos graph
2pi/B
To graph a sin/cos graphā¦
divide the period by four, giving you the minimums, maximums, and intercepts
Range
y values
domain
x values
How do you find a period in a graph?
count length of one cycle (one up, one down)
How do you find B from a graph
set 2pi/B equal to the period and solve
If the B value in a tangent or cotangent graph is 1, the period isā¦
pi
to graph tangent or cotangent, fine the values where the function is ā. These will be ā ā ā.
undefined, vertical asymptote values
general equations for tan and cot graphs
y=tanx and y=cotx
What is the period in a tan/cot graph if B is NOT 1?
pi/B
For tangent, set Bx = ā, ā, ā to find vertical asymptotes
-pi/2, pi/2, 3pi/2
For cotangent, set Bx = ā, ā, ā to find vertical asymptotes
-pi, 0, pi
To graph a csc or sec graphā¦
use the reciprocal graph as a guide. The x intercepts will create vertical asymptotes on the reciprocal graphs
On csc and sec graphs, the x-ints from the guide graphs areā¦
vertical asymptotes
On csc and sec graphs, the relative max/mins from the guide graphs areā¦
vertexes
Range restrictions for inverse trig
sin and csc: q1 and q4
tan and cot: q1 and q4
cos and sec: q1 and q2
y=ArcSinx is the same asā¦
y=sin^-1x
each inverse trig expression has only ā ā-, which MUST be in the ā restriction.
one answer, range
for special angle value expressions, evaluate the inside inverse trig function for the ā, then find the ā ā.
angle, trig ratio
For trig values with numbers not on the unit circle, ā ā ā from the inverse trig statement, then find the ā ā.
draw the triangle, trig ratio
when simplifying a trig function in terms of x, draw a triangle, fill in the missing side with a ā ā and find the trig ratio
x expression
reciprocal identity of sinx
1/cscx
reciprocal identity of cosx
1/secx
reciprocal identity of tanx
1/cotx
reciprocal identity of cscx
1/sinx
reciprocal identity of secx
1/cosx
reciprocal identity of cotx
1/tanx
sinĀ²x + cosĀ²x= ā
1
1+tanĀ²x= ā
secĀ²x
1+cotĀ²x= ā
cscĀ²x
1-sinĀ²x and sinĀ²x-1= ā
cosĀ²x
1-cosĀ²x and cosĀ²x-1= ā
sinĀ²x
even-odd identity rules
cos and sec will be pos with a negative x input (will still be positive if +x). Other ratios will be negative with a negative x.
sin(A+B)
sinAcosB+cosAsinB
sin(A-B)
sinAcosB-cosAsinB
cos(A+B)
cosAcosB-sinAsinB
cos(A-B)
cosAcosB+sinAsinB
(note: mrs. rich said this wonāt be on the test, but itās here for memorization.)
tan(A+B)
tanA+tanB/1-tanAtanB
(note: mrs. rich said this wonāt be on the test, but itās here for memorization.)
tan(A-B)
tanA-tanB/1+tanAtanB
know what functions are positive in what quadrants
q1: all
q2: sin csc
q3: tan cot
q4: cos sec
what would you do when given an equation like sin(pi/3 + pi/4)?
write out equation and use triangles to find values. then solve.
what would you do when given an equation like sin(5pi/12)?
find numbers that add or subtract to what is in parenthesis and also simplify to /4, /3, or /6. Then solve as if you were given the numbers.
If given some ratios of A and B in certain quadrants, draw ā and then ā as normal.
triangles, solve
sin2x
2sinxcosx
cos2x
cosĀ²x-sinĀ²x
(note: mrs. rich said this wonāt be on the test, but itās here for memorization.)
tan2x
2tanx/1-tanĀ²x
In a question where you are given a trig ratio and its quadrant, you wouldā¦
draw the triangle and plug the subsequent values/ratios into what the question asks for
angles and measurements for 30/60/90 triangle
angles and measurements for 45/45/90 triangle
sin in terms of x,y
y
cos in terms of x,y
x
tan in terms of x,y
y/x
csc in terms of x,y
1/y
sec in terms of x,y
1/x
cot in terms of x,y
x/y
unit circle points and angles
tangent graph
cotangent graph
sin graph
csc graph
cos graph
sec graph
oblique triangle
triangle that does not contain a right angle
has either three acute angles or two acute angles and one obtuse angle
To use the law of sinesā¦
need two angles and the side across from one of the angles OR two sides and the angle across from one of the sides
Only ā ratios are used to solve for one unknown part of the triangle when using the law of sines.
two
ambiguous case
itās possible to have 0, 1, or 2 triangles for two sides and one angle
In the ambiguous case, you have 0 triangles whenā¦
sin > 1
In the ambiguous case, you have 1 triangle whenā¦
adding up the given angle and ang equal to one you solved for is > 180
In the ambiguous case, you have 2 triangles whenā¦
adding up given angle and ang equal to one you solved for is < 180
Area for oblique triangle
Ā½ bc SinA, Ā½ ab SinC, Ā½ ac SinB
law of cos is needed to solve for the missing part for:
SAS, SSS
once missing part of oblique triangle is found with law of cos, ā ā ā can be used
law of sines
cos of pi/6
square root of 3/2
sin of pi/6
1/2
tan of pi/6
square root of 3/3
sin of pi/4
square root of 2/2
cos of pi/4
square root of 2/2
tan of pi/4
1
cos of pi/3
1/2
sin of pi/3
square root of 3/2
tan of pi/3
square root of 3