T3M2: Prok Transcriptional Regulation

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22 Terms

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glucose vs lactose metabolism

  • E. coli bacteria prefer glucose as an energy source.

  • When both glucose and lactose are available, E. coli will use up all the glucose first before switching to lactose.

  • This switch is a highly regulated process — the bacteria only turn on the genes needed for lactose metabolism after glucose runs out.

  • These genes are controlled at the transcriptional level, meaning that E. coli can turn on or off specific genes depending on nutrient availability.

  • The bacteria detect two key environmental cues:

    1. Glucose levels (whether it’s high or low)

    2. Presence of lactose

  • Β-galactosidase and lactose permease proteins are non-detectable when E. Coli is using glucose as its main source of energy

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proteins involved in lactose metabolism

When E. coli switches from glucose to lactose:

  • It starts producing two important proteins:

    1. β-galactosidase – an enzyme that breaks lactose (a disaccharide) into glucose + galactose.

    2. Lactose permease – a membrane transport protein that helps bring lactose into the bacterial cell.

  • These proteins are not made while glucose is still available — glucose represses their production.

  • Once glucose is gone, and lactose is present, lactose induces their production.

  • This ensures E. coli only makes the lactose-digesting enzymes when necessary, saving energy.

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operons 

⇒ related prokaryotic genes with similar functions can be clustered into operons → allows for the control of transcription of the whole gene cluster in one unit — controlled by a single ON/OFF switch

⤷ in euk… each gene has its own promoter and enhancers 

> operon model = discovered by jacob and monod

composed of:

  • promoter (where RNA polymerase binds to start transcription)

  • operator (a DNA sequence that acts like an on/off switch)

    • found near the start of the operon, can be regulated to allow/inhibit transcription

    • if an operator is NOT bound to inhibitor.. then RNA poly can attach to promoter and transcribe genes in operon

  • cluster of structural genes (that code for proteins with related functions)

> allows for polycistronic mRNA — where a single mRNA can make multiple proteins bc it contains several start/stop codons

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lac operon

operon for specifically managing lactose (for transcriptional regulation)

controls production of:

  • β-galactosidase (lacZ)

  • Lactose permease transport proteins (lacY)

> involves regulatory sequences of transcription — w promoter that binds to RNA poly complex and operator (lacO) (binding site for repressor protein that is expressed by lacI coding seq.)

> ⇒ RNA polymerase can bind to and activate the transcription of lacY and lacZ genes… but lacI controls the expression

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promoter

where RNA poly binds

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operator

where repressor protein can bind to block transcription

» negative regulatory site bound by lac repressors proteins (overlap w the promoter)

» when lac repressor is bound, RNA poly cannot bind to promoter and start transcirption

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lacI gene 

makes the repressor protein that can bind to the operator 

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repressor 

when the repressor binds to the operator, RNA polymerase cannot transcribe lacZ and lacY — this is negative regulation

  • coded by lacI gene

  • negative transcription regulation: the ability of a repressor protein to halt transcription 

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lacY gene 

gene that codes for lactose permease transport proteins 

⤷ will embed itself in the cell membrane and allow for the import of lactose into the bacterial cell

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lacZ gene

code for β galactosidase 

⤷ helps cleave lactose into glucose and galactose

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negative regulation of the lac operon

when glucose present:

  • lacI gene is always expressed at low levels — encoding for repressor protein

    • repressor protein binds onto the operator… and twists its into a loop (bc of its tetrametric structure) prevening the RNA polymerase to transcript (cannot move downstream — “blocked“)

  • When the repressor is bound, RNA polymerase is blocked and cannot bind to teh promoter and no transcription occurs

  • This means no β-galactosidase or lactose permease are produced.

  • This happens when glucose is available, because the cell doesn’t need lactose-metabolizing enzymes.

when lactose is present, no glucose:

  • lactose becomes allolactose (isoform of lactose that acts as inducer)

  • allolactose passes thru the lactose permease channel, and binds onto the operator

  • binding of allolactose onto operator = causes teh repressor to change shape (conformational change) so the repressor can no longer bind anymore

    • no repressor on the operator = allows RNA poly to bind ==> allow transcription of beta. galactosidase and permease etc. 

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positive regulation of lac operon

positive regulation of lac operon occurs when there is no glucose => produces β galactosidase and lactose permease

HIGH glucose 

  • ↑ glucose = adenyl cyclase is active = ↑ production of cAMP = cAMP binds onto CRP binding site = ↑ affinity for RNA poly to bind onto promoter = ↑ transcription rates 

> when cAMP binds onto CRP binding site = will form CRP-cAMP complex as allosteric activator 

LOW glucose 

  • ↓ glucose = inhibits adenyl cyclase = ↓ cAMP = ↓ transcription 

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CRP binding site 

positive regulatory site, where CRP binds to promote transcription by helping

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CRP/CAP

glucose sensor, transcription factor that binds to DNA in the presence of cAMP to enhance RNA polymerase binding and initate transcription 

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Glucose present, lactose absent ~ 

  • NO transcription of the lac operon (bc lac repressor remains bound to the operator and prevents transcription by RNA polymerase) 

  • cAMP levels are LOW bc glucose levels are HIGH – ∴ CRP is inactive and cannot bind DNA

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Glucose present, lactose present ~ 

  • Low level transcription of the lac operon 

  • The lac repressor is released from the operator because the inducer (allolactose) is present 

  • cAMP levels = low bc glucose present 

  • ∴ CRP remains inactive bc cannot bind to DNA

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Glucose absent, lactose absent ~ 

  • No transcription of the lac operon 

  • cAMP levels are HIGH bc glucose levels are LOW → ∴ CRP is active and will be bound to DNA 

  • Lac repressor will be bound to the operator (absence of allolactose) → ∴ no RNA poly binding and preventing transcription

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Glucose absent, lactose present ~

  • Strong transcription of the lac operon 

  • The lac repressor is released from the operator because the inducer (allolactose) is present 

  • cAMP levels are high (bc glucose is absent) → ∴ CRP is active and binds to DNA 

  • CRP helps RNA poly to bind to the promoter ⇒ ∴ high levels of transcription

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combining negative and positive regulation

  • Negative regulation: a repressor binds onto DNA operator to block transcription.

    • Can be turned off by an inducer (like lactose).

  • Positive regulation: an activator (like CRP–cAMP) binds DNA to stimulate transcription.

    • Without the activator, transcription won’t happen efficiently.

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inducer protein

able to bind to repressor proteins and prevents it to bind onto DNA — reverse its function

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transcription activator protein

positive regulation of transcription ⇒ a transcription activator protein binding to an activator binding site on the DNA

  • the binding site = upstream/downstream or OVERLAP w promoter 

  • Once activator binds the DNA → RNA poly binds to promoter and start transcription 

    • If activator is not present/not able to bind to the activator binding site… then transcription cannot occur 

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<p>when are levels of lac operon mRNA the highest, lowest, and no lac operon </p>

when are levels of lac operon mRNA the highest, lowest, and no lac operon

  • ⇒ the highest level of lac operon mRNA would be @ point C ⇒ bc bacteria are actively utilizing lactose as a nutrient source ⇒ ∴ transcribing the lac operon gene products to be able to produce lactose permease + β galactosidase 

  • ⇒ low lac operon @ point B → this is the transitional time point where glucose has been used up and lac operon transcription is initiating 

  • ⇒ no lac operon @ point A → bc bacteria is still actively utilizing glucose as a nutrient source (repressed until there is no glucose)

<ul><li><p><span style="background-color: transparent;"><span>⇒ the </span><strong><span>highest level of lac operon</span></strong><span> mRNA would be @ </span><strong><span>point C</span></strong><span> ⇒ bc bacteria are actively utilizing lactose as a nutrient source ⇒ ∴ transcribing the lac operon gene products to be able to produce lactose permease + β galactosidase&nbsp;</span></span></p></li><li><p><span style="background-color: transparent;"><span>⇒ low lac operon @ point B → this is the transitional time point where glucose has been used up and lac operon transcription is initiating&nbsp;</span></span></p></li><li><p><span style="background-color: transparent;"><span>⇒ no lac operon @ point A → bc bacteria is still actively utilizing glucose as a nutrient source (repressed until there is no glucose)</span></span></p></li></ul><p></p>